Chapter 13: Problem 34
Consider two black coaxial parallel circular disks of equal diameter \(D\) that are spaced apart by a distance \(L\). The top and bottom disks have uniform temperatures of \(500^{\circ} \mathrm{C}\) and \(520^{\circ} \mathrm{C}\), respectively. Determine the radiation heat transfer coefficient \(h_{\text {rad }}\) between the disks if they are spaced apart by \(L=D\).
Short Answer
Step by step solution
Convert temperatures to Kelvin
Calculate the view factor
Calculate the net radiative heat flux
Calculate the radiation heat transfer coefficient
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stefan-Boltzmann Law
- \[E = \sigma T^4\]where \(E\) is the emissive power, \sigma is the Stefan-Boltzmann constant, approximately \(5.67 \times 10^{-8} \, \,\text{W/m}^2\text{K}^4\), and \(T\) is the absolute temperature in Kelvin.
View Factors
- \[F_{1 \to 2} = \frac{1}{2} \left(1 - \frac{1}{\sqrt{1 + \frac{4L^2}{D^2}}} \right)\]
Coaxial Disks
Heat Transfer Coefficient
- \[h_{\text{rad}} = \frac{-q_{1 \to 2}}{T_2 - T_1}\]