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A spaceship is moving away from Earth at speed \(0.20 \mathrm{c}\). A source on the rear of the ship emits light at wavelength \(450 \mathrm{~nm}\) according to someone on the ship. What (a) wavelength and (b) color (blue, green, yellow, or red) are detected by someone on Earth watching the ship?

Short Answer

Expert verified
The detected wavelength is approximately 551 nm and appears green.

Step by step solution

01

Identify the Problem

We need to calculate the wavelength of light detected from Earth when a spaceship recedes from us at a velocity of \(v = 0.20c\) and emits light at a wavelength of \( \lambda_s = 450 \text{ nm} \). This involves using the relativistic Doppler effect for light.
02

Use the Relativistic Doppler Shift Formula

The relativistic Doppler shift formula for light when the source is moving away is given by:\[\lambda_o = \lambda_s \sqrt{\frac{1 + \beta}{1 - \beta}}\]where \(\beta = \frac{v}{c}\). Substitute \(v = 0.20c\) into \(\beta\).
03

Calculate Beta

Evaluate \( \beta \):\[\beta = \frac{0.20c}{c} = 0.20\]
04

Calculate the Observed Wavelength

Substitute \(\lambda_s = 450 \text{ nm}\) and \(\beta = 0.20\) into the Doppler shift formula:\[\lambda_o = 450 \sqrt{\frac{1 + 0.20}{1 - 0.20}} \approx 450 \sqrt{\frac{1.20}{0.80}}\]Calculate the value inside the square root first:\[\sqrt{\frac{1.20}{0.80}} = \sqrt{1.5} \approx 1.2247\]Then multiply by \(450 \text{ nm} \):\[\lambda_o \approx 450 \times 1.2247 \approx 551 \text{ nm}\]
05

Determine the Color of the Detected Wavelength

The wavelength of 551 nm falls in the visible spectrum of light, which corresponds to green light. This is within the range typically defined for green as approximately 495–570 nm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Calculation
In physics, especially when dealing with light waves, calculating the observed wavelength is essential. The Doppler Effect is particularly important for understanding how wavelengths change based on the relative motion between a source and an observer. When a source moves away from an observer, the waves stretch, increasing the observed wavelength. This scenario is specifically described by the relativistic Doppler Effect.

The formula to calculate the observed wavelength (\( \lambda_o \)) when the source is moving away is:
  • \( \lambda_o = \lambda_s \sqrt{\frac{1 + \beta}{1 - \beta}} \)
where:
  • \( \lambda_s \) is the wavelength emitted by the source.
  • \( \beta = \frac{v}{c} \), with \( v \) being the velocity of the source relative to the observer and \( c \) the speed of light.
This formula helps calculate the apparent wavelength detected by an observer on Earth when a spaceship moving away emits light.

The given problem uses this formula to determine how the emission from a spaceship changes as it moves at a significant fraction of light speed.
Light Emission
Light emission is a fascinating process, particularly when considering how different observers perceive light emission events. These events occur when an object, such as a spaceship, emits photons at a specific wavelength. In physics, wavelength is the spatial period of a wave—the distance over which the wave's shape repeats.

In a stationary frame, light emitted at 450 nm appears as blue-violet, a part of the visible spectrum signifying a high-energy photon. However, relativistic speeds can significantly alter the appearance of this light due to the Doppler Effect. As the spaceship moves away from the observer, the frequency of this emitted light decreases, reflecting longer wavelengths.

The change in wavelength, or shift, is due to light's constant speed in a vacuum, emphasizing the relativistic nature of light and showcasing the effect of velocity on wave phenomena.
Visible Spectrum
The visible spectrum is a range of wavelengths associated with light that is visible to the human eye. This spectrum is part of the electromagnetic spectrum and includes wavelengths approximately from 380 nm to 750 nm. Each wavelength corresponds to a specific color, ranging from violet to red.

In the case of the spaceship problem, the emitted light at 450 nm falls within this spectrum, characterizing it as blue light initially. After applying the relativistic Doppler shift due to the spaceship's velocity, the observed wavelength becomes 551 nm.
This shift places the light in the green region of the visible spectrum.

The visible spectrum is crucial because it allows us to identify color changes due to shifts, helping us understand how motion impacts perceived light. This concept is not only important in academic exercises but also in real-world applications like astronomy and even radar technology.

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