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While two forces act on it, a particle is to move at the constant velocity \(\vec{v}=(3 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}-(4 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}} .\) One of the forces is \(\vec{F}_{1}=(2 \mathrm{~N}) \hat{\mathrm{i}}+(-6 \mathrm{~N}) \hat{\mathrm{j}}\) What is the other force?

Short Answer

Expert verified
The other force is \((-2 \text{ N}) \hat{\mathbf{i}} + (6 \text{ N}) \hat{\mathbf{j}}\).

Step by step solution

01

Understand the Problem

The problem states that a particle is moving with a constant velocity under the influence of two forces. Given the force \( \vec{F}_1 \) and the velocity \( \vec{v} \), we need to find the other force acting on the particle.
02

Apply Newton's First Law

Newton's First Law says that if an object is moving at a constant velocity, the net force acting on it is zero. Therefore, the sum of all forces acting on the particle is zero: \( \vec{F}_{net} = \vec{F}_1 + \vec{F}_2 = 0 \).
03

Solve for the Other Force

Since \( \vec{F}_{net} = 0 \), we have \( \vec{F}_2 = -\vec{F}_1 \). Using the given \( \vec{F}_1 = (2 \text{ N}) \hat{\mathbf{i}} + (-6 \text{ N}) \hat{\mathbf{j}} \), we find \( \vec{F}_2 = -(2 \text{ N}) \hat{\mathbf{i}} - (-6 \text{ N}) \hat{\mathbf{j}} = (-2 \text{ N}) \hat{\mathbf{i}} + (6 \text{ N}) \hat{\mathbf{j}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Constant Velocity
When an object moves with a constant velocity, it means that the speed and direction of the object are not changing over time. A constant velocity implies that the object travels equal distances in equal time intervals. Therefore, there are no accelerations involved, and the forces balanced in such a way that the object continues with its same speed and in the same direction.
This concept is directly tied to Newton's First Law of Motion, which states that an object at rest remains at rest, and an object in motion continues at a constant velocity unless acted upon by a net external force. This forms a basis for understanding the other concepts discussed here.
So, whenever you see a problem stating that an object or a particle is moving with constant velocity, make sure to first think about the balance of forces acting on it. This helps in conceptualizing the situation correctly even before getting into calculations.
Decoding Net Force
Net force is a crucial concept when dealing with Newton's Laws. It represents the combined effect of all forces acting on an object. The net force can alter the object's motion, either changing its speed or direction, or both.
To calculate the net force, you simply sum up all the individual vectors of forces acting on the object. In the scenario where the velocity is constant, like our exercise, it means that the total or net force is zero. This is because unbalanced forces would cause the object to accelerate, thereby changing its velocity.
Therefore, the key to problems involving constant velocity and net force is recognizing that if the object remains at constant velocity, then:
  • The sum of all acting forces equals zero.
  • Forces need to balance out perfectly in both magnitude and direction.
By finding one of the forces, as given in some problems, you can easily calculate any unknown forces needed to achieve this balance.
The Role of Vector Components
Vectors are essential in physics because they give us information about both the magnitude and direction of physical quantities like force and velocity. In problems like the one discussed here, vectors are presented in component form, using i and j to denote the x and y directions, respectively.
The key to solving these problems is understanding how to work with these vector components. The components tell you how much of a vector is directed along each axis. For example, a vector expressed as y = a\( \hat i\) + b\( \hat j\) means the vector is a combination of 'a' units in the x-direction and 'b' units in the y-direction.
To solve vector problems, especially those involving forces, it's often necessary to:
  • Break down vectors into their components.
  • Perform vector addition or subtraction as needed.
  • Ensure that the sum of all components is zero when the net force is zero (as in constant velocity scenarios).
By managing vector components correctly, you can effectively solve for all parts of forces involved, which is crucial for understanding overall motion and designing real-world applications.

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Most popular questions from this chapter

A block with a weight of \(3.0 \mathrm{~N}\) is at rest on a horizontal surface. A \(1.0 \mathrm{~N}\) upward force is applied to the block by means of an attached vertical string. What are the (a) magnitude and (b) direction of the force of the block on the horizontal surface?

Using a rope that will snap if the tension in it exceeds \(387 \mathrm{~N}\), you need to lower a bundle of old roofing material weighing \(449 \mathrm{~N}\) from a point \(6.1 \mathrm{~m}\) above the ground. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping? (b) At that acceleration, with what speed would the bundle hit the ground?

A certain force gives an object of mass \(m_{1}\) an acceleration of \(12.0 \mathrm{~m} / \mathrm{s}^{2}\) and an object of mass \(m_{2}\) an acceleration of \(3.30\) \(\mathrm{m} / \mathrm{s}^{2}\). What acceleration would the force give to an object of mass (a) \(m_{2}-m_{1}\) and (b) \(m_{2}+m_{1}\) ?

A spaceship lifts off vertically from the Moon, where \(g=1.6\) \(\mathrm{m} / \mathrm{s}^{2}\). If the ship has an upward acceleration of \(1.0 \mathrm{~m} / \mathrm{s}^{2}\) as it lifts off, what is the magnitude of the force exerted by the ship on its pilot, who weighs \(735 \mathrm{~N}\) on Earth?

A customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of a \(y\) axis with an acceleration magnitude of \(1.24 g\), with \(g=\) \(9.80 \mathrm{~m} / \mathrm{s}^{2}\), A \(0.567 \mathrm{~g}\) coin rests on the customer's knee. Once the motion begins and in unit-vector notation, what is the coin's acceleration relative to (a) the ground and (b) the customer? (c) How long does the coin take to reach the compartment ceiling, \(2.20 \mathrm{~m}\) above the knee? In unit-vector notation, what are (d) the actual force on the coin and (c) the apparent force according to the customer's measure of the coin's acceleration?

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