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How does the mass diffusivity of a gas mixture change with \((a)\) temperature and \((b)\) pressure?

Short Answer

Expert verified
Answer: As the temperature increases, the mass diffusivity of a gas mixture increases, which means gas molecules will diffuse faster at higher temperatures. On the other hand, as the pressure increases, the mass diffusivity of a gas mixture decreases, due to increased number of collisions between gas molecules.

Step by step solution

01

Understand mass diffusivity

Mass diffusivity (D) is a measure of how fast one gas diffuses into another gas. It is dependent on temperature (T), pressure (P), and the properties of the gases involved, such as their molecular weights and sizes. We will consider a binary gas mixture, which consists of two gases, A and B, diffusing into each other.
02

Formula for mass diffusivity

The mass diffusivity of a binary gas mixture can be calculated using the Chapman-Enskog theory, which gives the following formula: D = \frac{3}{16} \frac{(k_B T)^{3/2}}{(\pi \mu)^{1/2} \sigma^2 \Omega_D} where, - D is mass diffusivity - k_B is Boltzmann's constant - T is the temperature (in Kelvin) - \mu is the reduced mass of the gas pair, given by \frac{m_A m_B}{m_A+m_B} (m_A and m_B are the molecular masses of gases A and B) - \sigma is the collision diameter (a measure of the size of the gas molecules) - \Omega_D is a dimensionless quantity dependent on the gas properties and temperature, which accounts for the collision interactions between the two gases.
03

Effect of temperature on mass diffusivity

To study the effect of temperature on mass diffusivity, we need to look at how D changes with T, keeping pressure and other parameters constant. From the formula above, we can see that D is directly proportional to T^{3/2}. Therefore, as the temperature increases, the mass diffusivity also increases, which implies that gas molecules will diffuse faster at higher temperatures.
04

Effect of pressure on mass diffusivity

Pressure does not appear explicitly in the formula for mass diffusivity, so we need to analyze its effect indirectly. The collision diameter, \sigma, which is independent of pressure, can be considered constant. However, pressure affects the concentration (n/V) of the gas mixture, where n is the number of moles of the gas and V is the volume. As per the ideal gas equation, PV = nRT \Rightarrow \frac{n}{V}= \frac{P}{RT} As the pressure increases, the concentration increases which means that the number of collisions between gas molecules will also increase. An increased number of collisions will reduce the average distance traveled by the molecules between successive collisions, leading to a decrease in mass diffusivity. In summary, (a) As the temperature increases, the mass diffusivity of a gas mixture increases. (b) As the pressure increases, the mass diffusivity of a gas mixture decreases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binary Gas Mixture
A binary gas mixture consists of two different types of gas molecules, usually referred to as Gas A and Gas B. In such a mixture, the gases intermingle and diffuse into each other, a process driven by the random movement of molecules. This diffusion allows the gases to spread throughout the available space, gradually creating a uniform composition. The rate at which this diffusion occurs can be quantified using mass diffusivity, a crucial parameter in understanding gas behavior. The diffusion process in a binary gas mixture is influenced by several factors, including the molecular weights and sizes of the gases involved. Lighter and smaller molecules usually diffuse faster compared to heavier and larger ones. This property is central to applications such as gas separation, environmental monitoring, and chemical engineering.
Chapman-Enskog Theory
The Chapman-Enskog theory is a fundamental framework for analyzing gas diffusion, providing insights into how different factors affect the mass diffusivity of gases. Developed by David Enskog and Sydney Chapman in the early 20th century, this theory offers a mathematical approach to model the distribution of molecular velocities in gases, underpinned by statistical mechanics. According to this theory, mass diffusivity (D) for a binary gas mixture is given by:\[ D = \frac{3}{16} \frac{(k_B T)^{3/2}}{(\pi \mu)^{1/2} \sigma^2 \Omega_D} \]Here, various parameters like temperature (T), Boltzmann’s constant (k_B), molecular properties, and collision interactions (\Omega_D) are taken into account to predict how diffusion changes. The Chapman-Enskog formulation is widely used to predict diffusion behaviors in scientific research and practical applications in industries like manufacturing and refining.
Temperature Effect on Diffusion
The effect of temperature on the diffusion of gases is significant and largely straightforward. As temperature increases, the energy and speed of gaseous molecules also increase, enhancing their ability to mix and move through each other. This is reflected mathematically in the Chapman-Enskog theory formula, where mass diffusivity ( D ) is proportional to T^{3/2} . Therefore, as temperature rises, diffusion speeds up, leading to faster mixing and spreading of the gases within a binary mixture. This characteristic is particularly important in processes where temperature control is essential, such as gas reactions and chemical synthesis. In practical applications, understanding this temperature dependence helps optimize processes like combustion in engines or efficiency in chemical reactors, ensuring favorable conditions for desired reactions.
Pressure Effect on Diffusion
Pressure plays a less direct role in gas diffusion compared to temperature. While it does not appear explicitly in the Chapman-Enskog equation for mass diffusivity, pressure affects the concentration and spacing of gas molecules. According to the ideal gas law, pressure is directly proportional to the concentration of gas molecules, given by \( \frac{n}{V} = \frac{P}{RT} \).When pressure increases, the density of the gas mixture also increases, resulting in more frequent collisions among gas molecules. Although this might seem like it would enhance diffusion, the reverse is true. More frequent collisions reduce the average distance molecules travel before hitting another molecule, thus decreasing overall diffusivity.Understanding pressure's impact on diffusion is critical for processes where maintaining low mass diffusivity is necessary, such as ensuring the containment of gases in pressurized vessels or preventing rapid spreading in gas leaks.

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Most popular questions from this chapter

The diffusion coefficient of carbon in steel is given as $$ D_{A B}=2.67 \times 10^{-5} \exp (-17,400 / T) \quad\left(\mathrm{m}^{2} / \mathrm{s}\right) $$ where \(T\) is in \(\mathrm{K}\). Determine the diffusion coefficient from \(300 \mathrm{~K}\) to \(1500 \mathrm{~K}\) in \(100 \mathrm{~K}\) increments and plot the results.

Consider a thin layer of liquid water on a concrete surface. The surrounding air is dry with a convection heat transfer coefficient of \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The liquid water has an emissivity of \(0.95\), and the air and surrounding temperature is \(30^{\circ} \mathrm{C}\). If the layer of liquid water has a uniform temperature of \(20^{\circ} \mathrm{C}\), determine the conduction heat flux through the concrete.

An 8-cm-internal-diameter, 30-cm-high pitcher halffilled with water is left in a dry room at \(15^{\circ} \mathrm{C}\) and \(87 \mathrm{kPa}\) with its top open. If the water is maintained at \(15^{\circ} \mathrm{C}\) at all times also, determine how long it will take for the water to evaporate completely.

The diffusion of water vapor through plaster boards and its condensation in the wall insulation in cold weather are of concern since they reduce the effectiveness of insulation. Consider a house that is maintained at \(20^{\circ} \mathrm{C}\) and 60 percent relative humidity at a location where the atmospheric pressure is \(97 \mathrm{kPa}\). The inside of the walls is finished with \(9.5\)-mm-thick gypsum wallboard. Taking the vapor pressure at the outer side of the wallboard to be zero, determine the maximum amount of water vapor that will diffuse through a \(3-\mathrm{m} \times 8-\mathrm{m}\) section of a wall during a 24-h period. The permeance of the \(9.5\)-mm-thick gypsum wallboard to water vapor is \(2.86 \times 10^{-9} \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m}^{2} \cdot \mathrm{Pa}\).

Hydrogen can cause fire hazards, and hydrogen gas leaking into surrounding air can lead to spontaneous ignition with extremely hot flames. Even at very low leakage rate, hydrogen can sustain combustion causing extended fire damages. Hydrogen gas is lighter than air, so if a leakage occurs it accumulates under roofs and forms explosive hazards. To prevent such hazards, buildings containing source of hydrogen must have adequate ventilation system and hydrogen sensors. Consider a metal spherical vessel, with an inner diameter of \(5 \mathrm{~m}\) and a thickness of \(3 \mathrm{~mm}\), containing hydrogen gas at \(2000 \mathrm{kPa}\). The vessel is situated in a room with atmospheric air at \(1 \mathrm{~atm}\). The ventilation system for the room is capable of keeping the air fresh, provided that the rate of hydrogen leakage is below \(5 \mu \mathrm{g} / \mathrm{s}\). If the diffusion coefficient and solubility of hydrogen \(\mathrm{gas}\) in the metal vessel are \(1.5 \times 10^{-12} \mathrm{~m}^{2} / \mathrm{s}\) and \(0.005 \mathrm{kmol} / \mathrm{m}^{3}\).bar, respectively, determine whether or not the vessel is safely containing the hydrogen gas.

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