Chapter 1: Problem 42
One kilogram of diatomic oxygen \(\left(\mathrm{O}_{2},\right.\) molecular mass of 32 ) is contained in a 500 - \(L\) tank. Find the specific volume on both a mass and a mole basis \((v\) and \(\bar{v})\).
Short Answer
Expert verified
Specific volumes: mass basis is 0.5 m³/kg, mole basis is 0.016 m³/mol.
Step by step solution
01
Define the specific volume on a mass basis
The specific volume on a mass basis \(v\) is defined as the volume \(V\) of the gas divided by its mass \(m\). The formula is \(v = \frac{V}{m}\).
02
Calculate specific volume on a mass basis
Given that the volume \(V\) is 500 L. The mass \(m\) is 1 kg (or 1000 g). Converting volume to cubic meters \( \left(1 \text{ L} = 0.001 \text{ m}^3 \right)\) gives \(500 \times 0.001 = 0.5 \text{ m}^3\).Thus, the specific volume on a mass basis is:\[ v = \frac{0.5 \text{ m}^3}{1 \text{ kg}} = 0.5 \text{ m}^3/\text{kg} \]
03
Define the specific volume on a mole basis
The specific volume on a mole basis \(\bar{v}\) is defined as the volume \(V\) of the gas divided by the number of moles \(n\). The formula is \(\bar{v} = \frac{V}{n}\).
04
Calculate the number of moles
The number of moles \(n\) can be found using the formula \( n = \frac{m}{M} \), where \(M\) is the molar mass of oxygen, which is 32 g/mol. Thus:\[ n = \frac{1000 \text{ g}}{32 \text{ g/mol}} = 31.25 \text{ mol} \]
05
Calculate specific volume on a mole basis
Using the volume in cubic meters from Step 2, calculate the specific volume on a mole basis:\[ \bar{v} = \frac{0.5 \text{ m}^3}{31.25 \text{ mol}} \approx 0.016 \text{ m}^3/\text{mol} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Basis
When we talk about the specific volume on a mass basis, we're referring to how much volume a certain mass of a substance occupies. It's calculated by dividing the volume of the substance by its mass. This concept is particularly useful when you need to assess how much space a material or gas occupies per unit of mass.
In our example, with 500 liters converted to 0.5 cubic meters and a mass of 1 kg, the specific volume is found to be 0.5 \( \text{m}^3/\text{kg} \). This tells us for every kilogram of diatomic oxygen, half a cubic meter is occupied.
- Formula: The specific volume on a mass basis is expressed as \( v = \frac{V}{m} \).
- Units: In the provided exercise, the specific volume is expressed in \( \text{m}^3/\text{kg} \).
In our example, with 500 liters converted to 0.5 cubic meters and a mass of 1 kg, the specific volume is found to be 0.5 \( \text{m}^3/\text{kg} \). This tells us for every kilogram of diatomic oxygen, half a cubic meter is occupied.
Mole Basis
Specific volume on a mole basis deals with how much volume is occupied by one mole of a substance. This is primarily used in chemistry to understand gases and reactions at a molecular level.
The given exercise presents a specific volume on a mole basis as approximately 0.016 \( \text{m}^3/\text{mol} \), indicating that each mole of diatomic oxygen takes up about 0.016 cubic meters. This is valuable for visualizing how tightly or loosely a substance/molecules pack under certain conditions.
- Formula: It is expressed as \( \bar{v} = \frac{V}{n} \).
- Units: In the given problem, it is in \( \text{m}^3/\text{mol} \).
The given exercise presents a specific volume on a mole basis as approximately 0.016 \( \text{m}^3/\text{mol} \), indicating that each mole of diatomic oxygen takes up about 0.016 cubic meters. This is valuable for visualizing how tightly or loosely a substance/molecules pack under certain conditions.
Molar Mass
Molar mass is the mass of a given substance divided by the amount of substance, measured in moles. It is an essential concept in chemistry because it relates the mass of a substance to the number of moles.
In our problem with diatomic oxygen, the molar mass is 32 g/mol. This value is crucial for determining the number of moles from a given mass, like when converting 1000 g of oxygen to 31.25 moles. This conversion is a pivotal step in finding the specific volume on either a mass or mole basis.
- Definition: Molar mass \( M \) is typically expressed in \( \text{g/mol} \).
In our problem with diatomic oxygen, the molar mass is 32 g/mol. This value is crucial for determining the number of moles from a given mass, like when converting 1000 g of oxygen to 31.25 moles. This conversion is a pivotal step in finding the specific volume on either a mass or mole basis.
Number of Moles
The number of moles represents how many moles of a substance are present in a given sample. It connects physical mass to a chemical amount of substance.
- Formula: It is determined by \( n = \frac{m}{M} \), where \( m \) is mass and \( M \) is molar mass.
- Usage: It's vital for stoichiometry, chemical equations, and understanding molecular interactions.