/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 74 A particle moves along a stra... [FREE SOLUTION] | 91Ó°ÊÓ

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74 A particle moves along a straight path through displacement \(\vec{d}=(8 \mathrm{~m}) \hat{\mathrm{i}}+c \hat{\mathrm{j}}\) while force \(\vec{F}=(2 \mathrm{~N}) \hat{\mathrm{i}}-(4 \mathrm{~N}) \hat{\mathrm{j}}\) acts on it. (Other forces also act on the particle.) What is the value of \(c\) if the work done by \(\vec{F}\) on the particle is (a) zero, (b) positive, and (c) negative?

Short Answer

Expert verified
(a) \(c = 4\), (b) \(c < 4\), (c) \(c > 4\).

Step by step solution

01

Understanding the Work Done Formula

The work done by a force on a particle is calculated using the dot product of the force vector and the displacement vector. The formula for work is: \[ W = \vec{F} \cdot \vec{d} = F_x \cdot d_x + F_y \cdot d_y \]where \(F_x\) and \(F_y\) are the components of the force, and \(d_x\) and \(d_y\) are the components of the displacement.
02

Substitute the Given Values

Substitute the given components into the work formula: \[ \vec{F} = (2\,\mathrm{N}) \hat{\mathrm{i}} -(4\,\mathrm{N}) \hat{\mathrm{j}} \]\[ \vec{d} = (8\,\mathrm{m}) \hat{\mathrm{i}} + c \hat{\mathrm{j}} \]The work done is:\[ W = (2)(8) + (-4)(c) \] which simplifies to:\[ W = 16 - 4c \]
03

Solving for Zero Work Done

To make the work done zero, set:\[ 16 - 4c = 0 \]Solving for \(c\):\[ 16 = 4c \]\[ c = \frac{16}{4} = 4 \]
04

Solving for Positive Work Done

To make the work done positive, ensure that:\[ 16 - 4c > 0 \]Rearranging gives:\[ 16 > 4c \]\[ c < 4 \]
05

Solving for Negative Work Done

To make the work done negative, ensure that:\[ 16 - 4c < 0 \]Rearranging gives:\[ 16 < 4c \]\[ c > 4 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product is a method for multiplying two vectors, resulting in a scalar (a single number). It's frequently used in physics, especially when analyzing work done by a force. To compute the dot product, multiply the corresponding components of each vector and then sum these products. For two vectors \( \vec{A} = (A_x, A_y) \) and \( \vec{B} = (B_x, B_y) \), the dot product is calculated as follows:\[ \vec{A} \cdot \vec{B} = A_x \cdot B_x + A_y \cdot B_y \]This formula captures how much one vector extends in the direction of the other. If vectors are perpendicular, their dot product is zero, illustrating no overlap in direction, which can determine the work done by forces.
Displacement
Displacement is a vector quantity that refers to an object's overall change in position. Unlike distance, which is a scalar and only considers the path length, displacement considers direction as well.- **Vector Components**: Displacement is often represented by its components, such as \( \vec{d} = (d_x, d_y) \), illustrating how it extends in each of the coordinate directions.- **In Calculations**: In this exercise, displacement \( \vec{d} = (8\mathrm{~m}) \hat{\mathrm{i}} + c \hat{\mathrm{j}} \) shows it moves 8 meters in the x direction and "c" meters in the y direction.Understanding displacement components helps in visualizing movement and calculating work done by forces acting on a moving particle.
Force
Force is a vector that represents a push or pull acting on an object, affecting its motion. It has both magnitude and direction, typically expressed in Newtons (N).- **Components of Force**: Similar to displacement, force is often broken down into its components. For example, \( \vec{F} = (2\mathrm{~N}) \hat{\mathrm{i}} - (4\mathrm{~N}) \hat{\mathrm{j}} \) implies a force is applied 2 N in the positive x direction and 4 N in the negative y direction.- **Interaction with Objects**: Force influences how objects accelerate, direction they move, or how much work is completed.In problems, recognizing how force components align with movement helps determine the work done on an object, based on their orientation and magnitude.
Work Done
Work done is the measure of energy transfer that occurs when an object is moved over a distance by a force. It's calculated using the dot product of force and displacement vectors, reflecting the component of force acting in the direction of movement.- **Formula**: The general formula for work done \( W \) is: \[ W = \vec{F} \cdot \vec{d} = F_x \cdot d_x + F_y \cdot d_y \] - **Positive, Negative, and Zero Work**: - *Positive Work*: Occurs if the force component in the direction of displacement contributes energy to the object (when \( 16 - 4c > 0 \)). - *Negative Work*: Happens when the force component withdraws energy from moving the object (when \( 16 - 4c < 0 \)). - *Zero Work*: Arises when the force does not contribute to motion in its direction (when \( 16 - 4c = 0 \)).Understanding how work ties together force and displacement simplifies analyzing energy transformations in mechanical contexts.

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Most popular questions from this chapter

A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift is performed in three stages, each requiring a vertical distance of \(10.0 \mathrm{~m}\) : (a) the initially stationary spelunker is accelerated to a speed of \(5.00 \mathrm{~m} / \mathrm{s} ;(\mathrm{b})\) he is then lifted at the constant speed of \(5.00\) \(\mathrm{m} / \mathrm{s} ;\) (c) finally he is decelerated to zero speed. How much work is done on the \(80.0 \mathrm{~kg}\) rescuee by the force lifting him during each stage?

A \(100 \mathrm{~kg}\) block is pulled at a constant speed of \(5.0\) \(\mathrm{m} / \mathrm{s}\) across a horizontal floor by an applied force of \(122 \mathrm{~N}\) directed \(37^{\circ}\) above the horizontal. What is the rate at which the force does work on the block?

An explosion at ground level leaves a crater with a diameter that is proportional to the energy of the explosion raised to the \(\frac{1}{3}\) power; an explosion of 1 megaton of TNT leaves a crater with a \(1 \mathrm{~km}\) diameter. Below Lake Huron in Michigan there appears to be an ancient impact crater with a \(50 \mathrm{~km}\) diameter. What was the kinetic energy associated with that impact, in terms of (a) megatons of TNT (1 megaton yields \(\left.4.2 \times 10^{15} \mathrm{~J}\right)\) and (b) Hiroshima bomb equivalents (13 kilotons of TNT each)? (Ancient meteorite or comet impacts may have significantly altered Earth's climate and contributed to the extinction of the dinosaurs and other life-forms.)

If a Saturn \(V\) rocket with an Apollo spacecraft attached had a combined mass of \(2.9 \times 10^{5} \mathrm{~kg}\) and reached a speed of \(11.2 \mathrm{~km} / \mathrm{s}\), how much kinetic energy would it then have?

A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the child from the mother is \(100 \mathrm{~N}\) up the slide, the child's kinetic energy increases by \(30 \mathrm{~J}\) as she moves down the slide a distance of \(1.8 \mathrm{~m}\). (a) How much work is done on the child by the gravitational force during the \(1.8 \mathrm{~m}\) descent? (b) If the child is not restrained by her mother, how much will the child's kinetic energy increase as she comes down the slide that same distance of \(1.8 \mathrm{~m} ?\)

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