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In February 1955, a paratrooper fell \(370 \mathrm{~m}\) from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was \(56 \mathrm{~m} / \mathrm{s}\) (terminal speed), that his mass (including gear) was \(85 \mathrm{~kg}\), and that the magnitude of the force on him from the snow was at the survivable limit of \(1.2 \times 10^{5} \mathrm{~N}\). What are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?

Short Answer

Expert verified
The minimum depth of snow is approximately 1.11 meters, and the impulse is 4800 Ns.

Step by step solution

01

Calculate Stopping Time

To find the minimum depth of snow, we first need to determine the stopping time. The stopping force is given as the survivable limit, which is equal to the mass times the deceleration. Using the formula \(F = ma\), we can find the deceleration \(a\) by rearranging it: \[ a = \frac{F}{m} = \frac{1.2 \times 10^{5} \, \text{N}}{85 \, \text{kg}} \approx 1411.76 \, \text{m/s}^2 \].
02

Determine Stopping Time

Using the initial velocity and the calculated deceleration, apply the formula \(v = u + at\) where \(v = 0\) (final velocity), \(u = 56 \, \text{m/s}\) (initial velocity), and \(a = -1411.76 \, \text{m/s}^2\) (since it's deceleration). Solve for \(t\): \[ 0 = 56 - 1411.76t \Rightarrow t \approx 0.04 \, s \].
03

Calculate Minimum Depth of Snow

The depth of snow needed can be found using the relationship \(s = ut + \frac{1}{2}at^2\). Substituting \(u = 56 \, \text{m/s}\), \(a = -1411.76 \, \text{m/s}^2\), and \(t = 0.04 \, s\), we get: \[ s = 56 \times 0.04 + \frac{1}{2}(-1411.76)(0.04)^2 \approx 2.24 - 1.13 \approx 1.11 \, m \].
04

Calculate Impulse

Impulse is the change in momentum, and can be calculated as the product of the force and the stopping time. Using the force \(F = 1.2 \times 10^5 \, \text{N}\) and \(t = 0.04 \, s\), \[ \text{Impulse} = Ft = 1.2 \times 10^5 \times 0.04 = 4800 \, \text{Ns} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the causes of this motion. In the context of our exercise, kinematics helps us understand how the paratrooper stopped safely after falling into snow.

We often deal with quantities such as displacement, velocity, and acceleration. Displacement is the change in position of the object, while velocity is the rate of change of displacement. Acceleration is the rate at which velocity changes over time.

In our scenario, the initial velocity of the paratrooper upon impacting the snow is crucial to determine how safely he can come to a stop. We use kinematic equations like:
  • \(v = u + at\) to relate final velocity \(v\), initial velocity \(u\), acceleration \(a\), and time \(t\).
  • \(s = ut + \frac{1}{2}at^2\) to find the displacement within a given time period.
These formulas help calculate the minimum depth needed for the snow to stop him, ensuring he reaches zero velocity gently.
Impulse
Impulse in physics is defined as the product of force and the time duration over which the force acts. It is expressed as:
  • \( \text{Impulse} = Ft \)
Impulse is crucial because it relates to the change in momentum of an object.

Momentum, on the other hand, is the product of an object's mass and velocity. When dealing with impacts or sudden changes in motion, understanding impulse helps us compute how quickly an object can stop.

In the given problem, the impulse describes how the force of the snow stops the paratrooper. The magnitude indicates the total momentum change caused by the impact. With a force applied to stop the paratrooper safely within \(0.04\) seconds, the impulse tells us that this was sufficient to bring his initial downward momentum to zero.
Newton's Laws
Newton's Laws of Motion are fundamental principles used to understand motion and forces. In our problem, these laws guide us in identifying the forces acting on the paratrooper as he comes to a stop.

**Newton's First Law:** Often known as the law of inertia, states that an object will remain in uniform motion unless acted upon by an external force. For our paratrooper, initially moving at terminal velocity, this means he would have continued falling without the stopping force from the snow.

**Newton's Second Law:** Links force, mass, and acceleration with the equation:
  • \(F = ma\)
From this, we deduced the deceleration required for a safe landing, ensuring the stopping force doesn’t exceed the limit that would cause damage.

**Newton's Third Law:** States that for every action, there's an equal and opposite reaction. The snow applied an upward force on the paratrooper equal in magnitude to the force he exerted on it.

These laws are interwoven in the calculations of stopping time, force, and impulse, to ensure a comprehensive understanding of the motion and forces involved in this survivable fall.

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