/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 118 A Carnot heat engine operating b... [FREE SOLUTION] | 91Ó°ÊÓ

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A Carnot heat engine operating between a high \(T_{H}\) and low \(T_{L}\) energy reservoirs has an efficiency given by the temperatures. Compare this to two combined heat engines, one operating between \(T_{H}\) and an intermediate temperature \(T_{M}\) giving out work \(W_{A}\) and the other operating between \(T_{M}\) and \(T_{L}\) giving out work \(W_{B}\). The combination must have the same efficiency as the single heat engine, so the heat transfer ratio \(Q_{H} / Q_{L}=\psi\left(T_{H}, T_{L}\right)=\left[Q_{H} / Q_{M}\right]\left[Q_{M} / Q_{L}\right]\) The last two heat transfer ratios can be expressed by the same function \(\psi()\) also involving the temperature \(T_{M}\). Use this to show a condition that the function \(\psi\) () must satisfy.

Short Answer

Expert verified
Function \( \psi(T_{H}, T_{L}) \) must satisfy \( \psi(T_{H}, T_{L}) = \psi(T_{H}, T_{M}) \cdot \psi(T_{M}, T_{L}) \).

Step by step solution

01

Understanding Carnot Efficiency

The efficiency of a Carnot heat engine is given by \( \eta = 1 - \frac{T_{L}}{T_{H}} \), where \( T_{H} \) and \( T_{L} \) are the temperatures of the high and low energy reservoirs, respectively.
02

Efficiency of Combined Heat Engines

For two combined heat engines, one operating between \( T_{H} \) and \( T_{M} \), and the other between \( T_{M} \) and \( T_{L} \), the efficiencies are \( \eta_{1} = 1 - \frac{T_{M}}{T_{H}} \) and \( \eta_{2} = 1 - \frac{T_{L}}{T_{M}} \), respectively.
03

Total Efficiency of Combined Heat Engines

The total efficiency of the two combined engines is given by \( \eta_{total} = 1 - \frac{T_{L}}{T_{H}} \). This condition arises because the effective efficiency should match that of a single Carnot engine operating between \( T_{H} \) and \( T_{L} \).
04

Express H and L in terms of Heat Transfer Ratios

The heat transfer ratios are given by \( \frac{Q_{H}}{Q_{L}} = \psi(T_{H}, T_{L}) = \frac{Q_{H}}{Q_{M}} \cdot \frac{Q_{M}}{Q_{L}} \). By equating these forms, \( \psi(T_{H}, T_{L}) = \psi(T_{H}, T_{M}) \cdot \psi(T_{M}, T_{L}) \).
05

Condition for Function ()

To satisfy the equation, the function \( \psi \) must hold true such that \( \psi(T_{H}, T_{L}) = \psi(T_{H}, T_{M}) \cdot \psi(T_{M}, T_{L}) \). This implies that the heat transfer function \( \psi \) is multiplicative across the temperatures of the system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Efficiency
Thermodynamic efficiency describes how well a heat engine converts heat energy into work, compared to the maximum possible efficiency in accordance with the second law of thermodynamics. For a Carnot heat engine, which is an idealized model, this is calculated as the fraction of the temperature difference between the reservoirs over the high-temperature reservoir. The efficiency \( \eta \) of a Carnot engine is given by the formula:
\[ \eta = 1 - \frac{T_{L}}{T_{H}} \]where \( T_{H} \) is the temperature of the hot reservoir and \( T_{L} \) is the temperature of the cold reservoir.
This equation highlights a key aspect: the greater the difference in temperature between the two reservoirs, the higher the efficiency of the engine. However, no real engine can achieve this ideal Carnot efficiency, as it is based on a reversible process without any real-world inefficiencies.
Heat Transfer
Heat transfer in thermodynamics refers to the movement of thermal energy from one body or system to another as a result of a temperature difference. In the context of a Carnot heat engine and combined heat engines, understanding how heat energy flows can help us to determine the efficiency of the engine.
For combined heat engines, heat exchanges occur at three distinct temperature levels: \( T_{H} \), \( T_{M} \), and \( T_{L} \). Heat \( Q_{H} \) is absorbed from the high-temperature reservoir, some of which is converted into work \( W \), and the rest is released as \( Q_{L} \) to the low-temperature reservoir. The relationship between the heat transfers is crucial for analyzing engine efficiency:
  • \( Q_{H} / Q_{L} = \psi(T_{H}, T_{L}) \)
  • This implies that the function \( \psi() \) serves to show how ratios of heat transfer between different stages can be expressed.
Temperature Reservoirs
Temperature reservoirs are a fundamental concept in understanding heat engines and their efficiencies. These reservoirs can be imagined as large bodies capable of absorbing or providing limitless amounts of heat without changing temperature.
In a theoretical Carnot engine, we consider two principal reservoirs:
  • A hot reservoir at temperature \( T_{H} \)
  • A cold reservoir at temperature \( T_{L} \)
The engine can also involve an intermediate reservoir at temperature \( T_{M} \), which plays a role when engines are combined. By using an intermediate temperature, the overall system can balance the energy more effectively, demonstrating how different temperature levels work together to optimize performance and approximate ideal efficiencies.
Combined Heat Engines
Combined heat engines involve multiple stages or sections, typically to create more work or use energy more efficiently than a single-stage engine. In our scenario, these are two engines operating between three reservoirs:
  • The first operates between \( T_{H} \) and \( T_{M} \)
  • The second operates between \( T_{M} \) and \( T_{L} \)
For combined engines, the efficiencies \( \eta_1 \) and \( \eta_2 \) are calculated for each stage and then combined to ensure the system as a whole matches the efficiency of a single Carnot engine:
\[ \eta_{total} = 1 - \frac{T_{L}}{T_{H}} \]This concept shows how engines can be connected in series to achieve an end result similar to that of an ideal single engine. The condition that the function \( \psi(T_{H}, T_{L}) = \psi(T_{H}, T_{M}) \cdot \psi(T_{M}, T_{L}) \) must hold reflects the multiplicativity of the heat transfer across different stages.

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Most popular questions from this chapter

A small house that is kept at \(20^{\circ} \mathrm{C}\) inside loses \(12 \mathrm{~kW}\) to the outside ambient at \(0^{\circ} \mathrm{C}\). A heat pump is used to help heat the house together with possible electric heat. The heat pump is driven by a \(2.5-\mathrm{kW}\) motor, and it has a COP that is one- fourth that of a Carnot heat pump unit. Find the actual COP for the heat pump and the amount of electric heat that must be used (if any) to maintain the house temperature.

An ideal gas Carnot cycle with air in a piston cylinder has a high temperature of \(1000 \mathrm{~K}\) and heat rejection at \(400 \mathrm{~K}\). During heat addition the volume triples. Find the two specific heat transfers \((q)\) in the cycle and the overall cycle efficiency.

A lawnmower tractor engine produces 18 hp using \(40 \mathrm{Btu} / \mathrm{s}\) of heat transfer from burning fuel. Find the thermal efficiency and the rate of heat transfer rejected to the ambient.

A car engine operates with a thermal efficiency of \(35 \%\). Assume the air conditioner has a COP of \(\beta=3\) working as a refrigerator cooling the inside using engine shaft work to drive it. How much extra fuel energy should be spent to remove \(1 \mathrm{~kJ}\) from the inside?

A certain solar-energy collector produces a maximum temperature of \(100^{\circ} \mathrm{C}\). The energy is used in a cycle heat engine that operates in a \(10^{\circ} \mathrm{C}\) environment. What is the maximum thermal efficiency? If the collector is redesigned to focus the incoming light, what should the maximum temperature be to produce a \(25 \%\) improvement in engine efficiency?

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