/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 A generator supplies \(100 \math... [FREE SOLUTION] | 91Ó°ÊÓ

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A generator supplies \(100 \mathrm{~V}\) to a transformer's primary coil, which has 50 turns. If the secondary coil has 500 turns, what is the secondary voltage?

Short Answer

Expert verified
The secondary voltage is 1000 V.

Step by step solution

01

Understanding the Transformer Law

A transformer uses electromagnetic induction to transfer energy between its coils. The voltage across these coils is related to the number of turns in each coil as per the formula: \( \frac{V_2}{V_1} = \frac{N_2}{N_1} \), where \(V_1\) and \(V_2\) are the voltages and \(N_1\) and \(N_2\) are the number of turns in the primary and secondary coils, respectively.
02

Applying the Formula

Use the transformer formula: \( \frac{V_2}{V_1} = \frac{N_2}{N_1} \). Substitute the known values: \(V_1 = 100\, \mathrm{V}\), \(N_1 = 50\), and \(N_2 = 500\).
03

Calculating the Secondary Voltage

Rearrange the formula to solve for \(V_2\): \( V_2 = V_1 \times \frac{N_2}{N_1} \). Substitute the known values: \( V_2 = 100 \times \frac{500}{50} \). Calculate the result: \( V_2 = 100 \times 10 = 1000 \). So, the secondary voltage \( V_2 \) is 1000 volts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Induction
Electromagnetic induction is a phenomenon where an electric voltage is generated across a conductor situated in a changing magnetic field. Imagine it as the conductor 'cuts' through magnetic lines of force, which in turn, induces voltage.

This principle is the cornerstone of how transformers work. In our example, a transformer uses the concept of electromagnetic induction to convert the voltage levels. By changing magnetic fields within the primary coil, electricity is induced in the secondary coil. Since no physical connection exists between the two coils, the energy is passed through this changing magnetic field. This is why transformers are crucial in transferring electricity across power lines efficiently.
Voltage Transformation
Voltage transformation is about changing the voltage level from one coil to another using a transformer. In our example, this involves converting 100 volts at the primary coil to a higher voltage in the secondary coil. This is done through electromagnetic induction, where the energy transfer occurs through a magnetic field.

Transformers are widely used to either increase (step-up) or decrease (step-down) voltage levels. Their ability to transform voltage makes it possible to transport electricity over long distances with minimal losses. In our scenario, having more turns in the secondary coil compared to the primary coil results in a higher secondary voltage, demonstrating a step-up transformation.
Turns Ratio Rule
The turns ratio rule is a fundamental concept to calculate the transformed voltage in a transformer. By knowing the number of turns in both the primary and secondary coils, one can easily predict the voltage change. The formula is given by: \[\frac{V_2}{V_1} = \frac{N_2}{N_1}\]
  • \(V_1\) - primary voltage
  • \(V_2\) - secondary voltage
  • \(N_1\) - number of turns in the primary coil
  • \(N_2\) - number of turns in the secondary coil
In our exercise, given \(V_1 = 100\, \mathrm{V}\), \(N_1 = 50\), and \(N_2 = 500\), we can rearrange and calculate the secondary voltage \(V_2\) as follows:\[V_2 = V_1 \times \frac{N_2}{N_1} = 100 \times \frac{500}{50} = 1000\, \text{volts}\]The turns ratio rule simplifies the understanding of how transformers alter voltage levels based on coil turns.

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Most popular questions from this chapter

A transformer has 500 primary turns and 10 secondary turns. (a) If \(V_{p}\) is \(120 \mathrm{~V}\) (rms), what is \(V_{s}\) with an open circuit? If the secondary now has a resistive load of \(15 \Omega\), what is the current in the (b) primary and (c) secondary?

In an oscillating \(L C\) circuit in which \(C=4.00 \mu \mathrm{F}\), the maximum potential difference across the capacitor during the oscillations is \(1.50 \mathrm{~V}\) and the maximum current through the inductor is \(50.0 \mathrm{~mA}\). What are (a) the inductance \(L\) and (b) the frequency of the oscillations? (c) How much time is required for the charge on the capacitor to rise from zero to its maximum value?

In an oscillating \(L C\) circuit, \(L=3.00 \mathrm{mH}\) and \(C=2.70\) \(\mu\) F. At \(t=0\) the charge on the capacitor is zero and the current is \(2.00\) A. (a) What is the maximum charge that will appear on the capacitor? (b) At what earliest time \(t>0\) is the rate at which energy is stored in the capacitor greatest, and (c) what is that greatest rate?

When under load and operating at an rms voltage of \(220 \mathrm{~V}, \mathrm{a}\) certain electric motor draws an rms current of \(3.00 \mathrm{~A}\). It has a resistance of \(24.0 \Omega\) and no capacitive reactance. What is its inductive reactance?

A single-loop circuit consists of a \(7.20 \Omega\) resistor, a \(12.0 \mathrm{H}\) inductor, and a \(3.20 \mu \mathrm{F}\) capacitor. Initially the capacitor has a charge of \(6.20 \mu \mathrm{C}\) and the current is zero. Calculate the charge on the capacitor \(N\) complete cycles later for (a) \(N=5\), (b) \(N=10\), and (c) \(N=100\).

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