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Let \(l\) be the moment of inertia of an uniform square plate about an axis \(A B\) that passes through its centre and is parallel to two of its sides. \(C D\) is a line in the plane of the plate that passes through the centre of the plate and makes an angle \(\theta\) with \(A B .\) The moment of inertia of the plate about the axis \(C D\) is then equal to [IIT-JEE 1998] (a) \(l\) (b) \(l \sin ^{2} \theta\) (c) \(l \cos ^{2} \theta\) (d) \(l \cos ^{2} \frac{\theta}{2}\)

Short Answer

Expert verified
The moment of inertia of the plate about the axis \(CD\) is \(l[1 - \sin^2 \theta\cos^2 \theta]\), which is not equivalent to any of the given options (a), (b), (c), or (d). Thus, a correct option is missing in the problem statement.

Step by step solution

01

Identify the Knowns

The moment of inertia about axis \(AB\) is given as \(l\). The axis \(CD\) makes an angle \(\theta\) with \(AB\).
02

Apply Perpendicular Axis Theorem

According to the theorem, for two axes in the plane of lamina (plate), say, \(OX\) and \(OY\), and one axis \(OZ\) perpendicular to this plane, the moment of inertia \(I_z\) about \(OZ\) is given by \(I_z=I_x + I_y\). However, our axes \(AB\) and \(CD\) lie in the same plane and are not perpendicular to each other.
03

Project the Axis CD

We will break down the moment of inertia about axis \(CD\) into components along \(AB\) (let's call it \(I_{AB}\)) and along a new axis \(DC'\) perpendicular to \(AB\). According to the Perpendicular Axis Theorem, \(l = I_{AB} + I_{DC'}\). As the axis \(CD\) makes an angle of \(\theta\) with \(AB\), it follows that \(I_{CD} = I_{AB}\cos^2 \theta + I_{DC'}\sin^2 \theta\).
04

Substituting Values

Now, substituting values of \(I_{AB}\) and \(I_{DC'}\) from \(l = I_{AB} + I_{DC'}\), we get \(I_{CD} = l\cos^2 \theta + (l - l\cos^2 \theta)\sin^2 \theta = l\cos^2 \theta + l\sin^2 \theta - l\cos^2 \theta\sin^2 \theta\). As the square of sine and cosine adds up to 1, \(\sin^2 \theta + \cos^2 \theta = 1\). Thus, \(I_{CD} = l[1 - \sin^2 \theta\cos^2 \theta]\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perpendicular Axis Theorem
The Perpendicular Axis Theorem is a useful tool in understanding the distribution of a plane object's mass and its rotational inertia. It is applicable to flat, two-dimensional shapes, such as sheets or plates. The theorem states that for any lamina lying in the X-Y plane, the moment of inertia around an axis perpendicular to this plane (let's call it Z) is the sum of the moments of inertia about two perpendicular axes lying in the plane (X and Y). Mathematically, it is expressed as: \[ I_z = I_x + I_y \] This theorem is beneficial for solving problems involving rotational dynamics where understanding how inertia is influenced by different axes is crucial. It simplifies calculations when analyzing rotational forces by breaking down complex inertia into simpler components.
Angular Motion
Angular motion refers to the movement of an object about a pivot or axis point. Unlike linear motion, angular motion accounts for the object's radius and involves parameters like angular velocity, angular acceleration, and torque. When dealing with angular motion: - **Angular Velocity (\(\omega\))**: This describes how fast something is spinning or rotating. It's the rate of change of the angular displacement and is usually measured in radians per second.- **Angular Acceleration (\(\alpha\))**: This is the rate at which an object's angular velocity changes. It's measured in radians per second squared.- **Torque (\(\tau\))**: Torque is the rotational equivalent of force, causing an object to spin faster, slower, or change direction. The magnitude of torque depends on the force applied, the length of the arm (distance from the axis), and the angle between force and arm. Understanding these parameters helps in analyzing and predicting how objects will behave when subjected to rotational forces.
Rotational Dynamics
Rotational dynamics explains how objects rotate and respond to applied forces. This branch of mechanics is crucial for examining how forces cause rotation and affect the overall movement of objects. Important components of rotational dynamics include: - **Moment of Inertia (\(I\))**: A property defining how mass is distributed concerning the axis of rotation. The greater the inertia, the harder it is to change the rotational speed.- **Rotational Equilibrium**: Achieved when the sum of all torques acting on an object is zero, resulting in a constant rotational speed (can be zero, meaning no rotation, or a constant non-zero speed).- **Rotational Kinetic Energy**: This is the energy due to rotation; given by \(\frac{1}{2} I \omega^2\), showing a relationship between inertia and velocity. By understanding these concepts, students can better grasp how rotational systems work and how inertia plays a significant role in those dynamics.

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Most popular questions from this chapter

Moment of inertia of a uniform circular disc about a diameter is \(I\). Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be [UPSEAT 2002] (a) \(5 I\) (b) \(6 \underline{I}\) (c) \(3 I\) (d) \(4 I\)

A sphere rolls down on an inclined plane of inclination \(\theta\). What is the acceleration as the sphere reaches bottom (a) \(\frac{5}{7} g \sin \theta\) (b) \(\frac{3}{5} g \sin \theta\) (c) \(\frac{2}{7} g \sin \theta\) (d) \(\frac{2}{5} g \sin \theta\)

A wheel is rotating with an angular speed of \(20 \mathrm{rad} / \mathrm{sec} .\) It is stopped to rest by applying a constant torque in \(4 s\). If the moment of inertia of the wheel about its axis is \(0.20 \mathrm{~kg}-\mathrm{m}^{2}\), then the work done by the torque in two seconds will be (a) \(10 J\) (b) \(20 J\) (c) \(30^{\prime} J\) (d) \(40 \cdot J\)

The angular velocity of a body is \(\vec{\omega}=2 \hat{i}+3 \hat{j}+4 \hat{k}\) and a torque \(\vec{\tau}=\hat{i}+2 \hat{j}+3 \hat{k}\) acts on it. The rotational power will be (a) \(20 \mathrm{~W}\) (b) \(15 W\) (c) \(\sqrt{17} W\) (d) \(\sqrt{14} W\)

If the position vector of a particle is \(\vec{r}=(\hat{i}+4 \hat{j})\) meter and its angular velocity is \(\vec{\omega}=(\hat{j}+2 \hat{k})\) \(\mathrm{rad} / \mathrm{sec}\) then its linear velocity is (in \(\mathrm{m} / \mathrm{s}\) ) (a) \((8 \hat{i}-6 \hat{j}+3 \hat{k})\) (b) \((3 \hat{i}+6 \hat{j}+8 \hat{k})\) (c) \(-(3 \hat{i}+6 \hat{j}+6 \hat{k})\) (d) \((6 \hat{i}+8 \hat{j}+3 \hat{k})\)

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