Chapter 31: Problem 44
An ac generator with \(\mathscr{E}_{m}=220 \mathrm{~V}\) and operating at \(400 \mathrm{~Hz}\) causes oscillations in a series \(R L C\) circuit having \(R=220\) \(\Omega, L=150 \mathrm{mH}\), and \(C=24.0 \mu \mathrm{F}\). Find (a) the capacitive reactance \(X_{C},(\mathrm{~b})\) the impedance \(Z\), and \((\mathrm{c})\) the current amplitude \(I .\) A second capacitor of the same capacitance is then connected in series with the other components. Determine whether the values of (d) \(X_{C}\), (e) \(Z\), and (f) \(I\) increase, decrease, or remain the same.
Short Answer
Step by step solution
Calculate the Capacitive Reactance (X_C)
Calculate the Impedance (Z)
Calculate the Current Amplitude (I)
Determine the Effect on Capacitive Reactance (X_C) When A Second Capacitor Is Added
Determine the Effect on Impedance (Z) When A Second Capacitor Is Added
Determine the Effect on Current Amplitude (I) When A Second Capacitor Is Added
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Capacitive Reactance
- \( f \) is the frequency of the AC supply, measured in Hertz (Hz).
- \( C \) is the capacitance, measured in Farads (F).
Impedance
- \( R \) is the resistance.
- \( X_L \) is the inductive reactance.
- \( X_C \) is the capacitive reactance.
Current Amplitude
RLC Circuit
- The resistor impedes both AC and DC equally and converts electrical energy into heat.
- The inductor provides inductive reactance, hindering the change in current and storing energy as a magnetic field.
- The capacitor yields capacitive reactance, limiting the change in voltage and holding electrical energy in an electric field.
Inductive Reactance
- \( f \) is the frequency.
- \( L \) is the inductance, measured in Henrys (H).