Chapter 32: Problem 59
A parallel-plate capacitor with circular plates of radius \(R=16 \mathrm{~mm}\) and gap width \(d=5.0 \mathrm{~mm}\) has a uniform electric field between the plates. Starting at time \(t=0\), the potential difference between the two plates is \(V=(100 \mathrm{~V}) e^{-t / \tau}\), where the time constant \(\tau=12 \mathrm{~ms}\). At radial distance \(r=0.80 R\) from the central axis, what is the magnetic field magnitude (a) as a function of time for \(t \geq 0\) and \((\mathrm{b})\) at time \(t=3 \tau ?\)
Short Answer
Step by step solution
Start with the Formula for Capacitance
Determine the Time Derivative of the Potential
Find the Displacement Current
Apply Ampère-Maxwell Law
Simplify and Calculate Magnetic Field as Function of Time
Calculate Magnetic Field at Time \( t=3\tau \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parallel-Plate Capacitor
The capacitance (C) of a parallel-plate capacitor is determined by the formula: \( C = \frac{\varepsilon_0 A}{d} \). Here, \( \varepsilon_0 \) represents the vacuum permittivity, \( A \) is the area of the plates, and \( d \) is the gap width between the plates. In the case of circular plates, the area becomes \( A = \pi R^2 \), where \( R \) is the radius. Therefore, the capacitance is directly proportional to the area of the plates and inversely proportional to the distance between the plates.
- Larger plate area results in higher capacitance.
- A smaller distance between plates increases capacitance.
Displacement Current
Displacement current (I_d) is not a current in the traditional sense but represents a time-varying electric field's influence. In a capacitor, as the voltage across the plates changes over time, there's a corresponding change in the electric field between the plates. Maxwell proposed that this changing electric field can be treated as an equivalent current, given by the formula: \( I_d = C \frac{dV}{dt} \).
Using our parallel-plate capacitor example, the rate at which the voltage changes over time is signified by the derivative \( \frac{dV}{dt} \), which can directly impact the displacement current:
- This concept is crucial in ensuring continuity in Maxwell's equations, particularly when dealing with circuits that incorporate capacitors experiencing changing voltages.
- The displacement current bridges the gap in Ampère's Law, ensuring the continuity of current in a circuit.
Ampère-Maxwell Law
This law essentially states that both conduction currents and displacement currents contribute to the total magnetic field around a closed loop. The complete form of the law is expressed as an equation, where the magnetic field at a distance \( r \) from the central axis is given by:\[ B(2\pi r) = \mu_0 I_d \frac{r^2}{R^2} \]Here:
- \( \mu_0 \) is the permeability of free space.
- \( I_d \) represents the displacement current.
- \( r \) is the radial distance where the magnetic field is being evaluated.
Time Constant
For a parallel-plate capacitor with a time-varying potential, the formula for the voltage is typically modeled as \( V(t) = V_0 e^{-t / \tau} \), where \( V_0 \) is the initial potential difference. Here, the time constant \( \tau \) determines the time it takes for the potential difference to decrease to about 37% of its initial value.
- A smaller time constant represents rapid changes and swift charging/discharging.
- A larger time constant indicates slower changes over time.