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Starting with an energy balance on a rectangular volume element, derive the one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation.

Short Answer

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Based on the given step-by-step solution, provide a short answer explaining the one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation. The one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation is derived from an energy balance considering the net heat rate into a volume element and the rate of change of energy storage within the element. It is given by: 蟻 * c_p * 鈭俆 / 鈭倀 = k * 鈭偮睺 / 鈭倄虏 where 蟻 is the density, c_p is the specific heat at constant pressure, k is the thermal conductivity, T is the temperature, x is the position, and t is the time.

Step by step solution

01

Define a volume element

Consider a rectangular volume element in the plane wall of thickness 螖x, height h, and width w in the x-direction. Define T as the temperature of the material at position x and time t.
02

Perform an energy balance

Analyze the energy change within the volume element between its two faces at x and x + 螖x due to heat conduction. Incoming heat flux at x is q_x and outgoing heat flux at x + 螖x is q_(x+螖x). The net heat rate into the volume element, 螖q_net, is the difference between the rates of incoming and outgoing heat fluxes: 螖q_net = q_x - q_(x+螖x)
03

Apply Fourier's law of heat conduction

Apply Fourier's law of heat conduction to express the heat flux in terms of temperature gradient and thermal conductivity (k). q = -k * 鈭俆 / 鈭倄 Calculate the incoming and outgoing heat fluxes at x and x + 螖x: q_x = -k * 鈭俆 / 鈭倄 |_(x) q_(x+螖x) = -k * 鈭俆 / 鈭倄 |_(x+螖x) Plug the heat fluxes into the net heat rate equation: 螖q_net = -k * 鈭俆 / 鈭倄 |_(x) - (-k * 鈭俆 / 鈭倄 |_(x+螖x)) = -k * ( 鈭俆 / 鈭倄 |_(x+螖x) - 鈭俆 / 鈭倄 |_(x))
04

Relate net heat rate to energy storage

The net heat rate into the volume element equals the rate of change of energy storage within the volume element. The energy storage per unit volume in the element is given by 蟻*c_p * 鈭俆 / 鈭倀, where 蟻 is the density and c_p is the specific heat at constant pressure of the wall material. The rate of change of energy storage in the volume element = (蟻 * c_p * 鈭俆 / 鈭倀) * h * w * 螖x
05

Combine energy balance with energy storage

Equate the rate of change of energy storage to the net heat rate into the volume element: (蟻 * c_p * 鈭俆 / 鈭倀) * h * w * 螖x = -k * ( 鈭俆 / 鈭倄 |_(x+螖x) - 鈭俆 / 鈭倄 |_(x)) * h * w Divide both sides by h * w * 螖x: 蟻 * c_p * 鈭俆 / 鈭倀 = -k * ( 鈭俆 / 鈭倄 |_(x+螖x) - 鈭俆 / 鈭倄 |_(x)) / 螖x
06

Take the limit as 螖x approaches 0

Take the limit of the above equation as 螖x approaches 0 to obtain the one-dimensional transient heat conduction equation: 蟻 * c_p * 鈭俆 / 鈭倀 = k * 鈭偮睺 / 鈭倄虏 This is the one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Transient Heat Conduction
Transient heat conduction refers to the process of heat transfer in a material where the temperature changes with time. Unlike steady-state conduction, in transient conduction, the temperature at any given point inside a material is not constant over time.
This phenomenon occurs because the material reacts to a sudden change in thermal conditions, such as heating or cooling. Imagine a metal rod being heated at one end. The heat will move along the length of the rod and change its temperature distribution over time.
The main goal in studying transient heat conduction is to understand how the temperature evolves with time. This evolution is often described using differential equations that take into account various material properties like density and specific heat capacity.
Fourier's Law of Heat Conduction
Fourier's law is a fundamental principle describing heat conduction. It states that the rate of heat transfer through a material is proportional to the negative of the temperature gradient across the material. In simpler terms, heat flows from hot to cold regions, and the greater the temperature difference, the faster the flow.

  • Mathematically, Fourier鈥檚 law is expressed as: \[ q = -k \frac{\partial T}{\partial x} \] where:
    • \( q \) is the heat flux, or rate of heat transfer per unit area.
    • \( k \) is the thermal conductivity of the material.
    • \( T \) is the temperature.
    • \( x \) is the direction of the heat flux.
High thermal conductivity materials like metals allow heat to travel quickly, whereas materials like wood have low thermal conductivity and are good insulators.
Energy Balance in Heat Conduction
The concept of energy balance is crucial in solving heat conduction problems. It involves calculating the net heat entering and leaving a volume element to determine how much heat is stored.
To conduct an energy balance, you assess the following:
  • The incoming heat flux at one face of the volume element.
  • The outgoing heat flux at the opposite face.
  • The rate of change in energy stored within the element.
Using the principle of conservation of energy, any difference in incoming and outgoing heat must equal the rate of energy stored.
It's like filling a bathtub: the rate at which water enters minus the rate of drainage gives the rate at which water level rises. Similarly, in heat conduction, a net positive heat influx implies an increase in stored thermal energy.
Thermal Conductivity Explained
Thermal conductivity is a property of a material that indicates its ability to conduct heat. High thermal conductivity materials, like copper, rapidly spread heat through their molecules. In contrast, insulating materials like fiberglass have low thermal conductivity and resist heat flow.
  • The unit of thermal conductivity in the SI system is watts per meter-kelvin (W/m路K).
  • Thermal conductivity can depend on temperature, but in many problems, it is considered constant for simplicity.
  • Understanding thermal conductivity helps in choosing materials for thermal insulation or conduction based on their application needs.
For example, when designing a building, materials with varying thermal conductivity can be chosen strategically to manage heat transfer, thus improving energy efficiency.

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Most popular questions from this chapter

Consider a long solid cylinder of radius \(r_{o}=4 \mathrm{~cm}\) and thermal conductivity \(k=25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). Heat is generated in the cylinder uniformly at a rate of \(\dot{e}_{\text {gen }}=35 \mathrm{~W} / \mathrm{cm}^{3}\). The side surface of the cylinder is maintained at a constant temperature of \(T_{s}=80^{\circ} \mathrm{C}\). The variation of temperature in the cylinder is given by $$ T(r)=\frac{\dot{e}_{\text {gen }} r_{o}^{2}}{k}\left[1-\left[1-\left(\frac{r}{r_{o}}\right)^{2}\right]+T_{s}\right. $$ Based on this relation, determine \((a)\) if the heat conduction is steady or transient, \((b)\) if it is one-, two-, or three-dimensional, and \((c)\) the value of heat flux on the side surface of the cylinder at \(r=r_{o^{*}}\)

A plane wall of thickness \(L\) is subjected to convection at both surfaces with ambient temperature \(T_{\infty 1}\) and heat transfer coefficient \(h_{1}\) at inner surface, and corresponding \(T_{\infty 2}\) and \(h_{2}\) values at the outer surface. Taking the positive direction of \(x\) to be from the inner surface to the outer surface, the correct expression for the convection boundary condition is (a) \(\left.k \frac{d T(0)}{d x}=h_{1}\left[T(0)-T_{\mathrm{o} 1}\right)\right]\) (b) \(\left.k \frac{d T(L)}{d x}=h_{2}\left[T(L)-T_{\infty 2}\right)\right]\) (c) \(\left.-k \frac{d T(0)}{d x}=h_{1}\left[T_{\infty 1}-T_{\infty 2}\right)\right]\) (d) \(\left.-k \frac{d T(L)}{d x}=h_{2}\left[T_{\infty 1}-T_{\infty 22}\right)\right]\) (e) None of them

A \(1200-W\) iron is left on the iron board with its base exposed to ambient air at \(26^{\circ} \mathrm{C}\). The base plate of the iron has a thickness of \(L=0.5 \mathrm{~cm}\), base area of \(A=150 \mathrm{~cm}^{2}\), and thermal conductivity of \(k=18 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The inner surface of the base plate is subjected to uniform heat flux generated by the resistance heaters inside. The outer surface of the base plate whose emissivity is \(\varepsilon=0.7\), loses heat by convection to ambient air with an average heat transfer coefficient of \(h=\) \(30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) as well as by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}=295 \mathrm{~K}\). Disregarding any heat loss through the upper part of the iron, \((a)\) express the differential equation and the boundary conditions for steady one-dimensional heat conduction through the plate, \((b)\) obtain a relation for the temperature of the outer surface of the plate by solving the differential equation, and (c) evaluate the outer surface temperature.

Exhaust gases from a manufacturing plant are being discharged through a 10 - \(\mathrm{m}\) tall exhaust stack with outer diameter of \(1 \mathrm{~m}\), wall thickness of \(10 \mathrm{~cm}\), and thermal conductivity of \(40 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The exhaust gases are discharged at a rate of \(1.2 \mathrm{~kg} / \mathrm{s}\), while temperature drop between inlet and exit of the exhaust stack is \(30^{\circ} \mathrm{C}\), and the constant pressure specific heat of the exhaust gasses is \(1600 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). On a particular day, the outer surface of the exhaust stack experiences radiation with the surrounding at \(27^{\circ} \mathrm{C}\), and convection with the ambient air at \(27^{\circ} \mathrm{C}\) also, with an average convection heat transfer coefficient of \(8 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Solar radiation is incident on the exhaust stack outer surface at a rate of \(150 \mathrm{~W} / \mathrm{m}^{2}\), and both the emissivity and solar absorptivity of the outer surface are 0.9. Assuming steady one-dimensional heat transfer, (a) obtain the variation of temperature in the exhaust stack wall and (b) determine the inner surface temperature of the exhaust stack.

Consider a small hot metal object of mass \(m\) and specific heat \(c\) that is initially at a temperature of \(T_{i}\). Now the object is allowed to cool in an environment at \(T_{\infty}\) by convection with a heat transfer coefficient of \(h\). The temperature of the metal object is observed to vary uniformly with time during cooling. Writing an energy balance on the entire metal object, derive the differential equation that describes the variation of temperature of the ball with time, \(T(t)\). Assume constant thermal conductivity and no heat generation in the object. Do not solve.

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