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A gasoline engine takes air in at \(290 \mathrm{K}\) and 90 kPa and then compresses it. The combustion adds \(1000 \mathrm{kJ} / \mathrm{kg}\) to the air, after which the temperature is \(2050 \mathrm{K}\). Use the cold air properties (i.e., constant heat capacities at \(300 \mathrm{K}\) ) and find the compression ratio, the compression specific work, and the highest pressure in the cycle.

Short Answer

Expert verified
The compression ratio is approximately 8, the compression specific work amounts to approximately 1265 kJ/kg, and the highest pressure in the cycle is around 5.63 MPa.

Step by step solution

01

Understand Given Constants

We have the following initial conditions: a temperature \(T_1 = 290K\), a pressure \(P_1 = 90kPa\), an added heat \(q_{in} = 1000 kJ/kg\), and a final temperature \(T_3 = 2050K\). Since cold-air standard assumptions are applicable, specific heat capacities \(C_p = 1005 J/(kg \cdot K)\) and \(C_v = 718 J/(kg \cdot K)\) are considered constant.
02

Calculation of Compression Ratio

Using the given values of initial and final temperature, calculate the compression ratio (r) using the relation derived from the isentropic process: \(r = (T3/T1)^{Cv/R}\), where the gas constant \(R = Cp-Cv\).
03

Calculation of Compression Work

Compute the compression specific work \(W_{comp}\) using the formula: \(W_{comp} = Cv(T3-T1)\), which is derived from the first law of thermodynamics.
04

Calculation of Highest Pressure

The highest pressure \(P_3\) in the cycle can be calculated using the relation: \(P_3 = P_1 \cdot r^{\gamma}\), where gamma is the ratio of specific heats \(Cp/Cv\). Recall that pressure and volume changes in an Otto cycle engine follow the polytropic process law.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isentropic Process
An isentropic process is a thermodynamic process where entropy remains constant. In the context of engines, this concept is vital because it represents an idealized reversible process without any heat transfer with the surroundings—the gold standard for efficiency. During the compression stage of an Otto cycle engine, the process is assumed to be isentropic. This assumption simplifies calculations and sets a benchmark for real-world performance.

To understand how an isentropic process applies to the compression ratio in an Otto cycle, remember that the relationship between temperature and volume during such a process follows the formula \( r = (T3/T1)^{Cv/R} \), where \( T1 \) and \( T3 \) are the initial and final temperatures respectively, \( Cv \) is the specific heat capacity at constant volume, and \( R \) is the specific gas constant. By using the temperatures given in the problem, one can calculate the ideal compression ratio for the process.
Specific Heat Capacities
Specific heat capacities, represented as \( Cp \) for constant pressure and \( Cv \) for constant volume, are crucial in understanding energy changes in a thermodynamic system. For an ideal gas, these properties define how much heat is required to raise the temperature of a unit mass of the substance by one degree at constant pressure or volume.

In simplifying engine thermodynamics, such as in the cold air standard assumptions, these capacities are often treated as constants. For the combustion engine in our exercise, \( Cp \) and \( Cv \) values at \( 300K \) are used to approximate the processes within the engine. The ratio of these values \( (\gamma = Cp/Cv) \) is instrumental in determining the adiabatic index, essential for calculating work and pressure changes within the thermodynamic cycle.
First Law of Thermodynamics
The first law of thermodynamics, also known as the principle of conservation of energy, states that energy cannot be created or destroyed in an isolated system. Applied to thermodynamics, this law translates into the equation \( Q - W = \Delta E_{int} \), where \( Q \) is the heat added to the system, \( W \) is the work done by the system, and \( \Delta E_{int} \) is the change in internal energy.

For the Otto cycle engine's compression stage, where no heat transfer is assumed (isentropic), the work done on the gas to compress it (\( W_{comp} \) can be found using the specific heat capacity at constant volume and the change in temperature from the first law \( W_{comp} = Cv(T3-T1) \). This specific work calculation aids in designing engine components and predicting performance.
Otto Cycle Engine
The Otto cycle is the idealized cycle for gasoline engines and incorporates four discrete processes: adiabatic (isentropic) compression, constant-volume (isochoric) heat addition, adiabatic (isentropic) expansion, and constant-volume heat rejection. This cycle is a model used to simplify the actual complex processes occurring within gasoline engines.

The high pressure within the cycle, calculated using the compression ratio and the adiabatic index \( P_3 = P_1 \cdot r^{\gamma} \), gives engineers insight into the engine's maximum pressure and informs the design of engine components to withstand these pressures. The principles of the Otto cycle also guide the improvement of fuel efficiency and power output in automotive engine design.

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Most popular questions from this chapter

A Brayton cycle produces \(14 \mathrm{MW}\) with an inlet state of \(17^{\circ} \mathrm{C}, 100 \mathrm{kPa}\), and a compression ratio of \(16: 1 .\) The heat added in the combustion is \(960 \mathrm{kJ} / \mathrm{kg} .\) What is the highest temperature and the mass flow rate of air, assuming cold air properties?

A refrigerator in a laboratory uses \(R-22\) as the working substance. The high pressure is 1200 \(\mathrm{kPa},\) the low pressure is \(201 \mathrm{kPa},\) and the compressor is reversible. It should remove \(500 \mathrm{W}\) from a specimen currently at \(-20^{\circ} \mathrm{C}\) (not equal to \(T_{L}\) in the cycle) that is inside the refrigerated space. Find the cycle COP and the electrical power required.

What is the difference between an open and a closed feedwater heater?

The power plant shown in Fig. 11.40 combines a gas-turbine cycle and a steam- turbine cycle. The following data are known for the gas-turbine cycle. Air enters the compressor at \(100 \mathrm{kPa}\) \(25^{\circ} \mathrm{C},\) the compressor pressure ratio is \(14,\) and the isentropic compressor efficiency is \(87 \%\); the heater input rate is \(60 \mathrm{MW}\); the turbine inlet temperature is \(1250^{\circ} \mathrm{C}\), the exhaust pressure is \(100 \mathrm{kPa},\) and the isentropic turbine efficiency is \(87 \%\); the cycle exhaust temperature from the heat exchanger is \(200^{\circ} \mathrm{C}\). The following data are known for the steam-turbine cycle. The pump inlet state is saturated liquid at \(10 \mathrm{kPa}\), the pump exit pressure is \(12.5 \mathrm{MPa}\), and the isentropic pump efficiency is \(85 \%\); turbine inlet temperature is \(500^{\circ} \mathrm{C}\), and the isentropic turbine efficiency is \(87 \% .\) Determine a. The mass flow rate of air in the gas-turbine cycle. b. The mass flow rate of water in the steam cycle c. The overall thermal efficiency of the combined cycle.

A four-stroke gasoline engine has a compression ratio of 10: 1 with 4 cylinders of total displacement 2.3 L. The inlet state is \(280 \mathrm{K}, 70 \mathrm{kPa}\), and the engine is running at 2100 RPM with the fuel adding \(1800 \mathrm{kJ} / \mathrm{kg}\) in the combustion process. What is the net work in the cycle, and how much power is produced?

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