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In a single-slit diffraction experiment, there is a minimum of intensity for orange light \((\lambda=600 \mathrm{~nm})\) and a minimum of intensity for blue- green light \((\lambda=500 \mathrm{~nm})\) at the same angle of \(1.00\) mrad. For what minimum slit width is this possible?

Short Answer

Expert verified
The minimum slit width is \(3.00 \text{ mm}\).

Step by step solution

01

Identify the Diffraction Condition

When light passes through a narrow slit, a diffraction pattern is formed and the condition for the minimum intensity (dark fringe) is given by the equation: \(a \sin \theta = m \lambda\), where \(a\) is the slit width, \(\theta\) is the angle of diffraction, \(m\) is the order of minimum (a non-zero integer), and \(\lambda\) is the wavelength of the light.
02

Apply the Condition for Both Wavelengths

For the orange light \((\lambda_1 = 600 \text{ nm})\), and the blue-green light \((\lambda_2 = 500 \text{ nm})\), both have a minimum at the same angle of \(\theta = 1.00 \text{ mrad}\). Using the condition: \(a \sin \theta = m_1 \lambda_1 = m_2 \lambda_2\).
03

Express Angle in Radians

Since the angle is already given as \(1.00 \text{ mrad}\), it can be directly used in the equation by noting that \(\sin \theta \approx \theta\) for small angles, hence \(\sin(1.00 \text{ mrad}) = 1.00 \times 10^{-3}\).
04

Solve for Slit Width in Terms of Wavelengths and Orders

With the condition that \(m_1 \lambda_1 = m_2 \lambda_2\), rearrange the expression to find the slit width \(a\) that satisfies:\[a = \frac{m_1 \lambda_1}{\sin \theta} = \frac{m_2 \lambda_2}{\sin \theta}\]. Since the minimum width occurs when \(m_1\) and \(m_2\) are the smallest integers that satisfy \(\frac{\lambda_1}{m_1} = \frac{\lambda_2}{m_2}\), then \(m_1 = 5\) and \(m_2 = 6\).
05

Calculate the Minimum Slit Width

Using \(m_1 = 5\) and \(\lambda_1 = 600 \text{ nm} = 600 \times 10^{-9} \text{ m}\), calculate the slit width \(a\):\[a = \frac{5 \times 600 \times 10^{-9}}{1.00 \times 10^{-3}} = 3.00 \times 10^{-3} \text{ m}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffraction Pattern
A diffraction pattern is the distinctive pattern formed when waves, such as light, encounter a small opening or obstacle and subsequently spread out or bend. In a single-slit diffraction experiment, light waves pass through a narrow slit and create a pattern of bright and dark regions on a screen. These regions are a result of the constructive and destructive interference of the light waves.

The central bright fringe is the most intense and widest part of the pattern, surrounded by symmetrical dark and bright fringes. The dark fringes, where little to no light is visible, are called minima. These occur where the light waves cancel each other out, which happens at specific angles determined by the slit width and the light's wavelength.
Wavelength of Light
The wavelength of light is a critical property that defines its color in the visible spectrum. Wavelength, usually denoted by the Greek letter lambda (\( \lambda \)), is the distance between consecutive peaks of a wave.

Different colors of light have different wavelengths; for example, orange light has a wavelength of about 600 nanometers (nm), while blue-green light is closer to 500 nanometers. These differences in wavelength are pivotal in understanding how they interact with a slit to form diffraction patterns.
  • The wavelength influences the angle and position of the fringes in a diffraction pattern.
  • Shorter wavelengths like blue-green light produce more closely spaced fringes compared to longer wavelengths like orange light.
Angle of Diffraction
The angle of diffraction, denoted as \( \theta \), is the angle at which light waves spread out after passing through the slit. Importantly, the angle of diffraction determines where dark and bright fringes appear in a diffraction pattern.

Mathematically, the angle of diffraction is involved in the equation relating the slit width (\( a \)), wavelength (\( \lambda \)), and order of the fringe (\( m \)):\[ a \sin \theta = m \lambda \]

When dealing with very small angles, as in this example with \( 1.00 \) milliradian, \( \sin \theta \approx \theta \) is a helpful approximation, simplifying calculations without significant loss of accuracy.
Dark Fringe
Dark fringes in a diffraction pattern are points of minimum intensity, occurring where destructive interference of the light waves happens. For single-slit diffraction, these are defined by the condition:\[a \sin \theta = m \lambda\]where \( m \) is a non-zero integer (representing the order of the minimum), \( a \) is the slit width, \( \lambda \) is the wavelength of light, and \( \theta \) is the angle of diffraction.

Dark fringes are crucial for calculating the slit width in diffraction experiments. When different wavelengths produce a dark fringe at the same angle, it indicates a specific relationship between the slit width and the wavelengths. In this problem, both orange and blue-green lights create a dark fringe at the same angle, ensuring their conditions align for some integer values \( m_1 \) and \( m_2 \). By finding the simplest integer ratio between their wavelengths, we can determine the minimum slit width.

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Most popular questions from this chapter

A diffraction grating has 200 lines \(/ \mathrm{mm}\). Light consisting of a continuous range of wavelengths between \(550 \mathrm{~nm}\) and \(700 \mathrm{~nm}\) is incident perpendicularly on the grating. (a) What is the lowest order that is overlapped by another order? (b) What is the highest order for which the complete spectrum is present?

With light from a gaseous discharge tube incident normally on a grating with slit separation \(1.73 \mu \mathrm{m}\), sharp maxima of green light are experimentally found at angles \(\theta=\pm 17.6^{\circ}, 37.3^{\circ},-37.1^{\circ}\), \(65.2^{\circ}\), and \(-65.0^{\circ} .\) Compute the wavelength of the green light that best fits these data.

In the two-slit interference experiment of Fig. \(35-10\), the slit widths are each \(12.0 \mu \mathrm{m}\), their separation is \(24.0 \mu \mathrm{m}\), the wavelength is \(600 \mathrm{~nm}\), and the viewing screen is at a distance of \(4.00 \mathrm{~m}\). Let \(I_{P}\) represent the intensity at point \(P\) on the screen, at height \(y=70.0 \mathrm{~cm} .\) (a) What is the ratio of \(I_{P}\) to the intensity \(I_{m}\) at the center of the pattern? (b) Determine where \(P\) is in the two-slit interference pattern by giving the maximum or minimum on which it lies or the maximum and minimum between which it lies. (c) In the same way, for the diffraction that occurs, determine where point \(P\) is in the diffraction pattern.

A diffraction grating illuminated by monochromatic light normal to the grating produces a certain line at angle \(\theta .\) (a) What is the product of that line's half-width and the grating's resolving power? (b) Evaluate that product for the first order of a grating of slit separation \(900 \mathrm{~nm}\) in light of wavelength \(600 \mathrm{~nm}\).

A double-slit system with individual slit widths of \(0.030 \mathrm{~mm}\) and a slit separation of \(0.18 \mathrm{~mm}\) is illuminated with \(500 \mathrm{~nm}\) light directed perpendicular to the plane of the slits. What is the total number of complete bright fringes appearing between the two first- order minima of the diffraction pattern? (Do not count the fringes that coincide with the minima of the diffraction pattern.)

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