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Why are the convection and the radiation resistances at a surface in parallel instead of being in series?

Short Answer

Expert verified
Answer: Convection and radiation resistances at a surface are in parallel instead of being in series because both mechanisms occur simultaneously and independently from each other, allowing for separate pathways for heat flow. The total rate of heat transfer at the surface is the summation of the heat transferred through convection and radiation.

Step by step solution

01

Define Convection Resistance

Convection resistance represents the resistance to heat transfer by convection between a solid surface and the surrounding fluid. In other words, it describes the difficulty for heat to transfer from the surface to the fluid (or vice versa) due to the movement of fluid particles.
02

Define Radiation Resistance

Radiation resistance represents the resistance to heat transfer by radiation between a hot surface and its cooler surroundings. It accounts for the heat transfer through thermal radiation, which is the emission of electromagnetic waves (usually infrared) from a heated object.
03

Analyze Heat Transfer Mechanisms

In a real-world scenario, both convection and radiation heat transfer mechanisms occur at the same time at a surface. The heat transfer by convection is usually conducted from a solid surface to the surrounding fluid (or vice versa) and depends on the temperature difference between the surface and the fluid. On the other hand, the heat transfer by radiation is between the surface and the surroundings (typically air) and relies on the temperature difference between the surface and the surroundings.
04

Explain Parallel Resistances

When two resistances are in parallel, they allow for the heat to transfer across them simultaneously. In the case of convection and radiation resistances, both mechanisms occur at the same time and have separate pathways for heat flow. The total rate of heat transfer at the surface (Q) is the summation of the heat transferred through convection (Q_conv) and radiation (Q_rad): \[Q = Q_{conv} + Q_{rad}\]
05

Explain Why Resistances are Not in Series

For resistances to be in series, the heat transfer must pass through both resistances in sequence, one after the other. However, in the case of convection and radiation, the heat transfer does not go through a specific order. Both mechanisms transfer heat simultaneously and independently from each other. In conclusion, the convection and radiation resistances at a surface are in parallel instead of being in series because both mechanisms occur simultaneously and independently from each other, allowing for separate pathways for heat flow.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Convection Resistance
Convection resistance refers to the difficulty that heat experiences as it tries to move between a solid surface and the fluid around it. Whether it's air, water, or any other fluid, this process involves heat being transferred as the fluid particles move. The formula for convection resistance is usually expressed as \[ R_{conv} = \frac{1}{h A} \]where \(h\) is the convection heat transfer coefficient, and \(A\) is the area of the surface. This equation reflects how the efficiency of heat transfer increases with a higher convection coefficient and a larger area. Convection can occur naturally, due to buoyancy effects, or be forced, by fans or winds. Understanding this resistance helps in designing systems that efficiently use airflow, like heating or cooling systems, to manage temperature.
  • Higher convection coefficient = less resistance.
  • Larger surface area = less resistance.
Exploring Radiation Resistance
Radiation resistance is quite different from convection resistance as it involves heat transfer via electromagnetic waves. This kind of transfer doesn't require a medium (like air or water) and can even occur in a vacuum. When dealing with radiation resistance, we usually focus on thermal radiation, which is mostly in the infrared spectrum. The resistance to radiation is defined by the equation: \[ R_{rad} = \frac{1}{\epsilon \sigma A (T_s^4 - T_{sur}^4)} \]where \(\epsilon\) is the emissivity of the surface, \(\sigma\) is the Stefan-Boltzmann constant, \(A\) is the area, \(T_s\) is the surface temperature and \(T_{sur}\) is the surrounding temperature. The emissivity value serves as an indicator of how effectively a surface can emit energy as radiation. Radiation resistance demonstrates how much a surface's ability to radiate heat is impacted by its emissivity and the temperature differences. This is crucial in applications where high temperatures and significant energy emissions are involved.
  • Lower emissivity = higher resistance.
  • Greater temperature difference = less resistance.
The Concept of Parallel Resistances
When convection and radiation resistances are described as parallel, it means they allow for heat to be transferred at the same time through separate avenues. In this arrangement, both heat transfer mechanisms function independently and do not affect each other directly, allowing concurrent heat flow. The total heat transfer rate \(Q\) is therefore the sum of the heat transferred by convection \(Q_{conv}\) and by radiation \(Q_{rad}\):\[ Q = Q_{conv} + Q_{rad} \]This formula underscores the benefit of having these mechanisms in parallel; they can each contribute to the heat transfer without one being a bottleneck to the other. It's similar to having two open gates allowing cars to flow through simultaneously, instead of in a single line.
  • Parallel means simultaneous transfer.
  • Independent paths lead to efficient flow.
Understanding Heat Transfer Mechanisms
Heat transfer mechanisms can be fascinating because they describe how energy moves from one place to another, like from the sun to the Earth's surface or from a radiator to the air in a room. In practical applications, convection and radiation often occur together, making it necessary to grasp how both work and interact. Convection involves heat moving via fluid motion, often visible in heating systems or weather patterns, creating a "conveyor belt" of energy. Radiation allows heat transfer through electromagnetic waves, crucial for instances like warmth from a campfire or sunlight. Both mechanisms have their unique characteristics and operate simultaneously when heat is transferred from a surface to its surroundings. By understanding these basic principles, engineers and scientists can design more efficient systems that use energy wisely, ensure comfort, or protect equipment from overheating. This concept also shows why knowing each mechanism individually is important as it enables better control in practical scenarios.
  • Convection: heat flow through moving fluids.
  • Radiation: heat flow through electromagnetic waves.

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Most popular questions from this chapter

A 4-mm-diameter and 10-cm-long aluminum fin \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is attached to a surface. If the heat transfer coefficient is \(12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the percent error in the rate of heat transfer from the fin when the infinitely long fin assumption is used instead of the adiabatic fin tip assumption.

Two plate fins of constant rectangular cross section are identical, except that the thickness of one of them is twice the thickness of the other. For which fin is the \((a)\) fin effectiveness and \((b)\) fin efficiency higher? Explain.

We are interested in steady state heat transfer analysis from a human forearm subjected to certain environmental conditions. For this purpose consider the forearm to be made up of muscle with thickness \(r_{m}\) with a skin/fat layer of thickness \(t_{s f}\) over it, as shown in the Figure P3-138. For simplicity approximate the forearm as a one-dimensional cylinder and ignore the presence of bones. The metabolic heat generation rate \(\left(\dot{e}_{m}\right)\) and perfusion rate \((\dot{p})\) are both constant throughout the muscle. The blood density and specific heat are \(\rho_{b}\) and \(c_{b}\), respectively. The core body temperate \(\left(T_{c}\right)\) and the arterial blood temperature \(\left(T_{a}\right)\) are both assumed to be the same and constant. The muscle and the skin/fat layer thermal conductivities are \(k_{m}\) and \(k_{s f}\), respectively. The skin has an emissivity of \(\varepsilon\) and the forearm is subjected to an air environment with a temperature of \(T_{\infty}\), a convection heat transfer coefficient of \(h_{\text {conv }}\), and a radiation heat transfer coefficient of \(h_{\mathrm{rad}}\). Assuming blood properties and thermal conductivities are all constant, \((a)\) write the bioheat transfer equation in radial coordinates. The boundary conditions for the forearm are specified constant temperature at the outer surface of the muscle \(\left(T_{i}\right)\) and temperature symmetry at the centerline of the forearm. \((b)\) Solve the differential equation and apply the boundary conditions to develop an expression for the temperature distribution in the forearm. (c) Determine the temperature at the outer surface of the muscle \(\left(T_{i}\right)\) and the maximum temperature in the forearm \(\left(T_{\max }\right)\) for the following conditions: $$ \begin{aligned} &r_{m}=0.05 \mathrm{~m}, t_{s f}=0.003 \mathrm{~m}, \dot{e}_{m}=700 \mathrm{~W} / \mathrm{m}^{3}, \dot{p}=0.00051 / \mathrm{s} \\ &T_{a}=37^{\circ} \mathrm{C}, T_{\text {co }}=T_{\text {surr }}=24^{\circ} \mathrm{C}, \varepsilon=0.95 \\ &\rho_{b}=1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{b}=3600 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k_{m}=0.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K} \\ &k_{s f}=0.3 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, h_{\text {conv }}=2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}, h_{\mathrm{rad}}=5.9 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K} \end{aligned} $$

An 8-m-internal-diameter spherical tank made of \(1.5\)-cm-thick stainless steel \((k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is used to store iced water at \(0^{\circ} \mathrm{C}\). The tank is located in a room whose temperature is \(25^{\circ} \mathrm{C}\). The walls of the room are also at \(25^{\circ} \mathrm{C}\). The outer surface of the tank is black (emissivity \(\varepsilon=1\) ), and heat transfer between the outer surface of the tank and the surroundings is by natural convection and radiation. The convection heat transfer coefficients at the inner and the outer surfaces of the tank are \(80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. Determine \((a)\) the rate of heat transfer to the iced water in the tank and \((b)\) the amount of ice at \(0^{\circ} \mathrm{C}\) that melts during a 24 -h period. The heat of fusion of water at atmospheric pressure is \(h_{i f}=333.7 \mathrm{~kJ} / \mathrm{kg}\).

One wall of a refrigerated warehouse is \(10.0\)-m-high and \(5.0\)-m-wide. The wall is made of three layers: \(1.0\)-cm-thick aluminum \((k=200 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}), 8.0\)-cm-thick fibreglass \((k=\) \(0.038 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\), and \(3.0-\mathrm{cm}\) thick gypsum board \((k=\) \(0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The warehouse inside and outside temperatures are \(-10^{\circ} \mathrm{C}\) and \(20^{\circ} \mathrm{C}\), respectively, and the average value of both inside and outside heat transfer coefficients is \(40 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Calculate the rate of heat transfer across the warehouse wall in steady operation. (b) Suppose that 400 metal bolts \((k=43 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\), each \(2.0 \mathrm{~cm}\) in diameter and \(12.0 \mathrm{~cm}\) long, are used to fasten (i.e., hold together) the three wall layers. Calculate the rate of heat transfer for the "bolted" wall. (c) What is the percent change in the rate of heat transfer across the wall due to metal bolts?

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