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For a liquid or a solid, is \(v\) more sensitive to \(T\) or \(P ?\) How about an ideal gas?

Short Answer

Expert verified
For liquids or solids, volume is more sensitive to T. For ideal gases, volume is equally sensitive to both T and P.

Step by step solution

01

Understanding Sensitivities

To determine if a volume (v) is more sensitive to changes in temperature (T) or pressure (P), we look at the material's isothermal compressibility (b), which represents sensitivity to P, and the coefficient of thermal expansion (a), which represents sensitivity to T.
02

Sensitivity in Liquid or Solid

For liquids and solids, the compressibility (b) is generally much smaller than the coefficient of thermal expansion (a). As a result, volume is more sensitive to temperature (T) changes than pressure (P) changes.
03

Sensitivity in Ideal Gas

In an ideal gas, the volume is directly related to temperature and pressure by the equation PV = nRT. Since the change in volume relative to pressure and temperature follows linear relationships, volume (v) is equally sensitive to changes in both temperature (T) and pressure (P).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isothermal Compressibility
Isothermal compressibility is a measure of a material's change in volume under pressure while the temperature remains constant. It is an important property in thermodynamics.

When we apply pressure to a substance, the isothermal compressibility, denoted by \( \beta \), helps tell us how much the volume decreases.

For solids and liquids, compressibility is typically quite low, meaning they do not easily change volume with pressure. This is because the molecules in solids and liquids are closely packed.

In mathematical terms, isothermal compressibility is given by the formula:\[\beta = -\frac{1}{V} \left(\frac{\partial V}{\partial P} \right)_T\]
  • \( \beta \) is the isothermal compressibility.
  • \( V \) is volume.
  • \( P \) is pressure.
  • \( T \) indicates constant temperature.
Solids and liquids tend to have low compressibility, while gases have higher compressibility because gases' particles are much further apart and can move closer together with increased pressure.
Coefficient of Thermal Expansion
The coefficient of thermal expansion describes how the volume of a material changes with a change in temperature.

Specifically, it tells us how much a substance expands or contracts when the temperature changes.

Liquids and solids have a higher coefficient of thermal expansion than gases, which means they expand more significantly with temperature changes. This property is important in applications where temperature variations occur, influencing material design considerations.

Mathematically, the coefficient of thermal expansion, represented by \( \alpha \), can be expressed as:\[\alpha = \frac{1}{V} \left(\frac{\partial V}{\partial T} \right)_P\]
  • \( \alpha \) is the coefficient of thermal expansion.
  • \( V \) is volume.
  • \( T \) is temperature.
  • \( P \) indicates constant pressure.
Materials must be selected carefully in engineering when they will be exposed to temperature changes, to avoid issues like cracking or deformation.
Ideal Gas Law
The ideal gas law is a fundamental equation in thermodynamics that describes the behavior of ideal gases. It connects pressure, volume, temperature, and the number of moles of the gas.

The law is usually written as:\[PV = nRT\]
  • \( P \) is the pressure of the gas.
  • \( V \) is the volume of the gas.
  • \( n \) is the number of moles of gas.
  • \( R \) is the ideal gas constant.
  • \( T \) is the absolute temperature of the gas.
This equation assumes the gas particles do not interact and occupy no volume themselves, making it an excellent approximation for many gases under varied conditions.

Since both pressure and temperature have linear influences on volume in an ideal gas, the sensitivity to changes in these conditions is equal, unlike in solids or liquids. This makes understanding and predicting gas behavior under different thermodynamic conditions easier.

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Most popular questions from this chapter

A piston/cylinder contains \(10 \mathrm{lbm}\) butane gas at \(900 \mathrm{R}, 750 \mathrm{lbf} / \mathrm{in} .^{2}\). The butane expands in a reversible polytropic process to \(820 \mathrm{R}, 450\) lbf/in. \(^{2}\). Determine the polytropic exponent and the work done during the process.

Most equations of state are developed to cover which range of states?

A piston/cylinder contains ethane gas initially at \(500 \mathrm{kPa}, 100 \mathrm{~L},\) and at ambient temperature \(0^{\circ} \mathrm{C} .\) The piston is moved, compressing the ethane until it is at \(20^{\circ} \mathrm{C}\) with a quality of \(50 \%\). The work required is \(25 \%\) more than would have been needed for a reversible polytropic process between the same initial and final states. Calculate the heat transfer and the net entropy change for the process.

A 2 -kg mixture of \(50 \%\) argon and \(50 \%\) nitrogen by mole is in a tank at \(2 \mathrm{MPa}, 180 \mathrm{~K}\). How large is the volume using a model of (a) ideal gas and (b) van der Waals' EOS with \(a, b\) for a mixture?

A certain refrigerant vapor enters a steady-flow, constant-pressure condenser at \(150 \mathrm{kPa}, 70^{\circ} \mathrm{C}\), at a rate of \(1.5 \mathrm{~kg} / \mathrm{s}\), and it exits as saturated liquid. Calculate the rate of heat transfer from the condenser. It may be assumed that the vapor is an ideal gas and also that at saturation, \(v_{f} \ll v_{g} .\) The following is known: $$\ln P_{g}=8.15-1000 / T \quad C_{p 0}=0.7 \mathrm{~kJ} / \mathrm{kg} \mathrm{K}$$ with pressure in \(\mathrm{kPa}\) and temperature in \(\mathrm{K}\). The molecular mass is 100 .

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