/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 High-power lasers are used to co... [FREE SOLUTION] | 91Ó°ÊÓ

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High-power lasers are used to compress a plasma (a gas of charged particles) by radiation pressure. A laser generating radiation pulses with peak power \(1.5 \times 10^{3} \mathrm{MW}\) is focused onto \(1.0\) \(\mathrm{mm}^{2}\) of high-electron-density plasma. Find the pressure exerted on the plasma if the plasma reflects all the light beams directly back along their paths.

Short Answer

Expert verified
The pressure exerted on the plasma is \(10^7\) Pa.

Step by step solution

01

Identify the relationship between power and pressure

The pressure ( p ) exerted by a light on a surface that perfectly reflects it can be calculated using the formula: \[ p = \frac{2P}{A \times c} \] where \( P \) is the power of the laser, \( A \) is the area, and \( c \) is the speed of light (approximately \( 3.0 \times 10^8 \text{ m/s} \)).
02

Substitute the given values into the formula

We know \( P = 1.5 \times 10^3 \text{ MW} = 1.5 \times 10^{9} \text{ W} \), \( A = 1.0 \text{ mm}^2 = 1.0 \times 10^{-6} \text{ m}^2 \), and \( c = 3.0 \times 10^8 \text{ m/s} \). Substitute these into the formula: \[ p = \frac{2 \times 1.5 \times 10^{9}}{1.0 \times 10^{-6} \times 3.0 \times 10^8} \]
03

Calculate the pressure

Perform the calculation: \[ p = \frac{3.0 \times 10^{9}}{3.0 \times 10^2} \] Simplifying this gives: \[ p = 1.0 \times 10^7 \text{ N/m}^2 \] or \( 10^7 \text{ Pa} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laser Power
Laser power refers to the amount of energy a laser emits per unit time. It is measured in watts (W), or in this case, megawatts (MW). A laser's power is crucial in applications such as cutting, medical surgeries, or inducing plasma compression through radiation pressure. High-power lasers can achieve significant effects in very short time spans, due to their enormous power output. Understanding laser power involves recognizing its relationship with energy and time:
  • Energy (in joules) = Power (in watts) × Time (in seconds)
The intensity of a laser's beam, defined as the power per unit area, highlights why it's an effective tool for precisely manipulating materials, including the compression of plasma by generating substantial radiation pressure.
Plasma Physics
Plasma physics is the study of plasma—often called the fourth state of matter. Plasmas consist of charged particles, such as electrons and ions, and exhibit unique behaviors compared to solids, liquids, and gases. In plasma, the particles are so energized that electrons are freed from their atoms, allowing for their charged nature and unique physical properties. Key characteristics:
  • Plasmas conduct electricity.
  • They are affected by magnetic and electric fields.
  • They can generate and respond to radiation, including light and X-rays.
In the context of a laser compressing a plasma, understanding these properties helps explain how the energy and pressure from the laser can alter or control the plasma state.
Reflection of Light
Reflection of light involves the bouncing back of light waves when they encounter a surface. In perfect reflection, such as with a mirror or a reflective plasma, nearly all the incoming light is redirected. When we talk about laser beams and plasma:
  • The incident light energy can exert pressure on the reflective surface, due to the momentum change when light bounces back.
  • This reflective property is used in calculations of radiation pressure, where a perfectly reflective surface reflects all incident light along the same path, maximizing the pressure effect.
For the exercise, the assumption that the plasma reflects all the light is crucial for accurately determining the pressure calculation.
Pressure Calculation
Pressure, in this context, is the force exerted by light on a surface area. When light reflects off a surface, it imparts more pressure than if it were absorbed or transmitted. This is because the change in momentum is doubled, as light moves from one direction and reverses. The formula used: \[ p = \frac{2P}{A \times c} \]captures this effect mathematically. Here's what each symbol means:
  • \( p \): pressure (in pascals, Pa)
  • \( P \): power of the laser (in watts, W)
  • \( A \): area the laser affects (in square meters, m²)
  • \( c \): speed of light (approximately \( 3.0 \times 10^8 \text{ m/s} \))
Substituting the given values into this formula enables the calculation of the pressure exerted on the plasma surface by the laser.
Speed of Light
The speed of light is a fundamental constant in physics, denoted as \( c \), with a value of approximately \( 3.0 \times 10^8 \text{ m/s} \). This constant is crucial not just for calculations involving light, but for understanding universal physical laws. In radiation pressure calculations:
  • Light's speed relates light's power and energy to the pressure it exerts.
  • It is a constant bridge connecting energy, momentum, and force in electromagnetic theory.
  • It impacts how laser energy influences materials; faster interactions mean effects happen swiftly and forcefully.
Appreciating the speed of light's role in these calculations helps us understand how light can exert substantial forces and manipulate materials at high speeds.

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Most popular questions from this chapter

An electromagnetic wave with frequency \(4.00 \times 10^{14} \mathrm{~Hz}\) travels through vacuum in the positive direction of an \(x\) axis. The wave has its electric field directed parallel to the \(y\) axis, with amplitude \(E_{m}\). At time \(t=0\), the electric field at point \(P\) on the \(x\) axis has a value of \(+E_{m} / 4\) and is decreasing with time. What is the distance along the \(x\) axis from point \(P\) to the first point with \(E=0\) if we search in (a) the negative direction and (b) the positive direction of the \(x\) axis?

Figure 33-61 depicts a simplistic optical fiber: a plastic core \(\left(n_{1}=\right.\) \(1.58\) ) is surrounded by a plastic sheath \(\left(n_{2}=1.53\right) .\) A light ray is incident on one end of the fiber at angle \(\theta\). The ray is to undergo total internal reflection at point \(A\), where it encounters the core-sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of \(\theta\) that allows total internal reflection at \(A\) ?

The average intensity of the solar radiation that strikes normally on a surface just outside Earth's atmosphere is \(1.4 \mathrm{~kW} / \mathrm{m}^{2} .\) (a) What radiation pressure \(p_{r}\) is exerted on this surface, assuming complete absorption? (b) For comparison, find the ratio of \(p_{r}\) to Earth's sea-level atmospheric pressure, which is \(1.0 \times 10^{5} \mathrm{~Pa}\).

(a) How long does it take a radio signal to travel \(150 \mathrm{~km}\) from a transmitter to a receiving antenna? (b) We see a full Moon by reflected sunlight. How much earlier did the light that enters our eye leave the Sun? The Earth-Moon and Earth-Sun distances are \(3.8 \times 10^{5} \mathrm{~km}\) and \(1.5 \times 10^{8} \mathrm{~km}\), respectively. (c) What is the round-trip travel time for light between Earth and a spaceship orbiting Saturn, \(1.3 \times 10^{9} \mathrm{~km}\) distant? (d) The Crab nebula, which is about 6500 light-years (ly) distant, is thought to be the result of a supernova explosion recorded by Chinese astronomers in A.D. 1054 . In approximately what year did the explosion actually occur? (When we look into the night sky, we are effectively looking back in time.)

A black, totally absorbing piece of cardboard of area \(A=2.0 \mathrm{~cm}^{2}\) intercepts light with an intensity of \(10 \mathrm{~W} / \mathrm{m}^{2}\) from a camera strobe light. What radiation pressure is produced on the cardboard by the light?

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