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Estimate the linear separation of two objects on Mars that can just be resolved under ideal conditions by an observer on Earth (a) using the naked eye and (b) using the 200 in. \((=5.1 \mathrm{~m})\) Mount Palomar telescope. Use the following data: distance to Mars \(=8.0 \times 10^{7} \mathrm{~km}\), diameter of pupil \(=5.0 \mathrm{~mm}\), wavelength of light \(=550 \mathrm{~nm}\).

Short Answer

Expert verified
Naked eye: 10720 m, Telescope: 10560 m

Step by step solution

01

Understanding Resolution

Resolution is the ability to distinguish two separate points as distinct. The smallest angle (angular resolution) which can be resolved by a circular aperture is given by the Rayleigh criterion: \( \theta = 1.22 \frac{\lambda}{D} \), where \( \lambda \) is the wavelength of light, and \( D \) is the diameter of the aperture (pupil or telescope).
02

Convert Units Appropriately

Convert the wavelength \( \lambda \) from nanometers to meters and the diameter from inches to meters when necessary. For calculations, \( \lambda = 550 \mathrm{~nm} = 550 \times 10^{-9} \mathrm{~m} \). For the telescope, \( D = 200 \) inches is already given as \( 5.1 \mathrm{~m} \).
03

Calculate Angular Resolution for Naked Eye

Substitute the diameter of the pupil \( D = 5.0 \mathrm{~mm} = 0.005 \mathrm{~m} \) into the Rayleigh criterion formula to find the angular resolution: \( \theta_{eye} = 1.22 \frac{550 \times 10^{-9}}{0.005} \approx 1.34 \times 10^{-4} \) radians.
04

Calculate Linear Separation for Naked Eye

Using the small-angle approximation \( s = d \times \theta \), where \( s \) is the linear separation, \( d \) is the distance to Mars. So, \( s_{eye} = 8.0 \times 10^{10} \times 1.34 \times 10^{-4} \approx 10720 \) meters.
05

Calculate Angular Resolution for Mount Palomar Telescope

Substitute \( D = 5.1 \mathrm{~m} \) for the telescope diameter into the Rayleigh criterion: \( \theta_{telescope} = 1.22 \frac{550 \times 10^{-9}}{5.1} \approx 1.32 \times 10^{-7} \) radians.
06

Calculate Linear Separation for Mount Palomar Telescope

Using the same small-angle approximation, \( s_{telescope} = 8.0 \times 10^{10} \times 1.32 \times 10^{-7} \approx 10560 \) meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rayleigh Criterion
The Rayleigh criterion is a principle used to determine the resolution capability of optical systems, such as the human eye or telescopes. Resolution refers to the ability to differentiate between two points that are close together. According to the Rayleigh criterion, the minimum resolvable angle \( \theta \) by a circular aperture is given by the formula:
  • \( \theta = 1.22 \frac{\lambda}{D} \)
Here, \( \lambda \) represents the wavelength of light, and \( D \) is the diameter of the aperture. This formula illustrates that the angular resolution depends on both the wavelength of the light being used and the size of the aperture. A smaller angle indicates a better resolution.
Intuitively, the Rayleigh criterion reflects a fundamental property of light diffraction: smaller apertures or larger wavelengths will produce more significant diffraction, which reduces the resolving power.
Linear Separation
Linear separation is essentially the actual distance between two objects, such as stars or terrestrial landmarks, which an observer can resolve. This concept is crucial when observing distant objects, especially in astronomy.
The relationship between angular resolution and linear separation can be established using the small-angle approximation. When dealing with astronomical distances, this approximation simplifies calculations significantly:
  • \( s = d \times \theta \)
In this formula, \( s \) is the linear separation, \( d \) is the distance to the object (in this case, Mars), and \( \theta \) is the angular resolution obtained from the Rayleigh criterion.
For observers on Earth trying to resolve features on Mars, the linear separation indicates the smallest feature size on Mars that can be distinguished, depending on the observing method employed, whether it be the naked eye or advanced telescopic equipment.
Telescope Resolution
Telescope resolution refers to the smallest detail of an astronomical object that a telescope can discern. It is a critical attribute for telescopes to efficiently examine celestial phenomena like planets, stars, and galaxies.
The resolution is governed by the same principles outlined by the Rayleigh criterion, utilizing the diameter of the telescope's aperture \( D \). The Mount Palomar telescope, with its 5.1-meter diameter, provides a much finer resolution than the human eye due to its larger aperture.
  • For the Mount Palomar telescope: \( \theta_{telescope} = 1.22 \frac{550 \times 10^{-9}}{5.1} \approx 1.32 \times 10^{-7} \) radians
Such precise angular resolution allows astronomers to observe much smaller features on distant celestial bodies, making it an essential tool for planetary study and scientific discovery.
The ability to resolve finer details helps in understanding the composition, structure, and dynamics of astronomical objects.
Wavelength of Light
Wavelength of light is the distance between successive peaks of electromagnetic waves. In the context of resolution, the wavelength plays a pivotal role. Shorter wavelengths, like blue light, enable better resolution compared to longer wavelengths, like red light, due to lower diffraction effects.
In this exercise, we utilized a wavelength of 550 nm, which corresponds to green light. This value is chosen because it is in the middle of the visible spectrum and represents an average wavelength that the human eye is sensitive to.
  • \( \lambda = 550 \text{ nm} = 550 \times 10^{-9} \text{ meters} \)
By incorporating this wavelength into the Rayleigh criterion, we determined how well different apertures, such as the human eye and the Mount Palomar telescope, can resolve two distinct points.
The role of wavelength illustrates why different light spectra, such as infrared or ultraviolet, can affect the precision and clarity of astronomical observations.

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Most popular questions from this chapter

A diffraction grating having 180 lines/mm is illuminated with a light signal containing only two wavelengths, \(\lambda_{1}=400 \mathrm{~nm}\) and \(\lambda_{2}=500 \mathrm{~nm} .\) The signal is incident perpendicularly on the grating. (a) What is the angular separation between the second-order maxima of these two wavelengths? (b) What is the smallest angle at which two of the resulting maxima are superimposed? (c) What is the highest order for which maxima for both wavelengths are present in the diffraction pattern?

Assume that Rayleigh's criterion gives the limit of resolution of an astronaut's eye looking down on Earth's surface from a typical space shuttle altitude of \(400 \mathrm{~km}\). (a) Under that idealized assumption, estimate the smallest linear width on Earth's surface that the astronaut can resolve. Take the astronaut's pupil diameter to be \(5 \mathrm{~mm}\) and the wavelength of visible light to be \(550 \mathrm{~nm}\). (b) Can the astronaut resolve the Great Wall of China (Fig. 36-40), which is more than \(3000 \mathrm{~km}\) long, 5 to \(10 \mathrm{~m}\) thick at its base, \(4 \mathrm{~m}\) thick at its top, and \(8 \mathrm{~m}\) in height? (c) Would the astronaut be able to resolve any unmistakable sign of intelligent life on Earth's surface?

In June 1985 , a laser beam was sent out from the Air Force Optical Station on Maui, Hawaii, and reflected back from the shuttle Discovery as it sped by \(354 \mathrm{~km}\) overhead. The diameter of the central maximum of the beam at the shuttle position was said to be \(9.1 \mathrm{~m}\), and the beam wavelength was \(500 \mathrm{~nm} .\) What is the effective diameter of the laser aperture at the Maui ground station? (Hint: A laser beam spreads only because of diffraction; assume a circular exit aperture.)

The distance between the first and fifth minima of a single-slit diffraction pattern is \(0.35 \mathrm{~mm}\) with the screen \(40 \mathrm{~cm}\) away from the slit, when light of wavelength \(550 \mathrm{~nm}\) is used. (a) Find the slit width. (b) Calculate the angle \(\theta\) of the first diffraction minimum.

What is the smallest Bragg angle for \(x\) rays of wavelength 30 \(\mathrm{pm}\) to reflect from reflecting planes spaced \(0.30 \mathrm{~nm}\) apart in a calcite crystal?

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