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A small water pump at ground level has an inlet pipe down into a well at a depth \(H\) with the water at \(100 \mathrm{kPa}, 15^{\circ} \mathrm{C}\). The pump delivers water at \(400 \mathrm{kPa}\) to a building. The absolute pressure of the water must be at least twice the saturation pressure to avoid cavitation. What is the maximum depth this setup will allow?

Short Answer

Expert verified
The maximum depth is approximately 9.83 meters.

Step by step solution

01

Determine Saturation Pressure

To avoid cavitation, the absolute pressure must be twice the saturation pressure. First, refer to the water tables to find the saturation pressure at a temperature of \(15^{\circ} \mathrm{C}\). The saturation pressure \(P_{\text{sat}}\) is approximately \(1.705 \mathrm{kPa}\).
02

Calculate Required Minimum Absolute Pressure

Since the pressure must be at least twice the saturation pressure to avoid cavitation, we calculate the required absolute pressure as: \(P_{\text{required}} = 2 \times P_{\text{sat}} = 2 \times 1.705 = 3.41 \mathrm{kPa}\).
03

Express Pump Inlet Pressure in Terms of Depth

The pressure in the inlet pipe at depth \(H\) is given by \(P_{\text{inlet}} = P_{\text{water}} - \rho g H\), where \(\rho\) is the density of water (approximately \(1000 \mathrm{kg/m^3}\)) and \(g\) is the acceleration due to gravity (\(9.81 \mathrm{m/s^2}\)). We know \(P_{\text{water}} = 100 \mathrm{kPa}\).
04

Calculate Maximum Allowable Depth

Substitute the known minimum pressure and solve for \(H\): \(100\, \mathrm{kPa} - \rho g H = 3.41\, \mathrm{kPa}\). Rearranging gives \(H = \frac{100 - 3.41}{9.81} \approx 9.83 \mathrm{m}\).
05

Validate with Saturation Pressure Condition

Verify that at the calculated depth, the inlet pressure is indeed greater than twice the saturation pressure. Using \(P_{\text{inlet}} = 100 - 9.81 \times 9.83 = 3.41 \mathrm{kPa}\), the condition is satisfied as this is equal to \(P_{\text{required}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Saturation Pressure
Saturation pressure is a critical concept in understanding how to prevent cavitation in pumps. At a given temperature, a liquid's saturation pressure is the vapor pressure at which it changes to vapor. For water, this varies with temperature, meaning at higher temperatures, water transitions to steam at higher pressures.

Understanding saturation pressure is essential when ensuring that the absolute pressure inside a pump does not drop below this threshold. If it does, the water begins to vaporize, leading to cavitation, which can damage the pump.

In the context of the exercise, the water is at a temperature of 15°C. Referencing standard water tables, we find the saturation pressure to be about 1.705 kPa. To prevent cavitation, the inlet pressure must be at least twice this value, ensuring that the water remains liquid and effectively avoids the damage mechanism associated with cavitation.
Hydrostatic Pressure
Hydrostatic pressure is the pressure exerted by a fluid at equilibrium due to the gravitational force acting on it. It's crucial for understanding how water moves within a pump system from a well.

When you have a water column, the pressure increases with depth according to the formula \( P = ho g H \), where \( \rho \) is the fluid density (approximately 1000 kg/m³ for water), \( g \) is the gravitational acceleration (9.81 m/s²), and \( H \) is the height of the water column.

For the pump setup in the exercise, the water at the surface is at 100 kPa pressure. As it descends into the well, the hydrostatic pressure decreases the effective pressure in the inlet pipe. To ensure the pump functions without cavitation, we need the depth \( H \) such that the inlet pressure remains above twice the saturation pressure. Solving \( 100 - ho g H = 3.41 \) kPa, we find that the maximum depth \( H \) allowable is approximately 9.83 meters.
Fluid Mechanics
Fluid mechanics provides the essential principles needed to analyze the behavior of fluids in motion or at rest. It's particularly useful in pump systems, where fluid dynamics governs the movement of water through varying pressures and depths.

In our pump scenario, the principles of fluid mechanics help describe how water flows from a well, into a pump, and to a higher elevation in a building. We consider factors such as pressure differences, fluid density, and gravitational forces, which influence the water's flow.

These factors collectively affect decisions in system design to overcome challenges like cavitation. By applying fluid mechanics, we calculate pressure changes, determine safe operational limits, and design effectively functioning systems without the risk of cavitation, ensuring long equipment life and efficient operation.

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Most popular questions from this chapter

Carbon dioxide enters an adiabatic compressor at \(100 \mathrm{kPa}, 300 \mathrm{~K}\) and exits at \(1000 \mathrm{kPa}, 520 \mathrm{~K}\). Find the compressor efficiency and the entropy generation for the process using Table A.5.

An initially empty spring-loaded piston/cylinder requires \(100 \mathrm{kPa}\) to float the piston. A compressor with a line and valve now charges the cylinder with water to a final pressure of \(1.4 \mathrm{MPa}\), at which point the volume is \(0.6 \mathrm{~m}^{3}\), state 2 . The inlet condition to the reversible adiabatic compressor is saturated vapor at \(100 \mathrm{kPa}\). Find the final mass of water, the piston work from 1 to 2 and the required compressor work.

Two flows of air are both at \(200 \mathrm{kPa}\); one has \(2 \mathrm{~kg} / \mathrm{s}\) at \(400 \mathrm{~K}\), and the other has \(1 \mathrm{~kg} / \mathrm{s}\) at \(290 \mathrm{~K}\). The two flows are mixed together in an insulated box to produce a single exit flow at \(200 \mathrm{kPa}\). Find the exit temperature and the total rate of entropy generation.

Nitrogen gas flowing in a pipe at \(500 \mathrm{kPa}, 200^{\circ} \mathrm{C}\), and at a velocity of \(10 \mathrm{~m} / \mathrm{s}\), should be expanded in a nozzle to produce a velocity of \(300 \mathrm{~m} / \mathrm{s}\). Determine the exit pressure and cross-sectional area of the nozzle if the mass flow rate is \(0.15 \mathrm{~kg} / \mathrm{s}\) and the expansion is reversible and adiabatic.

A large supply line has a steady flow of R-410A at \(175 \mathrm{psia}, 140 \mathrm{~F}\). It is used in three different adiabatic devices shown in Fig. P7.63: a throttle flow, an ideal nozzle, and an ideal turbine. All the exit flows are at 60 psia. Find the exit temperature and specific entropy generation for each device and the exit velocity of the nozzle.

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