Chapter 3: Problem 235
Ammonia ( \(2 \mathrm{~kg}\) ) in a piston/cylinder is at \(100 \mathrm{kPa}\) \(-20^{\circ} \mathrm{C}\) and is now heated in a polytropic process with \(n=1.3\) to a pressure of \(200 \mathrm{kPa}\). Do not use the ideal gas approximation and find \(T_{2},\) the work, and the heat transfer in the process.
Short Answer
Step by step solution
Understanding Initial Conditions
Analyzing the Polytropic Process
Use Ammonia Tables
Identifying Final State Properties
Calculate Temperature \( T_2 \)
Calculate Work Done in the Process
Calculate Heat Transfer
Final Calculations and Results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polytropic Process
- If \( n = 1 \), it means an isothermal process where the temperature remains constant.
- If \( n = \infty \), it represents an isochoric process with constant volume.
- A value of \( n = 1.3 \) suggests a process that is somewhere between an isothermal and adiabatic process, indicating heat exchange is occurring.
Ammonia Properties
- Ammonia has a high specific heat, meaning it can absorb a lot of heat before its temperature increases significantly.
- Compared to other refrigerants, it has excellent thermodynamic efficiency.
Thermodynamic Tables
- Specific Volume \( v \), which is key in determining the space ammonia occupies at a given state.
- Specific Internal Energy \( u \), necessary for calculating changes in energy during a process.
- Correlated temperature \( T \), essential for pinpointing the final temperature after a pressure change.
First Law of Thermodynamics
- \( Q \) is the heat added to the system.
- \( \Delta U \) is the change in internal energy.
- \( W \) is the work done by or on the system.