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A particle of mass \(m\) is describing a circular path of radius \(r\) with uniform speed. If \(L\) is the angular momentum of the particle about the axis of the circle, the kinetic energy of the particle is given by [CPMT 1995] (a) \(L^{2} / m r^{2}\) (b) \(L^{2} / 2 m r^{2}\) (c) \(2 L^{2} / m r^{2}\) (d) \(m r^{2} L\)

Short Answer

Expert verified
The correct answer is (b) \(L^{2} / 2 m r^{2}\)

Step by step solution

01

Express Velocity in terms of Angular Speed

The velocity \(v\) of the particle can also be represented in terms of angular speed \(\omega\) where \(v = r \omega\).
02

Substitution of velocity in Angular Momentum

Now, substitute the value of \(v\) obtained from the above step into the equation for angular momentum. This means substituting \(r \omega\) for \(v\) in the angular momentum equation \(L = mvr\), we get \(L = m r^{2} \omega \).
03

Calculate the kinetic energy

Next, calculate the kinetic energy of the particle using the formula \(K.E. = 1/2 m v^2\). Substitute \(v = r \omega\) in the kinetic energy formula, we get \(K.E. = 0.5 m (r \omega)^2 = 0.5 m r^2 \omega^2\)
04

Express Kinetic Energy in terms of Angular Momentum

Finally, express the kinetic energy in terms of the angular momentum by substituting \(\omega\) from Step 2 (where we found \(\omega = L / (m r^{2})\)), into the kinetic energy expression we got in the Step 3. This will give \(K.E. = 0.5 m r^2(L / (m r^{2}))^2 = 0.5 L^{2} / m r^{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy can be thought of as the energy of motion. For any object that is moving, it possesses kinetic energy. This energy depends on two factors: the mass of the object and the speed at which it is moving. Mathematically, it is given by the formula: \[ K.E. = \frac{1}{2} m v^2 \]where \( m \) is the mass of the object, and \( v \) is its velocity.
In the context of circular motion, such as a particle moving in a circular path, we often express kinetic energy in terms of angular speed. When a particle moves with uniform speed in a circle, its velocity \( v \) can be linked to its angular speed \( \omega \), fulfilling the relationship:\[ v = r \omega \]where \( r \) is the radius of the circle. Substituting this into the kinetic energy formula creates an opportunity to express this energy in terms of angular momentum.
  • For circular motion, we have \( L = m v r = m r^2 \omega \), the angular momentum related to \( K.E. \).
  • Rewriting \( K.E. \) through \( L \), becomes \( K.E. = \frac{L^2}{2 m r^2} \).
This displays how kinetic energy is influenced not just by mass and velocity, but also by the angular momentum in curved paths.
Circular Motion
Circular motion occurs when an object travels along a circular path. This motion can be characterized by uniform or non-uniform speed. In uniform circular motion, the magnitude of the velocity remains constant, even while the direction continuously changes, causing acceleration.
Acceleration here is towards the center of the circle and is called centripetal acceleration, calculated by:\[ a_c = \frac{v^2}{r} \]where \( v \) is the speed and \( r \) is the radius of the circle. This acceleration is the reason why the object maintains the curve in its path.
  • Circular motion retains constant speed, but changing direction requires force.
  • Newton's second law helps us relate centripetal force needed: \( F_c = m a_c = \frac{m v^2}{r} \).
For circular motion involving angular momentum, it interrelates with kinetic energy and centripetal force, forming a dynamic harmony of physics principles. Angular momentum \( L \) is crucial in this balance, enhancing our understanding of energy dynamics in motion.
Uniform Speed
Uniform speed essentially means that an object is moving at a constant rate throughout its motion. This implies that the magnitude of its velocity remains unchanged over time, which is particularly important in circular motion.
  • Uniform speed guarantees that kinetic energy is stable if mass remains constant.
  • Although speed itself is unvarying, the direction could be adjusting, especially in circular paths.
In uniform circular motion, uniform speed necessitates consistent centripetal force. As speed doesn’t fluctuate, the particle's energy is calculable as constant given a steady mass.
Even with uniform speed, factors like direction and radius play vital roles, especially relating to kinetic energy and angular momentum. To better understand speed in circles:
  • Velocity fixes at \( v = r \omega \) for **angular speed** \( \omega \).
  • Uniform speed allows for straightforward calculations of both kinetic energy (\( \frac{1}{2} mv^2 \)) and angular momentum (\( L = mvr \)).
Hence, understanding uniform speed provides clarity about kinetic energy's leads and lags in the journey of motion.

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