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Consider a medium in which the heat conduction equation is given in its simplest form as $$ \frac{\partial^{2} T}{\partial x^{2}}=\frac{1}{\alpha} \frac{\partial T}{\partial t} $$ (a) Is heat transfer steady or transient? (b) Is heat transfer one-, two-, or three-dimensional? (c) Is there heat generation in the medium? (d) Is the thermal conductivity of the medium constant or variable?

Short Answer

Expert verified
Answer: Transient Question: What is the dimensionality of the heat transfer process in the given equation? Answer: One-dimensional Question: Is there heat generation in the medium according to the given heat conduction equation? Answer: No Question: Based on the provided heat conduction equation, can we determine if the thermal conductivity of the medium is constant or variable? Answer: No, it is not possible to determine from the equation.

Step by step solution

01

(a) Steady or Transient Heat Transfer

To determine if the heat transfer is steady or transient, we need to check if there is any time dependence in the given equation. The presence of the term \(\frac{\partial T}{\partial t}\) indicates that the temperature changes with respect to time, which means the heat transfer is transient.
02

(b) One-, Two-, or Three-Dimensional Heat Transfer

To determine the dimensionality of the heat transfer, we need to analyze the given equation for spatial derivatives. The equation only contains a second-order derivative with respect to the x-axis: $$\frac{\partial^{2} T}{\partial x^{2}}$$ Since there are no terms containing the y-axis or z-axis, we can conclude that heat transfer is one-dimensional.
03

(c) Presence of Heat Generation

To determine if there is heat generation in the medium, we need to check the given equation for any source term representing heat generation. The given equation does not have any source term, so there is no heat generation in the medium.
04

(d) Constant or Variable Thermal Conductivity

Finally, to determine if the thermal conductivity is constant or variable, we need to check if there is any thermal conductivity term in the given equation. The term \(\alpha\) represents the thermal diffusivity and is given by: $$\alpha = \frac{k}{\rho c_p}$$ where: - \(k\) is the thermal conductivity - \(\rho\) is the density of the medium - \(c_p\) is the specific heat capacity at constant pressure Since the equation only includes the thermal diffusivity and not the thermal conductivity explicitly, it is not possible to determine from this equation whether the thermal conductivity is constant or variable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transient Heat Transfer
When exploring the concept of transient heat transfer, it's crucial to recognize the dynamic nature of the phenomenon. Unlike steady-state heat transfer, where temperatures remain constant over time, transient heat transfer involves time-dependent changes. In the heat conduction equation provided in the exercise, the partial derivative with respect to time, \( \frac{\partial T}{\partial t} \), unmistakably indicates that the temperature, and thus the heat within the medium, varies as time progresses. This time-dependency is the essence of transient heat transfer and must be considered when analyzing thermal systems that experience fluctuations such as heating up or cooling down over time.

One-Dimensional Heat Transfer
One-dimensional heat transfer implies that the temperature varies along one spatial dimension only, with no significant variation in the other directions. The heat conduction equation \( \frac{\partial^{2} T}{\partial x^{2}} = \frac{1}{\alpha} \frac{\partial T}{\partial t} \) from the exercise exemplifies one-dimensional heat transfer, as the temperature gradient is solely with respect to the x-axis. This simplification is useful for problems where heat transfer perpendicular to the x-axis is negligible, such as in long, thin rods or insulated walls, where lateral heat flow does not contribute substantially to the thermal behavior of the system.

Heat Generation
In some thermal systems, heat can be generated internally due to chemical reactions, electrical resistance, or other processes. To evaluate the presence of heat generation within a medium, one should look for a source term in the heat conduction equation. In the provided exercise, the absence of such a term implies that no internal heat generation occurs in the medium. Thus, any thermal changes are due to heat transfer with the surroundings, not from within. It's essential for engineers and scientists to understand whether heat generation is a factor to appropriately design and manage thermal systems.

Thermal Conductivity
Thermal conductivity, denoted by the symbol \( k \) in thermal physics, is a property that quantifies a material's ability to conduct heat. It appears in the calculation of thermal diffusivity, \( \alpha \)—which is present in the heat conduction equation—as \( \alpha = \frac{k}{\rho c_p} \) where \( \rho \) represents density and \( c_p \) is the specific heat capacity at constant pressure. Although thermal conductivity is not explicitly specified in the given equation, understanding its role is key in analyzing heat transfer problems. A constant thermal conductivity simplifies analysis, whereas variable conductivity requires a more nuanced approach, considering changes in material properties with temperature or phase transitions.

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Most popular questions from this chapter

Consider a 20-cm-thick large concrete plane wall \((k=0.77 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) subjected to convection on both sides with \(T_{\infty 1}=27^{\circ} \mathrm{C}\) and \(h_{1}=5 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) on the inside, and \(T_{\infty 2}=8^{\circ} \mathrm{C}\) and \(h_{2}=12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) on the outside. Assuming constant thermal conductivity with no heat generation and negligible radiation, (a) express the differential equation and the boundary conditions for steady one-dimensional heat conduction through the wall, (b) obtain a relation for the variation of temperature in the wall by solving the differential equation, and \((c)\) evaluate the temperatures at the inner and outer surfaces of the wall.

A pipe is used for transporting boiling water in which the inner surface is at \(100^{\circ} \mathrm{C}\). The pipe is situated in surroundings where the ambient temperature is \(10^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is \(70 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The wall thickness of the pipe is \(3 \mathrm{~mm}\) and its inner diameter is \(30 \mathrm{~mm}\). The pipe wall has a variable thermal conductivity given as \(k(T)=k_{0}(1+\beta T)\), where \(k_{0}=1.23 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \beta=0.002 \mathrm{~K}^{-1}\), and \(T\) is in \(\mathrm{K}\). For safety reasons and to prevent thermal burn to workers, the outer surface temperature of the pipe should be kept below \(50^{\circ} \mathrm{C}\). Determine whether the outer surface temperature of the pipe is at a safe temperature so as to avoid thermal burn.

The temperatures at the inner and outer surfaces of a 15 -cm-thick plane wall are measured to be \(40^{\circ} \mathrm{C}\) and \(28^{\circ} \mathrm{C}\), respectively. The expression for steady, one-dimensional variation of temperature in the wall is (a) \(T(x)=28 x+40\) (b) \(T(x)=-40 x+28\) (c) \(T(x)=40 x+28\) (d) \(T(x)=-80 x+40\) (e) \(T(x)=40 x-80\)

Heat is generated uniformly in a 4-cm-diameter, 12 -cm-long solid bar \((k=2.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The temperatures at the center and at the surface of the bar are measured to be \(210^{\circ} \mathrm{C}\) and \(45^{\circ} \mathrm{C}\), respectively. The rate of heat generation within the bar is (a) \(597 \mathrm{~W}\) (b) \(760 \mathrm{~W}\) (c) \(826 \mathrm{~W}\) (d) \(928 \mathrm{~W}\) (e) \(1020 \mathrm{~W}\)

Consider a large plane wall of thickness \(L\) and constant thermal conductivity \(k\). The left side of the wall \((x=0)\) is maintained at a constant temperature \(T_{0}\), while the right surface at \(x=L\) is insulated. Heat is generated in the wall at the rate of \(\dot{e}_{\text {gen }}=a x^{2} \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{3}\). Assuming steady one-dimensional heat transfer, \((a)\) express the differential equation and the boundary conditions for heat conduction through the wall, \((b)\) by solving the differential equation, obtain a relation for the variation of temperature in the wall \(T(x)\) in terms of \(x, L, k, a\), and \(T_{0}\), and (c) what is the highest temperature \(\left({ }^{\circ} \mathrm{C}\right)\) in the plane wall when: \(L=1 \mathrm{ft}, k=5 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{\circ}{ }^{\circ} \mathrm{F}, a=1200 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{5}\), and \(T_{0}=700^{\circ} \mathrm{F}\).

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