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Since any heat transfer is driven by a temperature difference, how does that affect all the real cycles relative to the ideal cycles?

Short Answer

Expert verified
Real cycles are less efficient than ideal cycles due to energy losses from finite temperature differences causing irreversible processes.

Step by step solution

01

Understanding Heat Transfer and Temperature Difference

In thermodynamic cycles, heat transfer occurs due to a temperature difference between two regions. The efficiency of heat transfer increases with a higher temperature difference, but in practice, this causes inefficiencies in real cycles as compared to the ideal cycles.
02

Ideal vs. Real Cycles

Ideal cycles assume reversible processes with no losses and perfect heat transfer efficiency. Real cycles, on the other hand, involve irreversible processes, losses due to friction, and less efficient heat transfer due to finite temperature differences.
03

Impact on Efficiency

In real cycles, a finite temperature difference is necessary to drive heat transfer, which leads to higher entropy production and, consequently, reduces the thermal efficiency compared to ideal cycles that assume zero temperature difference for reversible heat transfer.
04

Energy Losses Due to Temperature Difference

Real cycles experience energy losses because the systems cannot achieve heat transfer at the same temperatures as the reservoirs. This results in additional entropy and less work output than the ideal cycle assumptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a fundamental concept in thermodynamics, vital for understanding how energy moves within systems. It emerges due to a temperature difference between a hot source and a cooler sink. This difference drives the movement of heat energy from one area to another. Typically, heat flows from the region with higher temperature to the lower temperature region. The greater the temperature difference, the more potent the heat transfer. However, this also introduces inefficiencies in real systems. In theory, during ideal heat transfer, all energy could be transferred perfectly. In practice, imperfections lead to some of the energy being lost to the surroundings. This is a key distinction between ideal and real cycles.
Temperature Difference
Temperature difference is the driving force behind heat transfer. It represents the variance in thermal energy between two regions in a system. This difference is crucial because it defines the rate and direction of heat transfer. In real-world applications, systems often have a significant temperature difference to facilitate effective heat flow. However, higher temperature differences can also result in increased inefficiencies, as maintaining large temperature gradients often requires more energy. For ideal cycles, we assume perfect temperature management where temperature gradients are handled flawlessly without energy loss. In reality, managing these differences is a challenge, resulting in additional energy consumption and, ultimately, lower efficiency.
Efficiency
Efficiency is a critical measure in thermodynamics, indicating how effectively a system converts input energy into useful work. It is particularly important for evaluating the performance of thermal cycles. In ideal cycles, efficiency is at its maximum because there are no losses, and all heat transfer is perfectly reversible. However, real cycles face multiple inefficiencies— unwanted heat dissipation, irreversible processes, and friction—all stemming from non-ideal conditions. These factors lead to lower efficiencies compared to idealized scenarios. Real cycle efficiencies are always lower due to the entropy generated within the system, which limits the amount of usable work that can even be extracted.
Ideal vs. Real Cycles
Ideal cycles serve as benchmarks in thermodynamic analysis. They operate under the assumption of perfect conditions where all processes are reversible, and no energy is lost. These cycles allow us to determine maximum possible efficiency. Conversely, real cycles depict how systems actually behave, accounting for practical limitations. In real cycles, irreversible processes such as friction and finite temperature differences lead to inefficiencies.
The finite temperature difference is essential for driving heat transfer but creates entropy, which decreases net work produced by the system.
Real cycles show energy losses not present in ideal cycles, resulting in lower thermal efficiency. Understanding these differences helps in designing processes closer to the ideal but accommodates real-world constraints.

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Most popular questions from this chapter

A Rankine steam power plant should operate with a high pressure of 3 MPa and a low pressure of \(10 \mathrm{kPa}\), and the boiler exit temperature should be \(500^{\circ} \mathrm{C}\). The available high-temperature source is the exhaust of \(175 \mathrm{~kg} / \mathrm{s}\) air at \(600^{\circ} \mathrm{C}\) from a gas turbine. If the boiler operates as a counterflowing heat exchanger in which the temperature difference at the pinch point is \(20^{\circ} \mathrm{C},\) find the maximum water mass flow rate possible and the air exit temperature.

In an actual refrigeration cycle using \(\mathrm{R}-134 \mathrm{a}\) as the working fluid, the refrigerant flow rate is \(0.05 \mathrm{~kg} / \mathrm{s}\). Vapor enters the compressor at \(150 \mathrm{kPa},-10^{\circ} \mathrm{C}\) \(\left(h_{1}=394.2 \mathrm{~kJ} / \mathrm{kg}, s_{1}=1.739 \mathrm{~kJ} / \mathrm{kg} \mathrm{K}\right)\) and leaves at \(1.2 \mathrm{MPa}, 75^{\circ} \mathrm{C}\left(h_{2}=454.2 \mathrm{~kJ} / \mathrm{kg}, s_{2}=\right.\) \(1.805 \mathrm{~kJ} / \mathrm{kg} \mathrm{K}\) ). The power input to the nonadiabatic compressor is measured and found be \(2.4 \mathrm{~kW}\). The refrigerant enters the expansion valve at \(1.15 \mathrm{MPa}\) \(40^{\circ} \mathrm{C}(h=256.4 \mathrm{~kJ} / \mathrm{kg})\) and leaves the evaporator at \(160 \mathrm{kPa},-15^{\circ} \mathrm{C}(h=389.8 \mathrm{~kJ} / \mathrm{kg}) .\) Determine the entropy generation in the compression process, the refrigeration capacity, and the COP for this cycle.

The effect of evaporator temperature on the COP of a heat pump is to be studied. Consider an ideal cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid and a condenser temperature of \(40^{\circ} \mathrm{C}\). Plot a curve for the COP versus the evaporator temperature for temperatures from +15 to \(-25^{\circ} \mathrm{C}\).

A closed FWH in a regenerative steam power cycle heats \(20 \mathrm{~kg} / \mathrm{s}\) of water from \(100^{\circ} \mathrm{C}, 20 \mathrm{MPa}\) to \(200^{\circ} \mathrm{C}, 20 \mathrm{MPa}\). The extraction steam from the turbine enters the heater at \(4 \mathrm{MPa}, 275^{\circ} \mathrm{C}\) and leaves as saturated liquid. What is the required mass flow rate of the extraction steam?

A split evaporator is used to provide cooling of the refrigerator section and separate cooling of the freezer section, as shown in Fig. P9.109. Assume constant pressure in the two evaporators. How does the \(\mathrm{COP}=\left(Q_{L 1}+Q_{L 2}\right) / W\) compare to that of a refrigerator with a single evaporator at the lowest temperature?

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