/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 A bio-reactor must be kept at \(... [FREE SOLUTION] | 91Ó°ÊÓ

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A bio-reactor must be kept at \(42^{\circ} \mathrm{C}\) by a heat pump driven by a \(3 \mathrm{~kW}\) motor. The reactor has a heat loss of \(12 \mathrm{~kW}\) to the ambient at \(15^{\circ} \mathrm{C}\). What is the minimum COP that will be acceptable for the heat pump?

Short Answer

Expert verified
The minimum COP required is 4.

Step by step solution

01

Understanding COP

The Coefficient of Performance (COP) for a heat pump is defined as the ratio of the heat output to the work input, given by the formula: \[ \text{COP} = \frac{Q_H}{W} \] where \( Q_H \) is the heat added to the system and \( W \) is the work input.
02

Identify Given Values

From the problem, we know the heat loss is \(12 \, \mathrm{kW}\), the motor driving the heat pump is providing \(3 \, \mathrm{kW}\) of power, and the temperatures are \(42^{\circ} \mathrm{C}\) for the bioreactor and \(15^{\circ} \mathrm{C}\) for the ambient temperature.
03

Relate Heat and Work in Equilibrium

For the heat pump to maintain the temperature, it must supply enough heat to compensate for the heat loss, i.e., \( Q_H = 12 \, \mathrm{kW} \). The work input \( W \) from the motor is given as \(3 \, \mathrm{kW}\).
04

Calculate Minimum COP

Using the COP formula, substitute the values: \[ \text{COP} = \frac{Q_H}{W} = \frac{12 \, \mathrm{kW}}{3 \, \mathrm{kW}} = 4 \]. This is the minimum COP value needed to sustain the operation of the heat pump.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Pumps
A heat pump is a device that transfers heat energy from a source to a destination. It usually takes heat from a cooler area and moves it to a warmer area, thereby reversing the natural flow of heat. This makes heat pumps quite essential in both heating and cooling applications. In our exercise, the heat pump is used to prevent heat loss from a bioreactor to the colder surrounding environment.
The functioning of a heat pump relies on basic thermodynamic principles. It uses a small amount of work input, often in the form of electricity, to transfer larger quantities of heat. This makes it energy-efficient when compared to simple electrical heating systems. In the given exercise, the heat pump must counteract a heat loss of 12 kW, with its motor powered by 3 kW, showcasing its efficiency in heat management.
Thermodynamic Cycles
At the heart of a heat pump's operation is the thermodynamic cycle, commonly the refrigeration cycle. This cycle involves a refrigerant, which is a fluid that can easily change state from liquid to gas and vice versa.
Here are the main stages of a typical cycle:
  • Compression: The refrigerant is compressed, raising its temperature.
  • Condensation: The high-pressure, high-temperature refrigerant releases heat to the surroundings and condenses into a liquid.
  • Expansion: The liquid refrigerant passes through an expansion valve, lowering its pressure and temperature.
  • Evaporation: The cold refrigerant absorbs heat from the surrounding environment, returning to a gaseous state.
In the bioreactor scenario, the cycle enables the continuous transfer of heat to maintain the desired temperature, even as heat is lost to the ambient air. Understanding this cycle is critical to grasp the functioning of heat pumps and systems that rely on thermal energy transfer.
Energy Efficiency
Energy efficiency is a key feature of many modern appliances, including heat pumps. In the context of our exercise, the heat pump's efficiency is represented by its Coefficient of Performance (COP). The COP is the ratio of useful heating or cooling provided to the work required to deliver that heating or cooling. It is a measure of how effectively a device uses energy.
A higher COP indicates a more efficient heat pump. Mathematically, the COP for heating is expressed as:\[ \text{COP} = \frac{Q_H}{W} \]where \( Q_H \) is the heat output added to the system, and \( W \) is the work input from the motor. In the bioreactor problem, a COP of 4 signifies that the heat pump transfers 4 times the amount of energy it consumes.
By understanding energy efficiency through the lens of COP, students gain insights into how devices can be optimized to manage energy consumption, ultimately leading to cost savings and reduced environmental impact.

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Most popular questions from this chapter

A heat pump receives energy from a source at \(80^{\circ} \mathrm{C}\) and delivers energy to a boiler that operates at \(350 \mathrm{kPa}\). The boiler input is saturated liquid water and the exit is saturated vapor, both at \(350 \mathrm{kPa}\). The heat pump is driven by a \(2.5-\mathrm{MW}\) motor and has a COP that is \(60 \%\) that of a Carnot heat pump. What is the maximum mass-flow rate of water the system can deliver?

R-410A enters the evaporator (the cold heat exchanger) in an air-conditioner unit at \(-20^{\circ} \mathrm{C}\), \(x=28 \%\) and leaves at \(-20^{\circ} \mathrm{C}, x=1\). The COP of the refrigerator is \(1.5\) and the mass-flow rate is \(0.003 \mathrm{~kg} / \mathrm{s}\). Find the net work input to the cycle.

In a few places where the air is very cold in the winter, such as \(-30^{\circ} \mathrm{C}\), it is possible to find a temperature of \(13^{\circ} \mathrm{C}\) below ground. What efficiency will a heat engine have when operating between these two thermal reservoirs?

Arctic explorers are unsure if they can use a \(5-\mathrm{kW}\) motor-driven heat pump to stay warm. It should keep their shelter at \(60 \mathrm{~F}\); the shelter loses energy at a rate of \(0.3 \mathrm{Btu} / \mathrm{s}\) per degree difference from the colder ambient. The heat pump has a COP that is \(50 \%\) that of a Carnot heat pump. If the ambient temperature can fall to \(-10 \mathrm{~F}\) at night, would you recommend this heat pump to the explorers?

An experimental power plant outputs \(130 \mathrm{MW}\) of electrical power. It uses a supply of \(1200 \mathrm{MW}\) from a geothermal source and rejects energy to the atmosphere. Find the power to the air and how much air should be flowed to the cooling tower \((\mathrm{kg} / \mathrm{s})\) if its temperature cannot be increased more than \(12^{\circ} \mathrm{C}\).

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