Chapter 36: Problem 66
An x-ray beam of a certain wavelength is incident on a \(\mathrm{NaCl}\) crystal, at \(30.0^{\circ}\) to a certain family of reflecting planes of spacing \(39.8 \mathrm{pm}\). If the reflection from those planes is of the first order, what is the wavelength of the \(\mathrm{x}\) rays?
Short Answer
Expert verified
The wavelength of the X-rays is 39.8 pm.
Step by step solution
01
Understand the Problem
We need to calculate the wavelength of an X-ray beam that is reflected first-order from a NaCl crystal. The angle of incidence is \(30.0^{\circ}\) and the plane spacing is \(39.8 \ \mathrm{pm}\).
02
Identify the Relevant Formula
We use Bragg's Law to solve the problem. Bragg's Law is formulated as: \[ n \lambda = 2d \sin \theta \] where \( n \) is the order of reflection, \( \lambda \) is the wavelength, \( d \) is the spacing between planes, and \( \theta \) is the angle of incidence.
03
Insert Known Values
Substitute the known values into Bragg's Law equation. We know \( n = 1 \) (first-order reflection), \( d = 39.8 \ \mathrm{pm} \), and \( \theta = 30.0^{\circ} \): \[ 1 \cdot \lambda = 2 \cdot 39.8 \ \mathrm{pm} \cdot \sin 30.0^{\circ} \]
04
Solve for Wavelength \( \lambda \)
Calculate \( \sin 30.0^{\circ} \) which equals \(0.5\), and substitute this into the equation: \[ \lambda = 2 \cdot 39.8 \ \mathrm{pm} \cdot 0.5 \] \[ \lambda = 39.8 \ \mathrm{pm} \]
05
Conclude the Calculation
The calculated wavelength of the X-ray that meets the given conditions of incidence and reflection is \(39.8 \ \mathrm{pm} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
X-ray diffraction
X-ray diffraction is a fascinating phenomenon that helps us understand the atomic structure of crystals. It occurs when X-rays are scattered by the electrons in a crystal. When these waves overlap, they produce a specific pattern known as diffraction. This pattern can be analyzed to provide critical information about the crystal’s structure.
X-rays have very short wavelengths, typically in the range of 0.1 to 10 nanometers, which are perfect for probing the spaces between the atoms in a crystal. When these waves hit a crystal lattice, they interact with the electron cloud around each atom, causing the waves to scatter in different directions.
X-rays have very short wavelengths, typically in the range of 0.1 to 10 nanometers, which are perfect for probing the spaces between the atoms in a crystal. When these waves hit a crystal lattice, they interact with the electron cloud around each atom, causing the waves to scatter in different directions.
- These scattered waves interfere with each other.
- Constructive interference occurs when the waves are in phase, strengthening their intensity and producing observable diffraction spots.
- Destructive interference occurs when the waves are out of phase, canceling each other out.
Crystal lattice
The crystal lattice is like the blueprint of a crystal. It's a highly ordered structure where atoms, molecules, or ions are arranged in a repeating pattern extending in all three spatial dimensions. This regularity and periodic nature is what allows X-ray diffraction to be such a powerful tool in structural analysis.
In a crystal lattice:
In a crystal lattice:
- The repeating units are known as the "unit cells," and these define the symmetry and structure of the entire crystal.
- Different types of lattices exist, such as cubic, hexagonal, tetragonal, etc., each with its own arrangement and angles between unit cells.
- The spacing between these planes, called the lattice parameter, is key to calculations using Bragg's Law.
Wavelength calculation
Calculating the wavelength of a beam using Bragg's Law is a straightforward process, but it requires a clear understanding of the underlying principles. Bragg's Law is expressed as \( n \lambda = 2d \sin \theta \). Let’s break this down:
\( \lambda = 2 \times 39.8 \ \text{pm} \times \sin 30.0^{\circ} \).
Substituting \( \sin 30.0^{\circ} = 0.5 \), we calculate \( \lambda = 39.8 \ \text{pm} \), delivering the wavelength of the reflected X-ray for these conditions. This calculation is a practical application of Bragg's Law, highlighting its significance in determining the characteristics of X-ray beams reflected by crystal lattices.
- \( n \) is the order of reflection, an integer value representing the sequence of the diffraction peak.
- \( \lambda \) is the wavelength of the incident X-ray, which we aim to calculate.
- \( d \) is the distance between the planes of atoms in the crystal, often provided in picometers (pm) or nanometers (nm).
- \( \theta \) is the angle of incidence, the angle at which the X-ray approaches the crystal planes.
\( \lambda = 2 \times 39.8 \ \text{pm} \times \sin 30.0^{\circ} \).
Substituting \( \sin 30.0^{\circ} = 0.5 \), we calculate \( \lambda = 39.8 \ \text{pm} \), delivering the wavelength of the reflected X-ray for these conditions. This calculation is a practical application of Bragg's Law, highlighting its significance in determining the characteristics of X-ray beams reflected by crystal lattices.