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Consider the setup with two stacked (temperaturewise ) heat engines, as in Fig. P5.4. Let \(T_{H}=850 \mathrm{~K}\), \(T_{M}=600 \mathrm{~K},\) and \(T_{L}=350 \mathrm{~K} .\) Find the two heat engine efficiencies and the combined overall efficiency assuming Carnot cycles.

Short Answer

Expert verified
Efficiencies: First engine = 29.41%, Second engine = 41.67%; Overall system = 58.83%.

Step by step solution

01

Understand the Carnot Efficiency Formula

The efficiency of a Carnot engine is given by the formula: \( \eta = 1 - \frac{T_C}{T_H} \), where \( T_H \) is the high temperature and \( T_C \) is the low temperature. These temperatures must be in Kelvin.
02

Calculate Efficiency of First Heat Engine

The first engine operates between \( T_H = 850\, \text{K} \) and \( T_M = 600\, \text{K} \). Plug these into the Carnot efficiency formula: \[ \eta_1 = 1 - \frac{600}{850} = 1 - 0.7059 = 0.2941. \]Hence, the efficiency \( \eta_1 \) of the first engine is \( 29.41\% \).
03

Calculate Efficiency of Second Heat Engine

The second engine operates between \( T_M = 600\, \text{K} \) and \( T_L = 350\, \text{K} \). Apply the Carnot efficiency formula: \[ \eta_2 = 1 - \frac{350}{600} = 1 - 0.5833 = 0.4167. \]Thus, the efficiency \( \eta_2 \) of the second engine is \( 41.67\% \).
04

Calculate Overall Efficiency of System

The overall efficiency of two stacked engines is calculated by finding how much of the original heat input to the first engine winds up as useful work. Use the formula: \[ \eta_{ ext{overall}} = 1 - (1 - \eta_1)(1 - \eta_2) \].Substitute the efficiencies: \[ \eta_{ ext{overall}} = 1 - (1 - 0.2941)(1 - 0.4167) \] \[ = 1 - (0.7059)(0.5833) \] \[ = 1 - 0.4117 = 0.5883. \] Therefore, the overall efficiency \( \eta_{\text{overall}} \) of the system is \( 58.83\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is a branch of physics focused on heat, energy, and the transformation of energy from one form to another. It dictates how energy is transferred, used, and conserved and is based upon its four fundamental laws. The First Law of Thermodynamics, also known as the Law of Energy Conservation, states that energy cannot be created or destroyed, only transformed. This underlies the operation of all heat engines, where energy is converted from heat to work.
  • Energy can change forms, such as from heat to work or vice versa.
  • Thermodynamics also helps us understand efficiency, the metric for how well a device converts energy.
The Second Law of Thermodynamics introduces the idea of entropy, a measure of disorder within a system. It establishes that in any energy exchange, if no energy enters or leaves the system, the potential energy of the final state will always be less than that of the initial state, due to energy dispersal.
This essentially places limits on creating work from heat, inspiring the development of heat engines.
Heat Engines
Heat engines are devices that transform thermal energy into mechanical work. They operate on cycles, with the most ideal being the Carnot cycle. The fundamental principle of a heat engine is to take advantage of temperature differences. In other words, heat flows from a hot reservoir to a cooler one, and some of this heat is converted into work.
  • Heat engines are all around us, like in car engines and power plants.
  • They work in cycles, taking heat energy and doing work such as moving pistons.
The efficiency of any heat engine depends on this flow of energy from high to low temperatures. In practice, no engine reaches 100% efficiency due to real-world inefficiencies and irreversibilities.
Understanding heat engines is crucial to improving energy systems and finding ways to generate power sustainably.
Energy Efficiency
Energy efficiency is the measure of how effectively energy is converted from one form to another. It is especially important in the context of heat engines, where it quantifies how much input thermal energy can be converted into useful mechanical work. The efficiency of a heat engine is determined using the ratio of the work output to the heat input.
  • Energy efficiency is key to reducing environmental impact and resource consumption.
  • Higher efficiency means less wastage and better utilization of energy sources.
When applied to heat engines, the Carnot efficiency provides a theoretical maximum based on temperature levels between the heat source and sink. However, real engines often have lower efficiencies due to practical limitations. Improving energy efficiency is vital in engineering, as it can lead to significant energy savings and reduced emissions.
Carnot Cycle
The Carnot cycle represents an idealized heat engine cycle proposed by Sadi Carnot. It sets the standard for the maximum possible efficiency between two temperature reservoirs. The cycle consists of four reversible processes: two isothermal and two adiabatic. Carnot efficiency is calculated using the temperatures of the hot and cold reservoirs.
  • The efficiency formula is: \( \eta = 1 - \frac{T_C}{T_H} \).
  • Carnot cycle efficiency depends solely on the temperature difference.
Despite being theoretically perfect, a real Carnot engine does not exist due to friction and energy losses in engines. However, understanding the Carnot cycle helps engineers design better engines and power systems by providing a benchmark for what's possible. In practice, striving towards Carnot efficiency drives innovation in thermal management and engine design.

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Most popular questions from this chapter

An air conditioner on a hot summer day removes \(8 \mathrm{~kW}\) of energy from a house at \(21^{\circ} \mathrm{C}\) and pushes energy to the outside, which is at \(31^{\circ} \mathrm{C}\). The house has a mass of \(15000 \mathrm{~kg}\) with an average specific heat of \(0.95 \mathrm{~kJ} / \mathrm{kgK}\). In order to do this, the cold side of the air conditioner is at \(5^{\circ} \mathrm{C}\) and the hot side is at \(40^{\circ} \mathrm{C}\). The air conditioner (refrigerator) has a COP that is \(60 \%\) that of a corresponding Carnot refrigerator. Find the actual COP of the air conditioner and the power required to run it.

A window air conditioner cools a room at \(T_{L}=20^{\circ} \mathrm{C}\) with a maximum of \(1.2 \mathrm{~kW}\) power input. The room gains \(0.6 \mathrm{~kW}\) per degree temperature difference to the ambient, and the refrigeration COP is \(\beta=0.6 \beta_{\text {Carnot }}\). Find the maximum outside temperature, \(T_{H},\) for which the air conditioner provides sufficient cooling.

Two heat engines operate between the same two energy reservoirs, and both receive the same \(Q_{H}\). One engine is reversible and the other is not. What can you say about the two \(Q_{L}\) 's?

A sports car engine delivers 100 hp to the driveshaft with a thermal efficiency of \(25 \% .\) The fuel has a heating value of \(40000 \mathrm{~kJ} / \mathrm{kg} .\) Find the rate of fuel consumption and the combined power rejected through the radiator and exhaust.

Arctic explorers are unsure if they can use a \(5-\mathrm{kW}\) motor-driven heat pump to stay warm. It should keep their shelter at \(15^{\circ} \mathrm{C}\). The shelter loses energy at a rate of \(0.5 \mathrm{~kW}\) per degree difference to the colder ambient. The heat pump has a COP that is \(50 \%\) that of a Carnot heat pump. If the ambient temperature can fall to \(-25^{\circ} \mathrm{C}\) at night, would you recommend this heat pump to the explorers?

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