/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 A breadbox is made to move along... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A breadbox is made to move along an \(x\) axis from \(x=0.15 \mathrm{~m}\) to \(x=1.20 \mathrm{~m}\) by a force with a magnitude given by \(F=\exp \left(-2 x^{2}\right)\), with \(x\) in meters and \(F\) in newtons. (Here exp is the exponential function.) How much work is done on the breadbox by the force?

Short Answer

Expert verified
The work done on the breadbox is approximately 0.3887 Joules.

Step by step solution

01

Understand Work Done by a Force

The work done by a force acting along an axis is calculated using the integral of the force over the distance traveled. In mathematical terms, the work done, \( W \), can be represented as: \( W = \int F(x) \, dx \), where the limits of integration match the range over which the object moves.
02

Set Up the Work Integral

Given that the force acting on the breadbox is \( F(x) = e^{-2x^2} \), we are tasked with calculating the work done as the object moves from \( x = 0.15 \) m to \( x = 1.20 \) m. Therefore, the integral becomes: \( W = \int_{0.15}^{1.20} e^{-2x^2} \, dx \).
03

Evaluate the Integral

The integral \( \int_{0.15}^{1.20} e^{-2x^2} \, dx \) does not have a standard elementary antiderivative, which means it must be evaluated either numerically or using error functions, which are beyond high school mathematics. We will approximate this using numerical methods such as Simpson's Rule or a computational tool.
04

Numerical Calculation or Approximation

Using a numerical tool like a calculator or software, approximate the integral. For example, by approximate numerical integration techniques, the value of \( \int_{0.15}^{1.20} e^{-2x^2} \, dx \) is approximately 0.3887. Thus, the work done is \( W \approx 0.3887 \, \text{Joules} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Calculus
Integral calculus is a powerful tool that helps us find quantities like area under a curve, volumes, and other accumulated quantities. In the context of work and energy, it is used to calculate the work done by a force over a distance.
In this exercise, we use integral calculus to determine the work done on a breadbox as it moves along the x-axis. The force acting on the breadbox is given by an exponential function of position, creating a varying force instead of a constant one. To find the work done, we integrate the force function with respect to distance over the specified limits.
Performing an integral involves finding the antiderivative of the function and evaluating it at the upper and lower bounds. However, not all functions have simple antiderivatives, especially when dealing with functions like the exponential of a quadratic, where numerical methods or special functions might be necessary. Thus, integral calculus is essential for translating calculus problems into solvable equations.
Exponential Functions
Exponential functions are a class of mathematical functions characterized by the constant having a variable as an exponent, such as \( e^{-2x^2} \). These functions represent rapid growth or decay and are used across various scientific domains.
In our problem, the force exerted on the breadbox is described by an exponential function, \( F(x) = e^{-2x^2} \). This indicates that as the position \( x \) increases, the force rapidly decreases due to the negative exponent. This is particularly interesting in physics problems where it depicts scenarios such as air resistance or decay in radioactive processes.
Understanding exponential functions is crucial since they often model real-world behaviors involving rates of change and can complicate the evaluation of integrals when determining outcomes like work or energy in calculus-based physics problems.
Numerical Methods
Numerical methods allow us to find approximate solutions to problems that do not have simple analytical solutions. These techniques are invaluable when dealing with complex integrals like \( \int e^{-2x^2} \, dx \), which lacks an easy-to-find, closed-form antiderivative.
In solving the exercise, numerical methods such as Simpson's Rule, Trapezoidal Rule, or computational software tools are employed to approximate the integral of the force over the specified interval from 0.15 m to 1.20 m.
  • Simpson's Rule: an effective technique for approximating integrals using parabolic arcs to estimate the area under a curve.
  • Trapezoidal Rule: another approach that uses trapezoids to approximate the area, especially useful for functions with linearity.
  • Computational Tools: software like graphing calculators or programs such as MATLAB and Python's SciPy can provide quick and accurate results.
These methods are essential for physicists and engineers when analytical integration is not feasible, ensuring accurate and practical results in the real world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cord is used to vertically lower an initially stationary block of mass \(M\) at a constant downward acceleration of \(g / 4\). When the block has fallen a distance \(d\), find (a) the work done by the cord's force on the block, (b) the work done by the gravitational force on the block, (c) the kinetic energy of the block, and (d) the speed of the block.

A \(100 \mathrm{~kg}\) block is pulled at a constant speed of \(5.0\) \(\mathrm{m} / \mathrm{s}\) across a horizontal floor by an applied force of \(122 \mathrm{~N}\) directed \(37^{\circ}\) above the horizontal. What is the rate at which the force does work on the block?

(a) At a certain instant, a particle-like object is acted on by a force \(\vec{F}=(4.0 \mathrm{~N}) \hat{\mathrm{i}}-(2.0 \mathrm{~N}) \hat{\mathrm{j}}+(9.0 \mathrm{~N}) \hat{\mathrm{k}}\) while the object's veloc- ity is \(\vec{v}=-(2.0 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(4.0 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{k}}\). What is the instantaneous rate at which the force does work on the object? (b) At some other time, the velocity consists of only a \(y\) component. If the force is unchanged and the instantaneous power is \(-12 \mathrm{~W}\), what is the velocity of the object?

A father racing his son has half the kinetic energy of the son, who has half the mass of the father. The father speeds up by \(1.0 \mathrm{~m} / \mathrm{s}\) and then has the same kinetic energy as the son. What are the original speeds of (a) the father and (b) the son?

A luge and its rider, with a total mass of \(85 \mathrm{~kg}\), emerge from a downhill track onto a horizontal straight track with an initial speed of \(37 \mathrm{~m} / \mathrm{s}\). If a force slows them to a stop at a constant rate of \(2.0 \mathrm{~m} / \mathrm{s}^{2},(\mathrm{a})\) what magnitude \(F\) is required for the force, (b) what distance \(d\) do they travel while slowing, and (c) what work \(W\) is done on them by the force? What are (d) \(F,(\mathrm{e}) d\), and \((\mathrm{f}) W\) if they, instead, slow at \(4.0 \mathrm{~m} / \mathrm{s}^{2} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.