/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 123 Can a differential equation invo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Can a differential equation involve more than one independent variable? Can it involve more than one dependent variable? Give examples.

Short Answer

Expert verified
Answer: Yes, a differential equation can involve more than one dependent variable, as shown in the example of a system of 2 ordinary differential equations: \( \frac{dy_1}{dt} = y_1^2 + y_2^2 \) and \( \frac{dy_2}{dt} = y_1 + y_2 \), where \( y_1 = y_1(t) \) and \( y_2 = y_2(t) \) are both dependent variables and t is the independent variable. Moreover, a differential equation can also involve more than one independent variable. This type of equation is known as a partial differential equation (PDE). An example is the 2D heat equation, which is a PDE with two independent variables x and y: \( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \), where u = u(x, y) is the dependent variable and x, y are independent variables.

Step by step solution

01

Dependent variables in differential equations

A differential equation can indeed involve more than one dependent variable. For example, consider a system of 2 ordinary differential equations: \( \frac{dy_1}{dt} = y_1^2 + y_2^2 \) and \( \frac{dy_2}{dt} = y_1 + y_2 \), where \( y_1 = y_1(t) \) and \( y_2 = y_2(t) \) are both dependent variables and t is the independent variable.
02

Independent variables in differential equations

A partial differential equation (PDE) is an equation involving multiple independent variables and their partial derivatives. For example, a 2D heat equation is a PDE having two independent variables x and y: \( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \), where u = u(x, y) is the dependent variable and x, y are independent variables.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ordinary Differential Equations
Ordinary Differential Equations (ODEs) involve functions of a single independent variable and their derivatives. A key characteristic of ODEs is that there is only one independent variable, typically referred to as time (t) though it can be any variable.
To understand ODEs better, think about the simple example of Newton's Law of Cooling, which can be modeled by the equation:
  • \(\frac{dT}{dt} = -k(T - T_{env})\)
where \(T\) is the temperature at time \(t\), and \(T_{env}\) is the environmental temperature, while \(k\) is a positive constant.
This ODE shows how temperature changes as a function of time. Here, \(T\) is the dependent variable, and \(t\) is the independent variable.
Partial Differential Equations
Partial Differential Equations (PDEs) differ significantly from ordinary differential equations because they involve multiple independent variables. These equations are crucial in fields such as physics and engineering.
A classic example is the 2D Laplace Equation:
  • \(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0\)
Here, PDEs describe how functions change concerning various factors, like space and time. In the given equation, \(u\) is the dependent variable which might represent physical phenomena like electric potential or temperature distribution across a surface, and \(x\) and \(y\) are its spatial independent variables.
Such complexity requires understanding of multivariable calculus, as these equations capture changes across multiple dimensions.
Dependent and Independent Variables
In differential equations, understanding the roles of dependent and independent variables is essential. The independent variable is often what you control or measure over time/space, while the dependent variable depends on the effect or outcome you are studying.
For example, in the system of ordinary differential equations (ODEs):
  • \(\frac{dy_1}{dt} = y_1^2 + y_2^2\)
  • \(\frac{dy_2}{dt} = y_1 + y_2\)
Here, \(t\) is the independent variable. It typically represents time, while \(y_1\) and \(y_2\) are dependent on \(t\) as they describe changes or outcomes with respect to time.
In a partial differential equation (PDE) like the 2D heat equation:
  • \(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0\)
The independent variables are \(x\) and \(y\), representing spatial dimensions, and \(u\) remains the dependent variable. This illustrates that dependent variables can change with respect to more than one independent variable in PDEs.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A large plane wall, with a thickness \(L\) and a thermal conductivity \(k\), has its left surface \((x=0)\) exposed to a uniform heat flux \(\dot{q}_{0}\). On the right surface \((x=L)\), convection and radiation heat transfer occur in a surrounding temperature of \(T_{\infty}\). The emissivity and the convection heat transfer coefficient on the right surface are \(\bar{\varepsilon}\) and \(h\), respectively. Express the houndary conditions and the differential equation of this heat conduction problem during steady operation.

Consider a cylindrical shell of length \(L\), inner radius \(r_{1}\), and outer radius \(r_{2}\) whose thermal conductivity varies in a specified temperature range as \(k(T)=k_{0}\left(1+\beta T^{2}\right)\) where \(k_{0}\) and \(\beta\) are two specified constants. The inner surface of the shell is maintained at a constant temperature of \(T_{1}\) while the outer surface is maintained at \(T_{2}\). Assuming steady one-dimensional heat transfer, obtain a relation for the heat transfer rate through the shell.

Consider a spherical reactor of \(5-\mathrm{cm}\) diameter operating at steady condition has a temperature variation that can be expressed in the form of \(T(r)=a-b r^{2}\), where \(a=850^{\circ} \mathrm{C}\) and \(b=5 \times 10^{5} \mathrm{~K} / \mathrm{m}^{2}\). The reactor is made of material with \(c=\) \(200 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}, k=40 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=9000 \mathrm{~kg} / \mathrm{m}^{3}\). If the heat generation of reactor is suddenly set to \(9 \mathrm{MW} / \mathrm{m}^{3}\), determine the time rate of temperature change in the reactor. Is the heat generation of reactor suddenly increased or decreased to \(9 \mathrm{MW} / \mathrm{m}^{3}\) from its steady operating condition?

Consider a long rectangular bar of length \(a\) in the \(x-\) direction and width \(b\) in the \(y\)-direction that is initially at a uniform temperature of \(T_{i}\). The surfaces of the bar at \(x=0\) and \(y=0\) are insulated, while heat is lost from the other two surfaces by convection to the surrounding medium at temperature \(T_{\infty}\) with a heat transfer coefficient of \(h\). Assuming constant thermal conductivity and transient two-dimensional heat transfer with no heat generation, express the mathematical formulation (the differential equation and the boundary and initial conditions) of this heat conduction problem. Do not solve.

Consider steady one-dimensional heat conduction in a plane wall in which the thermal conductivity varies linearly. The error involved in heat transfer calculations by assuming constant thermal conductivity at the average temperature is \((a)\) none, \((b)\) small, or \((c)\) significant.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.