/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 96 A superheater brings \(2.5 \math... [FREE SOLUTION] | 91Ó°ÊÓ

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A superheater brings \(2.5 \mathrm{~kg} / \mathrm{s}\) of saturated water vapor at \(2 \mathrm{MPa}\) to \(450^{\circ} \mathrm{C}\). The energy is provided by hot air at \(1200 \mathrm{~K}\) flowing outside the steam tube in the opposite direction as the water, a setup known as a counterflowing heat exchanger (similar to Fig. P4.95). Find the smallest possible mass flow rate of the air to ensure that its exit temperature is \(20^{\circ} \mathrm{C}\) larger than the incoming water temperature.

Short Answer

Expert verified
Calculate the heat for water, determine air's exit temperature, then use energy balance to find air's flow rate.

Step by step solution

01

Understand the Problem

We need to find the smallest possible mass flow rate of the hot air such that it raises the water vapor's temperature to \(450^{\circ} \text{C}\) while exiting 20 degrees Celsius higher than the incoming water temperature.
02

Identify Given Data

Water vapor flow rate: \( \dot{m}_{\text{water}} = 2.5 \; \mathrm{kg/s} \) at \(2 \; \mathrm{MPa}\). Final water temperature \(T_{\text{water,out}} = 450^{\circ} \text{C}\). Hot air input temperature \(T_{\text{air,in}} = 1200 \; \text{K}\). The air's exit temperature should be 20°C more than the incoming water temperature.
03

Determine Heat Transfer Required

Find the enthalpy change of the water using steam tables: the transition from saturated vapor at \(2 \; \text{MPa}\) to superheated steam at \(450^{\circ}C\). Subtract the enthalpy of the initial state from the enthalpy of the final state to find \( \Delta h_{\text{water}} \). Then, calculate the total heat needed using \( Q = \dot{m}_{\text{water}} \cdot \Delta h_{\text{water}} \).
04

Set Air Exit Temperature

Since the incoming water temperature is the boiling point at \(2 \; \text{MPa}\) (approximately 212°C for reference), set air exit temperature: \( T_{\text{air,out}} = 212^{\circ} \text{C} + 20^{\circ} \text{C} = 232^{\circ} \text{C} \).
05

Calculate Minimum Air Flow Rate

Use the formula \( Q = \dot{m}_{\text{air}} \cdot C_p \cdot (T_{\text{air,in}} - T_{\text{air,out}}) \), rearrange for \( \dot{m}_{\text{air}} \): \[ \dot{m}_{\text{air}} = \frac{Q}{C_p \cdot (T_{\text{air,in}} - T_{\text{air,out}})} \] where \( C_p \) is the specific heat of air at constant pressure. Use this formula to find \( \dot{m}_{\text{air}} \).
06

Perform Calculations

Substitute all known values into the equations including appropriate values for \( C_p \) (average \(1005 \; \text{J/kg} \cdot \text{K}\) as typical for air). This gives \( \dot{m}_{\text{air}} \) required to transfer the necessary heat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Superheated Steam
Superheated steam is a state of steam where its temperature is elevated beyond the boiling point at a given pressure.
For this exercise, the steam begins as saturated vapor at a pressure of 2 MPa, before being heated to 450°C. This process involves adding heat without increasing pressure.
Superheated steam is advantageous because it holds more energy than saturated steam, making it more efficient for various industrial applications, including turbines and heat exchange systems. In this exercise, understanding how steam tables work is crucial for calculating the enthalpy changes as water transitions from saturated to superheated steam.
  • You start by noting the initial state of the steam, consulting steam tables to get the enthalpy for saturated vapor at 2 MPa.
  • Then, find the enthalpy at the final state, which corresponds to 450°C at the same pressure.
  • The difference in these two enthalpy values gives you the energy added in kilojoules per kilogram (kJ/kg), which is crucial for further calculations.
Keeping a keen eye on these details is pivotal for solving any thermodynamics problem involving superheated steam.
Energy Transfer
Energy transfer in a heat exchanger involves moving heat from a hot substance to a cooler one.
In this setup, hot air flows past and transfers its energy to water vapor, heating it until it becomes superheated steam. The amount of energy transferred, also known as heat transfer (Q), is calculated using the formula: \[ Q = \dot{m}_{\text{water}} \times \Delta h_{\text{water}} \] where \( \dot{m}_{\text{water}} \) is the mass flow rate, and \( \Delta h_{\text{water}} \) is the change in enthalpy.To ensure effective heating, the energy required to reach 450°C must match the energy transferred by hot air. The efficiency of energy transfer heavily relies on temperature differences between the substances.
  • Large temperature difference: More efficient energy transfer.
  • Small temperature difference: Less efficient energy transfer.
Maximizing the difference in temperature between the input and output of both substances ensures optimal energy transfer in this scenario.
Counterflow Heat Exchanger
The counterflow heat exchanger is a clever engineering design where two fluids flow in opposite directions.
This arrangement maximizes the temperature gradient between the fluids, which improves the efficiency of the heat transfer process. In this exercise, hot air travels in one direction, while cooling water vapor moves in the opposite direction.
  • One advantage of counterflow arrangement is the greater heat recovery. Incoming hot air and cooling vapor remain in contact for maximum efficiency.
  • Another significant feature is the ability to achieve a smaller temperature difference between the outlet and inlet. This facilitates substantial heat exchange even when fluids have similar initial temperatures.
Through this design, it becomes possible for the exit air temperature to be higher than the water vapor entering temperature by 20°C, fulfilling the condition set by the exercise. This efficiency highlights why counterflow arrangements are common in industrial applications.

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Most popular questions from this chapter

Air at \(95 \mathrm{~F}, 16 \mathrm{lbf} / \mathrm{in} .^{2}\) flows in a 4 -in. \(\times 6\) -in. rectangular duct in a heating system. The volumetric flow rate is \(30 \mathrm{cfm}\left(\mathrm{ft}^{3} / \mathrm{min}\right)\). What is the velocity of the air flowing in the duct?

An empty bathtub has its drain closed and is being filled with water from the faucet at a rate of \(10 \mathrm{~kg} / \mathrm{min}\). After \(10 \mathrm{~min}\) the drain is opened and \(4 \mathrm{~kg} / \mathrm{min}\) flows out; at the same time, the inlet flow is reduced to \(2 \mathrm{~kg} / \mathrm{min}\). Plot the mass of the water in the bathtub versus time and determine the time from the very beginning when the tub will be empty.

A storage tank for natural gas has a top dome that can move up or down as gas is added to or subtracted from the tank, maintaining \(110 \mathrm{kPa}, 290 \mathrm{~K}\) inside. A pipeline at \(110 \mathrm{kPa}, 290 \mathrm{~K}\) now supplies some natural gas to the tank. Does its state change during the filling process? What happens to the flow work?

An insulated mixing chamber receives \(2 \mathrm{~kg} / \mathrm{s}\) of \(\mathrm{R}-134 \mathrm{a}\) at \(1 \mathrm{MPa}, 100^{\circ} \mathrm{C}\) in a line with low velocity. Another line with \(\mathrm{R}-134 \mathrm{a}\) as saturated liquid at \(60^{\circ} \mathrm{C}\) flows through a valve to the mixing chamber at 1 MPa after the valve, as shown in Fig. \(P 4.110\). The exit flow is saturated vapor at 1 MPa flowing at \(20 \mathrm{~m} / \mathrm{s}\). Find the flow rate for the second line.

A tank contains \(10 \mathrm{ft}^{3}\) of air at 15 psia, \(540 \mathrm{R}\). A pipe of flowing air at 150 psia, \(540 \mathrm{R}\) is connected to the tank and it is filled slowly to 150 psia. Find the heat transfer needed to reach a final temperature of \(540 \mathrm{R}\).

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