/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Consider a house with a floor sp... [FREE SOLUTION] | 91影视

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Consider a house with a floor space of \(200 \mathrm{~m}^{2}\) and an average height of \(3 \mathrm{~m}\) at sea level, where the standard atmospheric pressure is \(101.3 \mathrm{kPa}\). Initially the house is at a uniform temperature of \(10^{\circ} \mathrm{C}\). Now the electric heater is turned on, and the heater runs until the air temperature in the house rises to an average value of \(22^{\circ} \mathrm{C}\). Determine how much heat is absorbed by the air assuming some air escapes through the cracks as the heated air in the house expands at constant pressure. Also, determine the cost of this heat if the unit cost of electricity in that area is $$\$ 0.075 / \mathrm{kWh}$$.

Short Answer

Expert verified
Answer: The cost of heating the air in the house from 10掳C to 22掳C is approximately $0.34.

Step by step solution

01

Calculate the initial volume of air inside of the house

First, we need to calculate the initial volume of the air inside the house. The volume (V) of any space can be found by multiplying the area (A) by the height (h). In this case: V = A * H Where A = 200 m虏 and H = 3 m. V = 200 m虏 * 3 m = 600 m鲁
02

Find the final volume of air considering the expansion at constant pressure

To find the final volume of air, we can use the formula for the ideal gas law, which is: PV = nRT We know that the initial and final pressures (P) are constant at 101.3 kPa, and the temperature changes from 10掳C to 22掳C. The universal gas constant (R) is 8.314 J/(mol*K). We want to find the final volume (V鈧) and the number of moles (n鈧) of air. To do this, we will first convert the initial and final temperatures to Kelvin by adding 273.15: T鈧 = 10掳C + 273.15 = 283.15 K T鈧 = 22掳C + 273.15 = 295.15 K From the ideal gas law, we can calculate n鈧乂鈧/T鈧 and n鈧俈鈧/T鈧: n鈧乂鈧/T鈧 = n鈧俈鈧/T鈧 Since the pressures are equal, we can substitute the initial volume (V鈧) into the formula: n鈧俈鈧 = n鈧乂鈧乀鈧/T鈧 Since we are only interested in finding the final volume (V鈧), V鈧 = V鈧乀鈧/T鈧 Substitute the values: V鈧 = 600 m鲁 * (295.15 K / 283.15 K) = 626.23 m鲁
03

Determine the heat absorbed by the air

Now, we will determine the heat (Q) absorbed by the air using the formula: Q = n*C_p*螖T Where C_p is the specific heat capacity of air at constant pressure (1.005 kJ/kg*K), n is the number of moles (n = n鈧 - n鈧), and 螖T is the change in temperature (螖T = T鈧 - T鈧). We will first find n by dividing the difference in volumes (V鈧 - V鈧) by the molar volume of air at standard conditions (22.4 L/mol = 0.0224 m鲁/mol): n = (V鈧 - V鈧) / 0.0224 m鲁/mol = (626.23 m鲁 - 600 m鲁) / 0.0224 m鲁/mol 鈮 1169.64 mol Now we can find Q: Q = n * C_p * 螖T = 1169.64 mol * 1.005 kJ/mol*K * (295.15 K - 283.15 K) 鈮 16447.06 kJ
04

Compute the cost of the absorbed heat

Finally, we can calculate the cost of the absorbed heat. First, we need to convert the heat from kJ to kWh: 1 kWh = 3600 kJ 16447.06 kJ * (1 kWh / 3600 kJ) 鈮 4.57 kWh Now we can calculate the cost using the given unit cost of electricity ($0.075/kWh): Cost = 4.57 kWh * \(0.075/kWh 鈮 \)0.34 Thus, the cost of heating the air in the house from 10掳C to 22掳C is approximately $0.34.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental equation in thermodynamics that relates the pressure, volume, and temperature of a gas. It can be expressed as \( PV = nRT \), where:
  • \(P\) stands for pressure, measured in Pascals or kilopascals.
  • \(V\) represents the volume, often in cubic meters.
  • \(n\) is the number of moles of the gas.
  • \(R\) is the universal gas constant, \(8.314 \) J/(mol路K).
  • \(T\) is the temperature in Kelvin.
To solve for changes in the conditions of a gas, like in our problem, it's crucial to keep pressure constant when volume and temperature change. The relationship allows us to determine unknown variables if certain conditions are held constant, making it useful for understanding real-world behaviors of gases. In this exercise, the Ideal Gas Law helps us find the final volume of air after it heats from 10掳C to 22掳C in a house, a practical example of thermal expansion at constant pressure.
Specific Heat Capacity
Specific Heat Capacity indicates how much heat energy is needed to change a substance's temperature by one degree Celsius per unit mass. For air, the specific heat capacity at constant pressure is approximately \(1.005\, \text{kJ/kg}\cdot\text{K}\). This value allows us to calculate the total energy required to heat a space. We use it in the formula \( Q = n * C_p * \Delta T \), where:
  • \(Q\) is the heat absorbed or released.
  • \(n\) represents the number of moles of air.
  • \(C_p\) is the specific heat capacity at constant pressure.
  • \(\Delta T\) is the temperature change in Kelvin.
The higher the specific heat capacity, the more energy is required to change the temperature, indicating the efficiency of materials in heat absorption or emission. In our scenario, this concept helps determine the amount of energy the air within the house absorbs to increase its temperature.
Energy Cost Calculation
Energy Cost Calculation converts the heat energy needed (usually measured in kilojoules) into an economic cost based on your electricity rate. This involves converting the energy from kilojoules to kilowatt-hours (kWh), a common unit for billing electricity. The conversion is straightforward:
  • 1 kWh equals 3600 kJ.
Once the energy is in kWh, you can multiply it by the electricity unit cost. For instance, with an energy use of 4.57 kWh and a rate of \(0.075/kWh, the cost is:
  • 4.57 kWh \( \times \) \)0.075/kWh \( \approx \) $0.34.
This final step adds a practical dimension to understanding energy use, as it enlightens us on the financial implications of consuming energy, essential for budgeting and efficiency awareness in operating household systems.
Thermal Expansion
Thermal Expansion describes how materials expand when their temperature increases. This concept is especially important for gases, which increase in volume when heated under constant pressure. In the context of our task, we apply thermal expansion principles to explain the air volume increase inside the house as the temperature rises from 10掳C to 22掳C. We can quantify this expansion using the initial and final temperatures converted to Kelvin since thermal behaviors are often analyzed in absolute temperature. The Ideal Gas Law ultimately lets us calculate new volumes by considering constant pressure and changing temperature, predicting how much more space a heated gas will occupy. Understanding thermal expansion is crucial for managing temperature-related changes in systems, ensuring built environments like houses can maintain comfort and structural integrity as climate conditions evolve.

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