/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 117 A \(20 \mathrm{~kg}\) block on a... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(20 \mathrm{~kg}\) block on a horizontal surface is attached to a horizontal spring of spring constant \(k=4.0 \mathrm{kN} / \mathrm{m}\). The block is pulled to the right so that the spring is stretched \(10 \mathrm{~cm}\) beyond its relaxed length, and the block is then released from rest. The frictional force between the sliding block and the surface has a magnitude of \(80 \mathrm{~N}\). (a) What is the kinetic energy of the block when it has moved \(2.0\) \(\mathrm{cm}\) from its point of release? (b) What is the kinetic energy of the block when it first slides back through the point at which the spring is relaxed? (c) What is the maximum kinetic energy attained by the block as it slides from its point of release to the point at which the spring is relaxed?

Short Answer

Expert verified
(a) 5.6 J; (b) 12 J; (c) 18.4 J

Step by step solution

01

Calculate Initial Potential Energy

The initial potential energy of the spring, when stretched by 10 cm, is given by the formula for spring potential energy: \[ U_i = \frac{1}{2} k x^2 \]where \( k = 4000 \mathrm{~N/m} \) and \( x = 0.1 \mathrm{~m} \) (10 cm in meters).Substituting the given values:\[ U_i = \frac{1}{2} \times 4000 \times (0.1)^2 = 20 \text{ Joules} \]
02

Calculate Potential Energy After Moving 2 cm

Next, calculate the potential energy after the block has moved 2 cm (from 10 cm stretch to 8 cm stretch). The new displacement, \( x' = 0.08 \mathrm{~m} \).\[ U_f = \frac{1}{2} k (x')^2 = \frac{1}{2} \times 4000 \times (0.08)^2 = 12.8 \text{ Joules} \]
03

Calculate Work Done by Friction over 2 cm

The work done by friction as the block moves 2 cm is calculated using:\[ W_f = f \cdot d \]where \( f = 80 \mathrm{~N} \) (frictional force) and \( d = 0.02 \mathrm{~m} \) (distance moved).\[ W_f = 80 \times 0.02 = 1.6 \text{ Joules} \]
04

Calculate Kinetic Energy after Moving 2 cm

Using energy conservation, the initial total mechanical energy minus the work done by friction gives the kinetic energy after moving 2 cm:\[ E_i = U_i \]\[ E_f = K_f + U_f + W_f \]\[ 20 = K_f + 12.8 + 1.6 \]Solving for \( K_f \):\[ K_f = 20 - 12.8 - 1.6 = 5.6 \text{ Joules} \]
05

Calculate Potential Energy at the Relaxed Point

At the relaxed point, the potential energy is zero: \[ U_{relaxed} = 0 \text{ Joules} \]
06

Calculate Total Work Done by Friction to Relaxed Point

The block moves 10 cm from initial to the relaxed point. Work done by friction:\[ W' = f \cdot d' = 80 \times 0.1 = 8 \text{ Joules} \]
07

Calculate Kinetic Energy at the Relaxed Point

At the relaxed point, using energy conservation:\[ E_i = K_{relaxed} + U_{relaxed} + W' \]\[ 20 = K_{relaxed} + 0 + 8 \]\[ K_{relaxed} = 20 - 8 = 12 \text{ Joules} \]
08

Calculate Maximum Kinetic Energy within 10 cm

The maximum kinetic energy occurs just before the influence of friction reduces it. This is at the point of least potential energy while still considering the initial motion of 10 cm:\[ K_{max} = E_i - W_f = 20 - 1.6 = 18.4 \text{ Joules} \]
09

Answer the Given Questions

(a) After moving 2 cm from release: Kinetic energy is 5.6 Joules. (b) Upon reaching the relaxed point: Kinetic energy is 12 Joules. (c) Maximum kinetic energy in initial 10 cm: 18.4 Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential Energy is the energy stored in an object due to its position or configuration. In the context of the exercise, we are looking at the potential energy stored in a spring. When a spring is stretched or compressed, it has potential energy because it can perform work if allowed to return to its relaxed, or equilibrium, position.

The spring constant, denoted as \(k\), indicates how stiff the spring is. A larger \(k\) means a stiffer spring, which requires more force to stretch or compress by a given length. The potential energy \(U\) in a spring is given by:
  • \( U = \frac{1}{2} k x^2 \)
where \(x\) is the displacement from the spring's relaxed length. In this exercise, the spring is stretched by 10 cm initially, which equates to 20 Joules of potential energy.

As the block moves, this energy changes as the spring shifts back to its relaxed position. Calculating potential energy at each stage helps determine the changes in kinetic energy and the effects of work done by other forces.
Work Done by Friction
Friction is a force that opposes motion, converting kinetic energy into thermal energy. The work done by friction is a vital factor in determining the net energy available to convert into kinetic energy.

In this exercise, the block experiences a constant frictional force of 80 N as it slides. The work done by this frictional force \(W_f\) over a distance \(d\) is calculated using:
  • \( W_f = f \cdot d \)
where \(f\) is the frictional force, and \(d\) is the distance moved by the block.

As the block moves 2 cm from its initial position, the work done by friction is 1.6 Joules. When the block returns to the relaxed position of the spring, the total work done by friction amounts to 8 Joules. This reduction in mechanical energy due to friction affects the amount of kinetic energy the block possesses at various points in its motion.
Spring Constant
The spring constant \(k\) is a measure of a spring’s stiffness, indicating the force needed to stretch or compress the spring by one unit of length. It reflects the spring's ability to store potential energy. The units of the spring constant are typically Newtons per meter (N/m).

In the given exercise, the spring constant \(k\) is 4000 N/m. This indicates a rather stiff spring, requiring significant force to displace it. The stiffness of the spring directly influences the potential energy stored or released during compression or extension.
  • A higher spring constant means the spring stores more energy for a given displacement.
  • Determining \(k\) allows us to calculate potential energy and relate it to kinetic energy and work done by other forces.
Understanding the spring constant is essential to solving problems involving forces and energy transformations in spring-related exercises. It helps clarify how energy is transferred between potential and kinetic forms in these systems.

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