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A plate consists of two thin metal layers pressed against each other. Do we need to be concerned about the thermal contact resistance at the interface in a heat transfer analysis or can we just ignore it?

Short Answer

Expert verified
Answer: Whether to consider thermal contact resistance in the heat transfer analysis depends on the specific conditions of the metal layers and their interface. If the metals have high thermal conductivity, the surfaces are clean and smooth, and the contact pressure is high, the thermal contact resistance may be negligible and can be ignored. However, if any of these factors is not satisfied, it is advisable to include the effects of thermal contact resistance in the analysis to ensure accurate results.

Step by step solution

01

Understanding Thermal Contact Resistance

Thermal contact resistance refers to the resistance to heat transfer at the interface between two surfaces in contact. It is usually caused by factors such as surface roughness, surface deformation, and the presence of air or other contaminants between the surfaces. A heat transfer analysis should consider the effects of thermal contact resistance if it significantly impacts the overall heat transfer process.
02

Evaluating the significance of thermal contact resistance in the given scenario

In the case of a plate consisting of two thin metal layers pressed against each other, several factors can affect the significance of thermal contact resistance: 1. The nature of the metals: If the metals have high thermal conductivity, then the impact of thermal contact resistance may be minimal, and it could potentially be ignored in the analysis. On the other hand, if the metals have low thermal conductivity, the contact resistance could play a more significant role. 2. Surface roughness and contact pressure: The degree of surface roughness and the contact pressure between the metal layers can also affect the thermal contact resistance. High contact pressure and low surface roughness may result in good thermal contact, thereby reducing the contact resistance and making it less significant in the analysis. 3. The presence of contaminants: If the interface between the two metal layers is clean and free of contaminants, the thermal contact resistance will be lower and may be considered negligible in the heat transfer analysis. However, if contaminants are present, the contact resistance may increase and must be accounted for in the analysis.
03

Determining whether to consider thermal contact resistance

Based on the above discussion, the need to consider thermal contact resistance in the heat transfer analysis depends on the specific conditions of the metal layers and their interface. If the metals have high thermal conductivity, the surfaces are clean and smooth, and the contact pressure is high, the thermal contact resistance may be negligible and can be ignored. However, if any of these factors is not satisfied, it is advisable to include the effects of thermal contact resistance in the analysis to ensure accurate results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer Analysis
When conducting a heat transfer analysis, we examine how heat moves from one place to another. This process, which can occur through conduction, convection, and radiation, is fundamental in engineering and environmental sciences.

In our example, assessing whether the thermal contact resistance at the interface of two metal layers should be taken into account is crucial. This resistance can act as a bottleneck for heat flow, just like traffic congestion on a highway can impede vehicle movement. If thermal contact resistance is significant compared to other resistances in the system, it could lead to substantial errors if ignored.

Imagine wearing layers of clothing on a cold day; each layer of fabric and the air between them offer resistance to your body heat escaping to the environment. Similarly, for the metal plate, proper heat transfer analysis requires understanding all layers and interfaces to predict the temperature distribution and heat flow accurately.
Thermal Conductivity
Explaining thermal conductivity is essential for understanding heat transfer in materials. It's a measure of a material's ability to conduct heat, and it is represented by the symbol \( k \). High thermal conductivity indicates that the material will transfer heat quickly, much like a metal spoon that quickly becomes hot when placed in a pot of boiling water. Conversely, low thermal conductivity materials, such as plastic or wood, do not transfer heat as readily, akin to a wooden spoon that stays cool in the same pot.

In the debate about whether to consider thermal contact resistance, the thermal conductivity of the metal layers becomes a deciding factor. High conductivity materials might minimize the impact of contact resistance, allowing heat to 'jump' the interface more readily. However, if a material has low thermal conductivity, the interface resistance cannot be overlooked as it could become a key factor in heat flow obstruction.
Surface Roughness
The surface roughness of materials refers to the microscopic peaks and valleys found on all surfaces. These irregularities can have a profound effect on the contact area and thus the contact resistance when two surfaces are pressed together.

The role of surface roughness is akin to the difference in friction between a smooth, polished floor and a rough, gravel path. If the surfaces are smooth, they will have a larger real area of contact, promoting better heat transfer between them. Conversely, rough surfaces result in smaller points of actual contact, potentially trapping air pockets that act as insulation and obstruct heat flow.

In the case of our two metal layers, reducing surface roughness, or smoothing the surfaces, can improve thermal contact and allow the assumption of negligible thermal contact resistance. However, if the surfaces are rough and have not been treated to optimize contact, including the effects of thermal contact resistance in the analysis would be necessary to ensure the accuracy of the heat transfer model.

By focusing on these three core concepts, students can better grasp the critical aspects that dictate when thermal contact resistance is too important to ignore in a heat transfer analysis.

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Most popular questions from this chapter

An 8-m-internal-diameter spherical tank made of \(1.5\)-cm-thick stainless steel \((k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is used to store iced water at \(0^{\circ} \mathrm{C}\). The tank is located in a room whose temperature is \(25^{\circ} \mathrm{C}\). The walls of the room are also at \(25^{\circ} \mathrm{C}\). The outer surface of the tank is black (emissivity \(\varepsilon=1\) ), and heat transfer between the outer surface of the tank and the surroundings is by natural convection and radiation. The convection heat transfer coefficients at the inner and the outer surfaces of the tank are \(80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. Determine \((a)\) the rate of heat transfer to the iced water in the tank and \((b)\) the amount of ice at \(0^{\circ} \mathrm{C}\) that melts during a 24 -h period. The heat of fusion of water at atmospheric pressure is \(h_{i f}=333.7 \mathrm{~kJ} / \mathrm{kg}\).

A 3-cm-long, 2-mm \(\times 2-\mathrm{mm}\) rectangular crosssection aluminum fin \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is attached to a surface. If the fin efficiency is 65 percent, the effectiveness of this single fin is (a) 39 (b) 30 (c) 24 (d) \(18 \quad(e) 7\)

Consider a house with a flat roof whose outer dimensions are \(12 \mathrm{~m} \times 12 \mathrm{~m}\). The outer walls of the house are \(6 \mathrm{~m}\) high. The walls and the roof of the house are made of \(20-\mathrm{cm}-\) thick concrete \((k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The temperatures of the inner and outer surfaces of the house are \(15^{\circ} \mathrm{C}\) and \(3^{\circ} \mathrm{C}\), respectively. Accounting for the effects of the edges of adjoining surfaces, determine the rate of heat loss from the house through its walls and the roof. What is the error involved in ignoring the effects of the edges and corners and treating the roof as a \(12 \mathrm{~m} \times 12 \mathrm{~m}\) surface and the walls as \(6 \mathrm{~m} \times 12 \mathrm{~m}\) surfaces for simplicity?

Cold conditioned air at \(12^{\circ} \mathrm{C}\) is flowing inside a \(1.5\)-cm- thick square aluminum \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) duct of inner cross section \(22 \mathrm{~cm} \times 22 \mathrm{~cm}\) at a mass flow rate of \(0.8 \mathrm{~kg} / \mathrm{s}\). The duct is exposed to air at \(33^{\circ} \mathrm{C}\) with a combined convection-radiation heat transfer coefficient of \(13 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The convection heat transfer coefficient at the inner surface is \(75 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the air temperature in the duct should not increase by more than \(1^{\circ} \mathrm{C}\) determine the maximum length of the duct.

Using cylindrical samples of the same material, devise an experiment to determine the thermal contact resistance. Cylindrical samples are available at any length, and the thermal conductivity of the material is known.

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