/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 The height of the point vertical... [FREE SOLUTION] | 91Ó°ÊÓ

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The height of the point vertically above the earth's surface, at which acceleration due to gravity becomes \(1 \%\) of its value at the surface is (Radius of the earth \(=R\) ) (a) \(8 R\) (b) \(9 R\) (c) \(10 R\) (d) \(20 R\)

Short Answer

Expert verified
The short solution leads to the equation \( [1+(h/R)]^2 = 100 \). Solving this equation gives \(h = 9R\). Thus, the correct answer is (b) \(9R\). The exact details of the calculation could vary depending on how the student is used to solve quadratic equations.

Step by step solution

01

Understand and Use the Gravitational Force Formula

The Acceleration due to gravity at a height \(h\) above the earth's surface is given by the universal gravitational force formula \(g' = \frac{G * M }{ (R+h)^2 }\) where \(g'\) is the gravitational force at height \(h\), \(G\) is the gravitational constant, \(M\) is the mass of the Earth, and \(R\) is the radius of the Earth.
02

Express the given condition mathematically

The problem states that the acceleration due to gravity at a certain height is 1% of its value at the surface of earth. Mathematically, this could be expressed as \(g' = 0.01*g \), where \(g\) is the gravitational force at the earth's surface.
03

Substitute the formula of \(g'\) to find the value of \(h\)

Substituting the value of \(g'\) in the equation \(g' = 0.01*g\), we obtain: \(\frac{G * M }{ (R+h)^2 } = 0.01 * \frac{G * M }{ R^2 }\). Simplifying this equation should provide us with the value of \(h\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Gravity is a fundamental force that pulls objects toward the center of the Earth. It's what keeps your feet on the ground and what makes objects fall. The acceleration due to gravity on Earth's surface is approximately \(9.8 \, m/s^2\). This value represents the rate at which an object's velocity increases as it falls due to Earth's gravity.
At higher altitudes, the acceleration due to gravity decreases. In the exercise, the main objective is to find the height where this acceleration becomes only 1% of its surface value. To express this change in mathematical terms, we use the formula:\[g' = (0.01)g\] where \(g'\) is the gravitational acceleration at height \(h\) and \(g\) is the standard gravitational acceleration on Earth's surface. Understanding how to manipulate these equations is crucial for solving similar problems in gravitational physics.
Gravitational Constant
The gravitational constant, denoted as \(G\), is a fundamental part of the universal gravitational formula. This constant helps quantify the strength of gravity between two objects. Its approximate value is \( 6.674 \times 10^{-11} \, \text{N}\,\text{m}^2/\text{kg}^2\).
In this exercise, \(G\) allows us to calculate the gravitational force at a height \(h\) above Earth's surface. This is done using the equation:\[ g' = \frac{G \cdot M}{(R+h)^2} \]where \(M\) is Earth's mass, \(R\) is Earth's radius, and \(h\) is the height above Earth's surface.
Radius of the Earth
The radius of the Earth, symbolized by \(R\), is essential for calculations involving gravitational force and acceleration. Generally, Earth's radius is approximately \( 6371 \, \text{km} \).
This value is used whenever you need to assess gravitational forces at different heights. In the context of the problem, the radius of the Earth helps define how the gravitational pull weakens as you move further from the surface.
The gravitational pull decreases with increasing distance from the center of the Earth, emphasizing the significance of understanding the radius in gravitation-related studies.
Mathematical Substitution
Mathematical substitution is a technique used to solve equations by replacing one part of the equation with another expression. It simplifies the process of finding unknown variables.
In the step-by-step solution, we used substitution by setting:\[ g' = \frac{G \cdot M}{(R+h)^2} = 0.01 \cdot \frac{G \cdot M}{R^2} \]By simplifying this equation, unnecessary components such as \(G\) and \(M\) cancel out, aiding us in isolating the variable \(h\). This process allows us to find the required height above the Earth's surface where the acceleration due to gravity falls to 1% of its surface value. The simplified form helps in understanding how different variables interact in the context of gravity.

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