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Chapter 1: Problem 57

What is a temperature of \(-5^{\circ} \mathrm{C}\) in degrees Kelvin?

Short Answer

Expert verified
The temperature is 268.15 K.

Step by step solution

01

Understand the Conversion Formula

To convert a temperature from degrees Celsius to degrees Kelvin, we use the formula: \[ K = C + 273.15 \]where \(K\) is the temperature in Kelvin and \(C\) is the temperature in degrees Celsius.
02

Insert the Celsius Temperature into the Formula

Given temperature in Celsius is \(-5^{\circ} C\), so we substitute \(-5\) for \(C\) in the formula:\[ K = -5 + 273.15 \]
03

Calculate the Temperature in Kelvin

Perform the arithmetic operation: \[ K = -5 + 273.15 = 268.15 \]
04

Final Result

Therefore, the temperature \(-5^{\circ} C\) equals \(268.15\, K\) in degrees Kelvin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Celsius to Kelvin
When converting temperatures from Celsius to Kelvin, the process involves a straightforward calculation. This is because Kelvin, an absolute temperature scale, simply starts at absolute zero, which is the coldest possible temperature and equates to -273.15 degrees Celsius. Thus, to convert Celsius to Kelvin, you add 273.15.
For example, if you have a temperature of -5掳 Celsius, the conversion to Kelvin is done by adding 273.15:
  • Start with your Celsius temperature: -5掳 C
  • Add 273.15: \[K = -5 + 273.15 \]
  • This results in 268.15 Kelvin.
Using this method, you can convert any Celsius temperature to Kelvin easily.
Kelvin scale
The Kelvin scale is a temperature scale that is widely used in scientific studies and engineering fields. Named after the Scottish scientist William Thomson, 1st Baron Kelvin, it uses absolute zero as its null point. Absolute zero (0 K) is the point at which all molecular motion ceases.
In contrast with the Celsius or Fahrenheit scales, which use increments (or degrees), the Kelvin scale progresses in kelvins, which are direct measurements of thermal energy. This means that it starts with absolute zero:
  • 0 K represents absolute zero, the coldest possible temperature.
  • 273.15 K corresponds to the freezing point of water.
  • 373.15 K represents the boiling point of water.
Unlike degrees Celsius and Fahrenheit, Kelvin does not use the degree symbol (掳). This distinction emphasizes its basis in absolute measurements.
Temperature formula
The formula for converting Celsius to Kelvin is straightforward. It's helpful for scientific calculations where precise temperature measurements are crucial.
This conversion formula is:\[K = C + 273.15\]where:
  • \(K\) is the temperature in Kelvin
  • \(C\) is the temperature in degrees Celsius
This formula reflects that the Kelvin and Celsius scales are directly related, being offset by exactly 273.15 units. With this formula, any temperature given in Celsius can be calculated directly into its Kelvin equivalent by simply adding 273.15 to the Celsius value.
Understanding this formula is essential, especially when dealing with scientific environments where accuracy is critical, as it ensures consistent and accurate temperature readings across all scientific fields.

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Most popular questions from this chapter

A \(5-\mathrm{m}^{3}\) container is filled with \(900 \mathrm{~kg}\) of granite (density of \(2400 \mathrm{~kg} / \mathrm{m}^{3}\) ). The rest of the volume is air, with density equal to \(1.15 \mathrm{~kg} / \mathrm{m}^{3}\). Find the mass of air and the overall (average) specific volume.

An absolute pressure gauge attached to a steel cylinder shows \(135 \mathrm{kPa}\). We want to attach a manometer using liquid water on a day that \(P_{\mathrm{atm}}=101 \mathrm{kPa}\). How high a fluid level difference must we plan for?

A container ship is \(240 \mathrm{~m}\) long and \(22 \mathrm{~m}\) wide. Assume that the shape is like a rectangular box. How much mass does the ship carry as load if it is \(10 \mathrm{~m}\) down in the water and the mass of the ship itself is 30000 tonnes?

A car of mass \(4000 \mathrm{lbm}\) travels with a velocity of \(60 \mathrm{mi} / \mathrm{h}\). Find the kinetic energy. How high should the car be lifted in the standard gravitational field to have a potential energy that equals the kinetic energy?

A 5000-kg elephant has a cross-sectional area of \(0.02 \mathrm{~m}^{2}\) on each foot. Assuming an even distribution, what is the pressure under its feet?
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