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Judging from its unit \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\), can we define thermal conductivity of a material as the rate of heat transfer through the material per unit thickness per unit temperature difference? Explain.

Short Answer

Expert verified
Answer: Yes, based on Fourier's Law and the relationship between thermal conductivity, heat transfer rate, material thickness, and temperature gradient, the definition of thermal conductivity as the rate of heat transfer through the material per unit thickness per unit temperature difference is accurate, as it matches the units (\(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\)).

Step by step solution

01

Understand Thermal Conductivity

Thermal conductivity, denoted by the symbol \(k\), is a property of a material that indicates its ability to conduct heat. It is expressed in \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\). A material with a higher thermal conductivity can transfer heat more efficiently than a material with a lower thermal conductivity.
02

Relate Thermal Conductivity to Heat Transfer

The rate of heat transfer through a material can be described by Fourier's Law of heat conduction, which states that the heat transfer rate, \(q\), is proportional to the product of the thermal conductivity (\(k\)), the cross-sectional area of the material (\(A\)), the temperature gradient (temperature difference per unit thickness, \(\Delta T / d\)): $$q = kA\frac{\Delta T}{d}$$ Where \(d\) represents the thickness of the material.
03

Evaluate the Temperature Gradient

In Fourier's Law, the temperature gradient (\(\Delta T / d)\) represents the change in temperature with respect to the thickness of the material. It is expressed in units of \(\mathrm{K} / \mathrm{m}\). The temperature gradient plays a crucial role in determining the heat transfer rate.
04

Confirm the Definition

Given the relationship between the rate of heat transfer, thermal conductivity, cross-sectional area, and temperature gradient as per Fourier's Law, we can rewrite the equation and isolate thermal conductivity (\(k\)): $$k = \frac{q}{A}\frac{d}{\Delta T}$$ Since \(k\) is expressed in the same units as \(\frac{q}{A}\frac{d}{\Delta T}\), which are \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\), we can confirm that the definition of thermal conductivity as the rate of heat transfer through the material per unit thickness per unit temperature difference is accurate based on its units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is the process through which thermal energy moves from one substance to another. It can occur in three primary ways: conduction, convection, and radiation. In the context of this exercise, we are focusing on conduction. This is when heat moves directly through a substance or between substances that are in direct contact. Conduction happens because particles in hotter regions vibrate more energetically and transfer energy to neighboring cooler particles.

Several factors affect how efficiently heat is transferred:
  • Material properties: Some materials, like metals, conduct heat very well, while others, like wood, do not.
  • Cross-sectional area: The larger the area, the more heat that can be transferred.
  • Temperature difference: A greater difference increases the rate of transfer.
  • Distance: The thickness of the material affects how easily heat can travel through it.
Understanding heat transfer is crucial in designing systems for heating, cooling, and insulating materials.
Fourier's Law
Fourier's Law is fundamental in describing how heat conduction occurs through a material. Named after the French physicist Jean-Baptiste Joseph Fourier, this law states that the heat transfer rate through a material is proportional to the negative gradient of temperatures and the material's cross-sectional area. This law can be mathematically expressed as:\[ q = -kA \frac{dT}{dx} \]Where:
  • \(q\): Heat transfer rate, measured in watts (\(\mathrm{W}\)).
  • \(k\): Thermal conductivity, characteristic of the material.
  • \(A\): Cross-sectional area perpendicular to heat flow.
  • \(dT/dx\): Temperature gradient along the material's direction.
The law highlights how thermal energy flow is affected by material properties and temperature changes. It's essential in engineering fields where temperature control is vital, such as in designing buildings, engines, and electronic devices.
Temperature Gradient
The temperature gradient is a crucial component in the study of heat conduction and plays a pivotal role in Fourier's Law. It describes how temperature changes along the length of a material. The gradient is defined as the difference in temperature per unit distance, typically expressed in \(\mathrm{K}/\mathrm{m}\).

The significance of the temperature gradient lies in its direct influence on the rate of heat transfer. A steeper gradient—where temperature changes more rapidly over a shorter distance—means heat flows faster. This happens because heat naturally moves from hotter to cooler areas to equalize temperatures.

Factors affecting the temperature gradient include:
  • Material properties: Materials with high thermal conductivity have less steep gradients compared to insulating materials.
  • Environmental conditions: The surrounding temperature can affect how steep the gradient is.
  • Initial temperature distribution: How heat is initially spread inside the material also impacts the gradient.
Being able to manipulate and understand temperature gradients is key for efficient thermal management, especially in specialized applications like electronics cooling and climate control systems.

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Most popular questions from this chapter

Two surfaces, one highly polished and the other heavily oxidized, are found to be emitting the same amount of energy per unit area. The highly polished surface has an emissivity of \(0.1\) at \(1070^{\circ} \mathrm{C}\), while the emissivity of the heavily oxidized surface is \(0.78\). Determine the temperature of the heavily oxidized surface.

Heat is lost steadily through a \(0.5-\mathrm{cm}\) thick \(2 \mathrm{~m} \times 3 \mathrm{~m}\) window glass whose thermal conductivity is \(0.7 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The inner and outer surface temperatures of the glass are measured to be \(12^{\circ} \mathrm{C}\) to \(9^{\circ} \mathrm{C}\). The rate of heat loss by conduction through the glass is (a) \(420 \mathrm{~W}\) (b) \(5040 \mathrm{~W}\) (c) \(17,600 \mathrm{~W}\) (d) \(1256 \mathrm{~W}\) (e) \(2520 \mathrm{~W}\)

The outer surface of a spacecraft in space has an emissivity of \(0.8\) and a solar absorptivity of \(0.3\). If solar radiation is incident on the spacecraft at a rate of \(950 \mathrm{~W} / \mathrm{m}^{2}\), determine the surface temperature of the spacecraft when the radiation emitted equals the solar energy absorbed.

The critical heat flux (CHF) is a thermal limit at which a boiling crisis occurs whereby an abrupt rise in temperature causes overheating on fuel rod surface that leads to damage. A cylindrical fuel rod of \(2 \mathrm{~cm}\) in diameter is encased in a concentric tube and cooled by water. The fuel generates heat uniformly at a rate of \(150 \mathrm{MW} / \mathrm{m}^{3}\). The average temperature of the cooling water, sufficiently far from the fuel rod, is \(80^{\circ} \mathrm{C}\). The operating pressure of the cooling water is such that the surface temperature of the fuel rod must be kept below \(300^{\circ} \mathrm{C}\) to avoid the cooling water from reaching the critical heat flux. Determine the necessary convection heat transfer coefficient to avoid the critical heat flux from occurring.

Why is the thermal conductivity of superinsulation orders of magnitude lower than the thermal conductivity of ordinary insulation?

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