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The inductance of a closely wound coil is such that an emf of \(3.00 \mathrm{mV}\) is induced when the current changes at the rate of \(5.00\) A/s. A steady current of \(8.00\) A produces a magnetic flux of \(40.0\) \(\mu\) Wb through each turn. (a) Calculate the inductance of the coil. (b) How many turns does the coil have?

Short Answer

Expert verified
(a) The inductance is 0.600 mH. (b) The coil has 120 turns.

Step by step solution

01

Understanding the relationship for inductance

The induced emf \( \mathcal{E} \) in a coil is given by \( \mathcal{E} = -L \frac{dI}{dt} \), where \( L \) is the inductance of the coil, and \( \frac{dI}{dt} \) is the rate of change of current. In this problem, \( \mathcal{E} = 3.00 \: \text{mV} = 3.00 \times 10^{-3} \: \text{V} \) and \( \frac{dI}{dt} = 5.00 \: \text{A/s} \). Substitute these values to find \( L \).
02

Calculate the inductance

Rearrange the formula to find \( L = \frac{\mathcal{E}}{\frac{dI}{dt}} \). Substituting the given values, \( L = \frac{3.00 \times 10^{-3}}{5.00} \: \text{H} = 6.00 \times 10^{-4} \: \text{H} \) or \( 0.600 \: \text{mH} \).
03

Calculate the total magnetic flux

The magnetic flux through each turn due to a steady current is given as \( 40.0 \: \mu \text{Wb} = 40.0 \times 10^{-6} \: \text{Wb} \). The total magnetic flux \( \Phi \) is associated with the inductance \( L \) and current \( I \) by \( L = \frac{N \Phi}{I} \), where \( N \) is the number of turns.
04

Find the number of turns

Using the relationship \( L = \frac{N \Phi}{I} \) and rearranging gives \( N = \frac{LI}{\Phi} \). Substitute \( L = 6.00 \times 10^{-4} \: \text{H} \), \( I = 8.00 \: \text{A} \), and \( \Phi = 40.0 \times 10^{-6} \: \text{Wb} \) to get the number of turns: \( N = \frac{6.00 \times 10^{-4} \times 8.00}{40.0 \times 10^{-6}} = 120 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux refers to the total magnetic field passing through a particular area. It symbolizes the strength and presence of a magnetic field through a surface (like a loop of wire). The term "flux" gives an impression of flow, just like how water flows through a hose. The unit of magnetic flux is the Weber (Wb), and it's often found in micro Webers (μWb) in smaller applications.

In this exercise, the magnetic flux is crucial to understanding inductance in a coil. When we have a current flowing through a coil, it generates a magnetic field. This magnetic flux depends on the current and the structure of the coil. If the magnetic flux through each turn of a coil is known, as well as the current causing it, we can explore how many such 'turns' or loops are present in the coil, directly relating to coil inductance.
  • Magnetic flux, denoted as \( \Phi \), is expressed as \( \Phi = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field, \( A \) is the area through which the field lines pass, and \( \theta \) is the angle between the field lines and the perpendicular to the surface.
  • A steady current in the coil produces a consistent total magnetic flux, affecting the coil's inductance and other electrical properties.
  • Understanding the flow of magnetic flux helps in calculating the electrical characteristics of devices like inductors and transformers.
Faraday's Law of Electromagnetic Induction
Faraday's Law of Electromagnetic Induction is a fundamental principle that describes how electric currents are generated by changing magnetic fields. It forms the basis of how inductors operate and explains a lot of electromagnetic phenomena.

According to Faraday's Law, an electromotive force (emf) is induced in a circuit whenever the magnetic flux through the circuit changes. The relationship is given by the formula \( \mathcal{E} = -L \frac{dI}{dt} \), where \( \mathcal{E} \) is the induced emf, \( L \) is the inductance, and \( \frac{dI}{dt} \) is the rate of change of current. This is the primary equation that connects induced emf to inductance. The negative sign indicates Lenz's Law, which says the induced emf opposes the change in flux.

In our exercise, the coil's emf was induced by a change in current, using this very law. It allowed us to calculate the inductance of the coil with given values:
  • Faraday's Law helps engineers design electric components by predicting how inductors respond to varying currents and fields.
  • It shows that greater the rate of change of magnetic flux, the greater the induced emf.
  • The principle is key in electrical engineering and technologies involving motors, generators, and transformers, as it explains energy conversion between electrical and magnetic forms.
Coil Turns Calculation
When designing coils, knowing the number of turns is essential. The total number of coil turns, denoted by \( N \), directly impacts the inductance and magnetic properties of the coil.

The formula for calculating turns based on inductance and magnetic flux is given by rearranging the relationship \( L = \frac{N \Phi}{I} \). From this, \( N = \frac{L I}{\Phi} \). In simple words, for a determined inductance and resulting magnetic flux given a steady current, we can find out how many individual loops or turns the coil must have:
  • The number of turns impacts the overall strength of coils, affecting electromagnetic devices from simple transformers to complex communication equipment.
  • More turns in a coil generally mean higher inductance, translating into a greater magnetic field when used in circuits.
  • Precision in calculating coil turns ensures that devices like transformers are efficient and safe in operation.
Accurate calculation is crucial in electrical engineering to ensure proper functioning and safety of devices, whether they generate, transform, or store energy.

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Most popular questions from this chapter

The current in an \(R L\) circuit drops from \(1.0 \mathrm{~A}\) to \(10 \mathrm{~mA}\) in the first second following removal of the battery from the circuit. If \(L\) is \(10 \mathrm{H}\), find the resistance \(R\) in the circuit.

A small circular loop of area \(2.00 \mathrm{~cm}^{2}\) is placed in the plane of, and concentric with, a large circular loop of radius \(1.00 \mathrm{~m}\). The current in the large loop is changed at a constant rate from \(200 \mathrm{~A}\) to \(-200 \mathrm{~A}\) (a change in direction) in a time of \(1.00 \mathrm{~s}\), starting at \(t=0\). What is the magnitude of the magnetic field \(\vec{B}\) at the center of the small loop due to the current in the large loop at (a) \(t=0\), (b) \(t=0.500 \mathrm{~s}\), and \((\mathrm{c}) t=1.00 \mathrm{~s} ?\) (d) From \(t=0\) to \(t=1.00 \mathrm{~s}\), is \(\vec{B}\) reversed? Because the inner loop is small, assume \(\vec{B}\) is uniform over its area. (e) What emf is induced in the small loop at \(t=0.500 \mathrm{~s}\) ?

Two inductors \(L_{1}\) and \(L_{2}\) are connected in parallel and separated by a large distance so that the magnetic field of one cannot affect the other. (a) Show that the equivalent inductance is given by $$\frac{1}{L_{\mathrm{eq}}}=\frac{1}{L_{1}}+\frac{1}{L_{2}}$$ (Hint: Review the derivations for resistors in parallel and capacitors in parallel. Which is similar here?) (b) What is the generalization of (a) for \(N\) inductors in parallel?

A wire loop of lengths \(L=\) \(40.0 \mathrm{~cm}\) and \(W=25.0 \mathrm{~cm}\) lies in a magnetic field \(\vec{B}\). What are the (a) magnitude \(\mathscr{E}\) and (b) direction (clockwise or counterclockwise-or "none" if \(\mathscr{E}=0\) ) of the emf induced in the loop if \(\vec{B}=\left(4.00 \times 10^{-2} \mathrm{~T} / \mathrm{m}\right) y \hat{\mathrm{k}} ?\) What are (c) \(\mathscr{8}\) and (d) the direction if \(\vec{B}=\left(6.00 \times 10^{-2} \mathrm{~T} / \mathrm{s}\right) t \hat{\mathrm{k}} ?\) What are (e) \(\mathscr{E}\) and (f) the direction if \(\vec{B}=\left(8.00 \times 10^{-2} \mathrm{~T} / \mathrm{m} \cdot \mathrm{s}\right) y t \hat{\mathrm{k}} ?\) What are \((\mathrm{g}) \mathscr{8}\) and \((\mathrm{h})\) the direction if \(\vec{B}=\left(3.00 \times 10^{-2} \mathrm{~T} / \mathrm{m} \cdot \mathrm{s}\right) x t \hat{j} ?\) What are (i) \(\mathscr{E}\) and \((\mathrm{j})\) the direction if \(\vec{B}=\left(5.00 \times 10^{-2} \mathrm{~T} / \mathrm{m} \cdot \mathrm{s}\right) y t \hat{i} ?\)

A coil \(C\) of \(N\) turns is placed around a long solenoid \(\mathrm{S}\) of radius \(R\) and \(n\) turns per unit length, as in Fig. 30-67. (a) Show that the mutual in. ductance for the coil-solenoid combination is given by \(M=\mu_{0} \pi R^{2} n N\). (b) Explain why \(M\) does not depend on the shape, size, or possible lack of close packing of the coil.

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