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A person walks up a stalled 15 -m-long escalator in \(90 \mathrm{~s}\). When standing on the same escalator, now moving, the person is carried up in \(60 \mathrm{~s}\). How much time would it take that person to walk up the moving escalator? Does the answer depend on the length of the escalator?

Short Answer

Expert verified
It takes 36 seconds. The answer does not depend on the escalator's length.

Step by step solution

01

Define Variables and Constants

Let the speed of the person walking be \( v_p \) and the speed of the escalator when moving be \( v_e \). The length of the escalator is \( L = 15 \) meters.The time it takes to walk up the escalator when it is stalled (not moving) is \( t_p = 90 \) seconds, and the time to be carried up by the moving escalator without walking is \( t_e = 60 \) seconds.
02

Set Up Equations for Each Scenario

From the given information:1. When the escalator is stalled, the person walks the entire length with a speed of \( v_p \). Thus, \[ L = v_p \cdot t_p \Rightarrow v_p = \frac{L}{t_p} = \frac{15}{90} \text{ m/s} \] 2. When standing on the moving escalator, the person is carried the same length with a speed of \( v_e \). Thus, \[ L = v_e \cdot t_e \Rightarrow v_e = \frac{L}{t_e} = \frac{15}{60} \text{ m/s} \]
03

Combine Speeds for Person Walking on Moving Escalator

When the person walks up the moving escalator, their effective speed is the sum of the person's speed and the escalator's speed: \( v_{ ext{combined}} = v_p + v_e \). Substitute the expressions for \( v_p \) and \( v_e \):\[ v_{ ext{combined}} = \frac{15}{90} + \frac{15}{60} = \frac{1}{6} + \frac{1}{4} \text{ m/s} \]Find a common denominator to add these fractions:\[ v_{ ext{combined}} = \frac{2}{12} + \frac{3}{12} = \frac{5}{12} \text{ m/s} \]
04

Calculate Time to Walk Up Moving Escalator

Using the effective speed \( v_{\text{combined}} \), we calculate the time \( t_{\text{combined}} \) it takes to walk up the moving escalator:\[ L = v_{\text{combined}} \cdot t_{\text{combined}} \Rightarrow t_{\text{combined}} = \frac{L}{v_{\text{combined}}} = \frac{15}{\frac{5}{12}} \]Simplify the expression:\[ t_{\text{combined}} = 15 \times \frac{12}{5} = 36 \text{ seconds} \]
05

Assess Dependence on Escalator Length

The solution involves fractions of the length \( L \), indicating the approach is based on ratios. These ratios only depend on the times given (90s and 60s). The time calculated (36 seconds) is independent of the actual length, as it cancels out in the solution process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
In physics, relative velocity refers to the velocity of an object as observed from a certain frame of reference. It is crucial to understand how velocities add up, especially in problems involving multiple moving objects like an escalator and a person.
When considering relative velocity, think of it as how fast one object moves compared to another. For the person on the moving escalator, the total speed can be thought of as the sum of their walking speed and the escalator's speed. This combined velocity is then used to determine how quickly they move relative to the ground.
  • The concept of adding velocities is straightforward: if two velocities are in the same direction, they simply add.
  • This is often expressed mathematically as: \( v_{\text{combined}} = v_p + v_e \), which in this problem, shows the effective speed of the person walking on a moving escalator.
Understanding relative velocity helps in simplifying complex motion scenarios by reducing them to manageable problems.
Escalator Problem
Escalator problems typically involve finding out various time and speed relationships when an individual interacts with an escalator. The most common scenarios include walking on a stalled escalator versus a moving one or simply standing on the escalator as it moves.
In this particular problem, we encounter different situations, specifically:
  • The person walking up a non-moving or stalled escalator.
  • The person standing still while the escalator is moving.
  • The person walking on a moving escalator.
Each of these scenarios impacts the time it takes to reach the top. By understanding how the speeds of the person and escalator combine in both moving and non-moving scenarios, we can solve the problem using basic kinematic equations.
Time Calculation
Calculating time in these scenarios revolves around taking the known travel distance, speed, and solving the equation for time. Here, the crucial formula from kinematics to remember is:
  • Time = Distance / Speed

For example, when the person walks 15 meters up the stalled escalator in 90 seconds, their walking speed is calculated as \( v_p = \frac{L}{t_p} = \frac{15}{90} \) m/s. Similarly, the speed of the moving escalator is \( v_e = \frac{L}{t_e} = \frac{15}{60} \) m/s.
To calculate how much time it would take to walk up the moving escalator, we use the combined speed \( v_{\text{combined}} = \frac{5}{12} \) m/s, resulting in a much faster time to reach the top. This process involves straightforward substitution into the time formula to yield \( t_{\text{combined}} = 36 \) seconds.
Effective Speed
Effective speed combines different speeds to determine how fast something moves in a specific scenario. In the context of this problem, it is about how quickly a person walks up an escalator when both structures contribute motion.
Effective speed is calculated by simply adding up individual speeds when moving in the same direction. For the exercise:
  • The person's walking speed and the escalator's moving speed are combined.
  • Mathematically expressed as the sum \( v_{\text{combined}} = v_p + v_e \).
This concept shows how velocities, when aligned, produce an overall greater speed. It is this effective speed that is crucial for determining how quickly the person can walk up the moving escalator. Understanding effective speed allows us to approach problems involving multiple moving parts in a logical and systematic manner.

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