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It is claimed that beef can be stored for up to two years at \(-23^{\circ} \mathrm{C}\) but no more than one year at \(-12^{\circ} \mathrm{C}\). Is this claim reasonable? Explain.

Short Answer

Expert verified
Answer: Based on the Arrhenius equation and the relationship between temperature and reaction rates, it is reasonable to assume that the claim is plausible. Although we cannot determine the exact quantitative relationship without more information, the lower temperature of -23°C can potentially lead to a decreased reaction rate, allowing the beef to be stored longer than one year.

Step by step solution

01

Understanding the Arrhenius equation

The Arrhenius equation is used to demonstrate the relationship between the rate of a reaction and temperature. It is given as: k = Ae^(-Ea / RT) where: - k is the reaction rate constant - A is the pre-exponential factor (frequency factor) - Ea is the activation energy of the reaction - R is the gas constant (8.314 J/(mol·K)) - T is the temperature (in Kelvin) Note that since we're only comparing the relative rates, we don't need to explicitly calculate the pre-exponential factor.
02

Convert given temperatures to Kelvin

First, we need to convert the temperatures given in Celsius to Kelvin. The relationship between Celsius and Kelvin temperatures is: T(K) = T(°C) + 273.15 - For -23°C: T1 = -23 + 273.15 = 250.15 K - For -12°C: T2 = -12 + 273.15 = 261.15 K
03

Determine the ratio of reaction rates at both temperatures

Using the Arrhenius equation, we can establish a relationship between the reaction rates at both temperatures. Let k1 and k2 be the reaction rates at temperatures T1 and T2 respectively. The ratio of reaction rates (k2/k1) can be found by dividing the Arrhenius equations for both temperatures: (k2/k1) = e^(-(Ea / RT2) + (Ea / RT1)) Now, we don't know the values of Ea and R, but we can analyze the relationship between the temperatures and reaction rates.
04

Analyze the claim based on the ratio of reaction rates

Given that spoilage is a reaction, the claim is reasonable if the ratio of reaction rates (k2/k1) is equal to or greater than 2, which means that the beef spoils at least twice as fast at -12°C compared to -23°C. We cannot determine an exact value of the ratio without exact values for Ea and R, but we know that the exponential term inside the Arrhenius equation will decrease as the temperature decreases. Therefore, it is feasible that the ratio can be equal to or greater than 2, making the claim reasonable. In conclusion, although we cannot confirm the exact quantitative relationship between the reaction rates, it is reasonable to assume that the claim of beef lasting up to two years at -23°C compared to one year at -12°C is plausible based on the Arrhenius equation and the effect of temperature on reaction rates.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Rate Constant
When it comes to understanding how fast a chemical reaction can proceed, the reaction rate constant, denoted by the symbol k, is an essential quantity. The reaction rate constant is a measure of the speed at which reactants are converted into products under specific conditions, including temperature and pressure.

The value of k is not just a number to plug into equations; it encapsulates vital information about the reaction. For example, in a refrigeration scenario, the rate at which meat spoils is a reaction that we can describe using a rate constant. A higher reaction rate constant at a given temperature means that the spoilage reactions are happening faster. This constant is crucial for food industries where packaging, storage, and shelf life are tied closely to the speed of these reactions.

In the exercise, understanding k helps explain why beef may spoil slower at lower temperatures, indicating that k is lower when the beef is stored at -23°C compared to that at -12°C. It reflects the general rule that most chemical reactions, including spoilage, slow down as temperatures decrease.
Activation Energy
The term activation energy, symbolized by the variable Ea, refers to the minimum amount of energy required to initiate a chemical reaction. Imagine it as a barrier that reactants must overcome to transform into products. A higher activation energy means that fewer molecules have the necessary energy to react at a given temperature, which slows down the reaction rate.

In the context of food preservation, activation energy is the 'hill' that spoilage-causing bacteria or reactions need to climb to make the beef go bad. Lower temperatures make this 'hill' even harder to surmount, as fewer bacteria or molecules have the required energy, resulting in longer preservation times. This concept explains why there's a difference in shelf life for beef stored at the temperatures provided in the exercise—beef has a longer shelf life at -23°C because the activation energy barrier is more difficult to overcome at this lower temperature, leading to slower spoilage rates.
Temperature Conversion
The exercise provided us with temperatures in degrees Celsius, but in order to apply them in the Arrhenius equation, we must perform a temperature conversion to Kelvin. This is necessary because Kelvin is the standard unit of temperature in the scientific community, particularly in thermodynamics and kinetics calculations.

To convert from Celsius to Kelvin, we add 273.15 to the Celsius temperature. This conversion is based on the fact that 0 K, or absolute zero, is the point where molecules theoretically stop moving and is equivalent to -273.15°C. So, for the exercise, -23°C becomes 250.15 K and -12°C becomes 261.15 K. These Kelvin temperatures can then be used to calculate how the reaction rate constant changes with temperature, which is central to the question posed about the storage duration of beef at different temperatures. This calculation underscores the importance of precision in scientific measurements and translations between temperature scales.

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Most popular questions from this chapter

To warm up some milk for a baby, a mother pours milk into a thin-walled cylindrical container whose diameter is \(6 \mathrm{~cm}\). The height of the milk in the container is \(7 \mathrm{~cm}\). She then places the container into a large pan filled with hot water at \(70^{\circ} \mathrm{C}\). The milk is stirred constantly, so that its temperature is uniform at all times. If the heat transfer coefficient between the water and the container is \(120 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine how long it will take for the milk to warm up from \(3^{\circ} \mathrm{C}\) to \(38^{\circ} \mathrm{C}\). Assume the entire surface area of the cylindrical container (including the top and bottom) is in thermal contact with the hot water. Take the properties of the milk to be the same as those of water. Can the milk in this case be treated as a lumped system? Why? Answer: \(4.50 \mathrm{~min}\)

Oxy-fuel combustion power plants use pulverized coal particles as fuel to burn in a pure oxygen environment to generate electricity. Before entering the furnace, pulverized spherical coal particles with an average diameter of \(300 \mu \mathrm{m}\), are being transported at \(2 \mathrm{~m} / \mathrm{s}\) through a \(3-\mathrm{m}\) long heated tube while suspended in hot air. The air temperature in the tube is \(900^{\circ} \mathrm{C}\) and the average convection heat transfer coefficient is \(250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the temperature of the coal particles at the exit of the heated tube, if the initial temperature of the particles is \(20^{\circ} \mathrm{C}\).

Consider a spherical shell satellite with outer diameter of \(4 \mathrm{~m}\) and shell thickness of \(10 \mathrm{~mm}\) is reentering the atmosphere. The shell satellite is made of stainless steel with properties of \(\rho=8238 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=468 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(k=13.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). During the reentry, the effective atmosphere temperature surrounding the satellite is \(1250^{\circ} \mathrm{C}\) with convection heat transfer coefficient of \(130 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the initial temperature of the shell is \(10^{\circ} \mathrm{C}\), determine the shell temperature after 5 minutes of reentry. Assume heat transfer occurs only on the satellite shell.

What is the effect of cooking on the microorganisms in foods? Why is it important that the internal temperature of a roast in an oven be raised above \(70^{\circ} \mathrm{C}\) ?

A large cast iron container \((k=52 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\alpha=\) \(1.70 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\) ) with 5 -cm- thick walls is initially at a uniform temperature of \(0^{\circ} \mathrm{C}\) and is filled with ice at \(0^{\circ} \mathrm{C}\). Now the outer surfaces of the container are exposed to hot water at \(60^{\circ} \mathrm{C}\) with a very large heat transfer coefficient. Determine how long it will be before the ice inside the container starts melting. Also, taking the heat transfer coefficient on the inner surface of the container to be \(250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the rate of heat transfer to the ice through a \(1.2-\mathrm{m}\)-wide and \(2-\mathrm{m}\)-high section of the wall when steady operating conditions are reached. Assume the ice starts melting when its inner surface temperature rises to \(0.1^{\circ} \mathrm{C}\).

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