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Suppose we forget the model for heat transfer, \(\dot{Q}=C A \Delta T ;\) can we draw some information about the direction of \(Q\) from the second law?

Short Answer

Expert verified
Yes, \(Q\) flows spontaneously from higher to lower temperature, increasing entropy.

Step by step solution

01

Understand the Second Law of Thermodynamics

The second law of thermodynamics states that in a closed system, the total entropy can never decrease over time. Entropy typically increases when heat transfers from a hot object to a cold one, making the process spontaneous.
02

Analyze Heat Flow Direction

Consider two systems: one at high temperature and one at low temperature. When these systems are in contact, heat, denoted as \(Q\), will naturally flow from the system at higher temperature to the one at lower temperature, increasing the total entropy of the combined system.
03

Establish Heat Direction Using Entropy

Based on the second law, \(Q\) will flow in a direction that results in an increase in entropy. An increase occurs when heat moves from a hot object to a cold object, aligning with the direction of decreasing temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy
Entropy is a fundamental concept in thermodynamics that measures the degree of disorder or randomness in a system. It's crucial because it helps us understand the direction of spontaneous processes. According to the Second Law of Thermodynamics, the entropy of a closed system never decreases over time; it either increases or stays constant in ideal reversible processes. This means processes tend to move towards a state of higher disorder or entropy.
In the context of heat transfer, when two objects at different temperatures come into contact, heat will flow in a way that maximizes the entropy of the combined system. This typically happens when heat transfers from a hot object to a cold one, increasing the total entropy. Thus, entropy not only indicates disorder but also dictates the natural direction of heat flow.
Heat Transfer
Heat transfer is the movement of thermal energy from one object or substance to another, driven by temperature differences. There are three main modes of heat transfer: conduction, convection, and radiation. In each of these, heat always flows from warmer to cooler areas, which aligns with the Second Law of Thermodynamics.
In the exercise, we look at heat transfer as a spontaneous process that naturally occurs between two objects at different temperatures. As heat flows from the hot to the cold object, it causes an increase in the total entropy of the system. This increase in entropy is what ensures that the transfer continues until thermal equilibrium (a state where no more heat transfer occurs) is achieved.
Spontaneous Process
A spontaneous process is a natural process that occurs without external intervention. In thermodynamics, a spontaneous process always leads to an increase in the total entropy of the system plus its surroundings.
When considering heat transfer, which is a classical example of a spontaneous process, the heat will flow naturally from the hot region to the cold region. This direction of heat flow results in an increase in the total entropy, making the process spontaneous according to thermodynamic principles.
  • Spontaneous processes are guided by entropy changes.
  • These processes occur without added energy input.
  • The natural flow of heat (from hot to cold) exemplifies this.
Understanding spontaneous processes helps us predict how systems evolve and change over time.

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Most popular questions from this chapter

A window-mounted air-conditioner unit is placed on a laboratory bench and tested in cooling mode using \(750 \mathrm{~W}\) of electric power with a COP of \(1.75 .\) What is the cooling power capacity and what is the net effect on the laboratory?

A water cooler for drinking water should cool 10 gal/h water from \(65 \mathrm{~F}\) to \(50 \mathrm{~F}\) using a small refrigeration unit with a COP of 2.5 . Find the rate of cooling required and the power input to the unit.

A car engine with a thermal efficiency of \(33 \%\) drives the air-conditioner unit (a refrigerator) as well as powering the car and other auxiliary equipment. On a hot \(\left(35^{\circ} \mathrm{C}\right)\) summer day the air conditioner takes outside air in and cools it to \(5^{\circ} \mathrm{C}\), sending it into a duct using \(2 \mathrm{~kW}\) of power input, it is assumed to be half as good as a Carnot refrigeration unit. Find the extra rate of fuel (kW) being burned just to drive the air conditioner unit and its COP. Find the flow rate of cold air the air-conditioner unit can provide.

A steam power plant has \(1200 \mathrm{~F}\) in the boiler, \(630 \mathrm{Btu} / \mathrm{s}\) work out of the turbine, \(900 \mathrm{Btu} / \mathrm{s}\) is taken out at \(100 \mathrm{~F}\) in the condenser, and the pump work is 30 Btu/s. Find the plant's thermal efficiency. Assuming the same pump work and heat transfer to the boiler, what is the turbine power if the plant is running in a Carnot cycle?

A window-mounted air conditioner removes 3.5 Btu from the inside of a home using 1.75 Btu work input. How much energy is released outside, and what is its COP?

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