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Express the mass flow rate of water vapor through a wall of thickness \(L\) in terms of the partial pressure of water vapor on both sides of the wall and the permeability of the wall to the water vapor.

Short Answer

Expert verified
Answer: The formula to express the mass flow rate of water vapor through a wall of thickness L is m = -(k * A * ΔP) / L, where m is the mass flow rate, k is the permeability of the wall, A is the area of the wall, and ΔP is the difference in partial pressure between the two sides of the wall.

Step by step solution

01

Write down the Fick's law of diffusion formula

The formula for Fick's law of diffusion is: J = -k * (ΔP / L) Where: J is the diffusion flux k is the permeability of the wall ΔP is the difference in partial pressure between the two sides of the wall L is the thickness of the wall
02

Calculate the mass flow rate

To find the mass flow rate of water vapor (m), we need to multiply the diffusion flux (J) by the area of the wall (A). This gives us: m = J * A
03

Substitute Fick's law formula into the mass flow rate formula

Now let's substitute the Fick's law formula (from Step 1) into the mass flow rate formula (from Step 2): m = (-k * (ΔP / L)) * A
04

Rearrange the formula to express the mass flow rate in terms of the partial pressure and permeability

We can now rearrange the formula to better express the mass flow rate (m) in terms of the partial pressure difference (ΔP) and permeability (k): m = -(k * A * ΔP) / L This formula represents the mass flow rate of water vapor through a wall of thickness L, in terms of the partial pressure of water vapor on both sides of the wall and the permeability of the wall to the water vapor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fick's law of diffusion
Fick's law of diffusion is a fundamental principle used to describe the transport process of molecules across a space. It's named after the German physicist Adolf Fick who first introduced it. At its core, the law states that the diffusion flux, which is the flow of particles per unit area per unit time, is proportional to the negative gradient of the concentration. This means particles move from high concentration to low concentration. In mathematical terms for a plane wall, the law is expressed as:\[ J = -k \left( \frac{\Delta P}{L} \right) \]
  • Here, \( J \) represents diffusion flux.
  • \( k \) is the permeability of the material, indicating how easy it is for molecules to pass through.
  • \( \Delta P \) stands for the difference in partial pressure across the membrane.
  • \( L \) is the thickness of the barrier or wall.
The negative sign reflects that diffusion occurs in the direction of decreasing concentration. This law provides a simple yet powerful way to predict how substances like gases or solutes move in a medium.
Permeability
Permeability is a crucial concept when dealing with membrane transport and diffusion processes. It quantifies a material's ability to allow substances, such as water vapor, to pass through it. Different materials possess different permeability values based on their structure and composition.
Think of permeability as a measure of the 'openness' of the membrane. It's given the symbol \( k \) in Fick's law of diffusion, and its units can vary depending on the context but often include time and distance measurements like \( \text{cm}^2/\text{s} \).
  • Materials with high permeability, such as certain fabrics or membranes, allow substances to pass through easily.
  • Low permeability materials, like plastic or metal, restrict flow.
Understanding permeability is key for engineers and scientists who design systems where controlled diffusion is essential, such as in packaging, clothing, or even biological membranes.
Pressure Difference
Pressure difference, denoted as \( \Delta P \), is integral in assessing the movement of molecules through a membrane according to Fick's law. In essence, it's the driving force of diffusion, dictating how fast and efficiently molecules like water vapor pass through a barrier.
When we talk about pressure difference in diffusion problems:
  • It's the difference in partial pressure of a substance on two sides of a membrane. For instance, in our example, this would be the partial pressure of water vapor inside vs. outside a house wall.
  • The larger the pressure difference, the stronger the driving force, leading to a higher mass flow rate.
  • Conversely, if pressure difference is low, the movement of molecules is slower, resulting in a reduced flow rate.
This concept is widely applied in situations such as climate control in buildings, where ensuring the optimal mass transfer rate through walls or windows can significantly impact energy efficiency and indoor comfort.

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Most popular questions from this chapter

The solubility of hydrogen gas in steel in terms of its mass fraction is given as \(w_{\mathrm{H}_{2}}=2.09 \times 10^{-4} \exp (-3950 / T) P_{\mathrm{H}_{2}}^{0.5}\) where \(P_{\mathrm{H}_{2}}\) is the partial pressure of hydrogen in bars and \(T\) is the temperature in \(\mathrm{K}\). If natural gas is transported in a 1-cm-thick, 3-m-internal-diameter steel pipe at \(500 \mathrm{kPa}\) pressure and the mole fraction of hydrogen in the natural gas is 8 percent, determine the highest rate of hydrogen loss through a 100 -m-long section of the pipe at steady conditions at a temperature of \(293 \mathrm{~K}\) if the pipe is exposed to air. Take the diffusivity of hydrogen in steel to be \(2.9 \times 10^{-13} \mathrm{~m}^{2} / \mathrm{s}\).

The roof of a house is \(15 \mathrm{~m} \times 8 \mathrm{~m}\) and is made of a 20 -cm-thick concrete layer. The interior of the house is maintained at \(25^{\circ} \mathrm{C}\) and 50 percent relative humidity and the local atmospheric pressure is \(100 \mathrm{kPa}\). Determine the amount of water vapor that will migrate through the roof in \(24 \mathrm{~h}\) if the average outside conditions during that period are \(3^{\circ} \mathrm{C}\) and 30 percent relative humidity. The permeability of concrete to water vapor is \(24.7 \times 10^{-12} \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m} \cdot \mathrm{Pa}\).

Consider one-dimensional mass transfer in a moving medium that consists of species \(A\) and \(B\) with \(\rho=\rho_{A}+\rho_{B}=\) constant. Mark these statements as being True or False. (a) The rates of mass diffusion of species \(A\) and \(B\) are equal in magnitude and opposite in direction. (b) \(D_{A B}=D_{B A}\). (c) During equimolar counterdiffusion through a tube, equal numbers of moles of \(A\) and \(B\) move in opposite directions, and thus a velocity measurement device placed in the tube will read zero. (d) The lid of a tank containing propane gas (which is heavier than air) is left open. If the surrounding air and the propane in the tank are at the same temperature and pressure, no propane will escape the tank and no air will enter.

What is Stefan flow? Write the expression for Stefan's law and indicate what each variable represents.

A tank with a 2-cm-thick shell contains hydrogen gas at the atmospheric conditions of \(25^{\circ} \mathrm{C}\) and \(90 \mathrm{kPa}\). The charging valve of the tank has an internal diameter of \(3 \mathrm{~cm}\) and extends \(8 \mathrm{~cm}\) above the tank. If the lid of the tank is left open so that hydrogen and air can undergo equimolar counterdiffusion through the 10 -cm- long passageway, determine the mass flow rate of hydrogen lost to the atmosphere through the valve at the initial stages of the process.

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