Chapter 12: Problem 156
A cylinder fitted with a piston contains liquid methanol at \(70 \mathrm{~F}, 15 \mathrm{lbf} / \mathrm{in} .^{2}\) and volume \(1 \mathrm{ft}^{3}\). The piston is moved, compressing the methanol to \(3000 \mathrm{lbf} / \mathrm{in} .^{2}\) at constant temperature. Calculate the work required for this process. The isothermal compressibility of liquid methanol at \(70 \mathrm{~F}\) is \(8.3 \times 10^{-6} \mathrm{in}^{2} / \mathrm{lbf}\)
Short Answer
Step by step solution
Understand the Problem
Recall the Formula for Work in Isothermal Processes
Calculate Volume Change Using Isothermal Compressibility
Calculate Work Done
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isothermal Compressibility
Thermodynamic Work
- For gases, the work done is typically calculated using the pressure-volume relationship through integration.
- For liquids, like methanol, the isothermal compressibility helps in determining the small changes in volume within the system.
Pressure-Volume Relationship
- In an ideal gas, there is a simple relationship where volume changes significantly with pressure changes.
- In liquids, which are mostly incompressible, the change in volume is minute for large pressure changes, simplifying calculations using the isothermal compressibility concept.