/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 185 A 100 -hp car engine has a drive... [FREE SOLUTION] | 91Ó°ÊÓ

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A 100 -hp car engine has a drive shaft rotating at 2000 RPM. How much torque is on the shaft for \(25 \%\) of full power?

Short Answer

Expert verified
The torque on the shaft at 25% power is approximately 89.08 Nm.

Step by step solution

01

Convert Horsepower to Watts

The power of the engine is given as 100 hp (horsepower). First, we need to convert horsepower to watts because 1 hp is equal to 746 watts. Thus, the total power in watts is given by \(100 \times 746 = 74600\) watts.
02

Calculate 25% of Full Power

Since the problem states that we are interested in 25% of full power, we calculate this simply by multiplying the full power in watts by 0.25. Hence, \[0.25 \times 74600 = 18650 \text{ watts.}\]
03

Convert RPM to Radians per Second

The rotational speed is given as 2000 RPM (revolutions per minute). First, convert this to radians per second. Since 1 revolution is \(2\pi\) radians, and 1 minute is 60 seconds, we have \[\omega = \frac{2000 \times 2\pi}{60} \approx 209.4 \text{ rad/s.}\]
04

Determine Torque Using Power Equation

Using the power relation \(P = \tau \cdot \omega\), where \(P\) is power, \(\tau\) is torque, and \(\omega\) is angular velocity, we can solve for torque:\[\tau = \frac{P}{\omega} = \frac{18650}{209.4} \approx 89.08 \text{ Nm.}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Conversion
When dealing with engines and mechanical systems, one essential concept you will encounter is power conversion. This is pivotal because engines often provide power measurements in horsepower (hp), a common unit especially in automotive contexts. However, calculations and formulae in physics typically use watts, the SI unit of power. Therefore, converting between these units is crucial.
To convert horsepower to watts, it's important to remember that 1 hp equals 746 watts. Thus, for any given power in horsepower, you can find the equivalent power in watts by multiplying by 746.
  • Example: If you have 100 hp, converting to watts would mean calculating: \(100 \times 746 = 74600 \text{ watts}\).
This conversion prepares the power input for further analysis or integration into other formulas that require power in watts, like calculating torque or understanding energy consumption.
Rotational Speed
Rotational speed is a measure of how fast an object is spinning. The standard unit for this is revolutions per minute (RPM). However, when using it in calculations, particularly those involving angular measurements, it is often necessary to convert RPM into radians per second.
This conversion is because radians are the standard angular unit in physics, offering a universal measure across different contexts.
  • To convert RPM to radians per second, use the formula: \[ \omega = \frac{\text{RPM} \times 2\pi}{60} \] Where \(2\pi\) radians are equivalent to one full rotation, and there are 60 seconds in a minute.
In our example, 2000 RPM converts to approximately 209.4 rad/s. This conversion allows you to use rotational speed in torque and power equations without unit inconsistencies.
Angular Velocity
Angular velocity is the rate at which an object rotates or revolves around an axis. It's a key parameter in rotational dynamics and is expressed in radians per second (rad/s). This measure describes how fast an object is rotating, providing a foundation for further calculations such as torque.
The angular velocity is derived from rotational speed, as converted from RPM in the previous section. It forms a critical part of the equation when determining torque using power, as shown in the formula:
  • \( P = \tau \cdot \omega \) Where \(P\) is the power, \(\tau\) is the torque, and \(\omega\) is the angular velocity.
Knowing the angular velocity allows you to connect the dots between how fast the shaft spins and how much force is applied over a certain distance, which is essential in both mechanical and electrical applications.
Mechanical Power
Mechanical power refers to the rate at which work is done within mechanical systems and is fundamental to understanding how efficient these systems are. When referring to engines and motor systems, mechanical power can be calculated using various power-related formulas.
A common approach to finding mechanical power in the context of a rotating system is using the relation:
  • \(P = \tau \cdot \omega\) Where \(\tau\) is torque and \(\omega\) is angular velocity in rad/s.
This formula demonstrates how power relates to both the force of rotation (torque) and its rate (angular velocity). In our example, knowing the power output (25% of total power in watts) and the angular velocity allows for calculating the applied torque.
Understanding mechanical power can aid in analyzing engine performance, optimizing systems, and anticipating how variations in torque or speed affect overall power. This knowledge is vital for engineers and technicians working with mechanical systems.

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Most popular questions from this chapter

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