/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 What is a graybody? How does it ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 12: Problem 65

What is a graybody? How does it differ from a blackbody? What is a diffuse gray surface?

Short Answer

Expert verified
Answer: The main difference between a blackbody and a graybody is that a graybody emits and absorbs radiation less efficiently compared to a blackbody due to its lower emissivity value. A blackbody has an emissivity of 1, while a graybody's emissivity lies between 0 and 1. A diffuse gray surface is a specific type of graybody that reflects and emits radiation uniformly in all directions, following Lambert's cosine law. The primary characteristics of a diffuse gray surface are constant emissivity for all directions and wavelengths, governed by Lambert's cosine law, and even emission and reflection of radiation independently of the angle of incidence.

Step by step solution

01

Blackbody Definition

A blackbody is an ideal hypothetical object that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. In addition, a blackbody emits radiation based on its temperature following Planck's Law of Blackbody Radiation. A perfect blackbody has an emissivity of 1, which means it emits and absorbs radiation at the maximum possible rate for any given temperature.
02

Graybody Definition

A graybody is a more realistic object that does not absorb or emit radiation as efficiently as a blackbody. The emissivity of a graybody lies between 0 and 1, which indicates that it absorbs and emits radiation less efficiently than a perfect blackbody. The energy emitted by a graybody depends on its emissivity as well as its temperature.
03

Comparing Blackbody and Graybody

While blackbodies absorb and emit radiation at the maximum rate possible for their temperature, graybodies do not. A graybody will emit a fraction of the radiation emitted by a blackbody due to its lower emissivity value. The relationship between the emissivities of blackbodies and graybodies can be represented by the equation: \(P_{gray} = e \cdot P_{black}\), where \(P_{gray}\) is the power radiated by the graybody, \(e\) is the emissivity of the graybody, and \(P_{black}\) is the power radiated by a blackbody at the same temperature.
04

Diffuse Gray Surface Definition

A diffuse gray surface is a surface that reflects and emits radiation uniformly in all directions. It meets two criteria: firstly, its emissivity is constant for all directions and wavelengths, and secondly, it follows Lambert's cosine law which states that the intensity of radiation emitted is proportional to the cosine of the angle between the direction of emission and the surface normal. In simple terms, a diffuse gray surface emits and reflects radiation evenly and independently of the angle of incidence.
05

Diffuse Gray Surface Characteristics

The main characteristics of a diffuse gray surface are: 1. Constant emissivity for all directions and wavelengths. 2. Lambert's cosine law governs the emission and reflection of radiation. 3. It emits and reflects radiation evenly and independently of the angle of incidence. In summary, a graybody is an object that emits and absorbs radiation less efficiently than a blackbody due to its lower emissivity. A diffuse gray surface is a specific type of graybody that reflects and emits radiation uniformly in all directions, following Lambert's cosine law.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Blackbody
A blackbody is a theoretical concept used in physics to describe an idealized object. This object absorbs all electromagnetic radiation that hits it, without reflecting any. The unique property of a blackbody is its ability to emit radiation solely based on its temperature. It follows Planck's Law, which gives the spectrum of radiation emitted by a blackbody.
  • Perfect absorber: Absorbs all incident radiation.
  • Perfect emitter: Emits maximum possible radiation for its temperature.
  • Emissivity: A perfect blackbody has an emissivity of exactly 1.
The concept of a blackbody is often used as a reference when studying real-world objects that do not perfectly fit this model but can be approximated as such.
Emissivity
Emissivity is a measure of how effectively a surface emits radiation compared to a blackbody. It is a dimensionless quantity with values ranging from 0 to 1.
  • Value of 1: Would mean the object emits radiation as efficiently as a blackbody.
  • Value less than 1: The object is less efficient in emitting radiation compared to a blackbody.
The emissivity of a material depends on the type of material, its surface condition, and temperature. In practical terms, emissivity helps in determining how objects emit and absorb thermal energy.
Diffuse Gray Surface
A diffuse gray surface is a practical extension of the graybody model. It refers to a surface that maintains consistent emissivity across various angles and emits uniformly.
Key Characteristics:
  • Constant emissivity regardless of direction or wavelength.
  • Even emission and reflection of radiation in all directions.
Adhering to Lambert's Law, such surfaces emit radiation proportionally to the cosine of the angle from the surface normal. Diffuse gray surfaces are often used in models requiring a simplified assumption about emission and reflection patterns.
Planck's Law
Planck's Law describes the electromagnetic radiation emitted by a blackbody in thermal equilibrium at a given temperature. It provides the spectral distribution of radiation as a function of wavelength and temperature.
Equation:\[B(\lambda, T) = \frac{2hc^2}{\lambda^5} \frac{1}{e^{(hc/\lambda kT)} -1}\]where:
  • \(B(\lambda, T)\) is the spectral radiance.
  • \(\lambda\) is the wavelength.
  • \(T\) is the absolute temperature.
  • \(h\) is Planck's constant.
  • \(c\) is the speed of light.
  • \(k\) is Boltzmann's constant.
Planck's Law is fundamental in understanding how objects at different temperatures emit radiation, forming the basis for much of thermal radiation theory.
Lambert's Cosine Law
Lambert's Cosine Law relates to the intensity of light emitted from a surface. According to this law, the intensity is proportional to the cosine of the angle between the emission direction and the surface normal. This principle is widely used for modeling diffuse surfaces.
Key Aspects:
  • Describes emission patterns: Intensity reduces as the angle increases from the normal.
  • Helps in modeling diffuse surfaces like walls or rough surfaces.
Lambert鈥檚 Cosine Law provides a simplified approach for understanding how surfaces emit light or other radiation, especially useful in designing and predicting the behavior of light in engineering applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider an opaque plate that is well insulated on the edges and it is heated at the bottom with an electric heater. The plate has an emissivity of \(0.67\), and is situated in an ambient surrounding temperature of \(7^{\circ} \mathrm{C}\) where the natural convection heat transfer coefficient is \(7 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). To maintain a surface temperature of \(80^{\circ} \mathrm{C}\), the electric heater supplies \(1000 \mathrm{~W} / \mathrm{m}^{2}\) of uniform heat flux to the plate. Determine the radiosity of the plate under these conditions.

We can see the inside of a microwave oven during operation through its glass door, which indicates that visible radiation is escaping the oven. Do you think that the harmful microwave radiation might also be escaping?

The emissivity of a surface coated with aluminum oxide can be approximated to be \(0.15\) for radiation at wavelengths less than \(5 \mu \mathrm{m}\) and \(0.9\) for radiation at wavelengths greater than \(5 \mu \mathrm{m}\). Determine the average emissivity of this surface at (a) \(5800 \mathrm{~K}\) and (b) \(300 \mathrm{~K}\). What can you say about the absorptivity of this surface for radiation coming from sources at \(5800 \mathrm{~K}\) and \(300 \mathrm{~K}\) ?

For a surface, how is radiosity defined? For diffusely emitting and reflecting surfaces, how is radiosity related to the intensities of emitted and reflected radiation?

Why is radiation usually treated as a surface phenomenon?
See all solutions

Recommended explanations on Physics Textbooks

Astrophysics

Read Explanation

Turning Points in Physics

Read Explanation

Quantum Physics

Read Explanation

Nuclear Physics

Read Explanation

Electromagnetism

Read Explanation

Geometrical and Physical Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.