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A square loop of wire is held in a uniform \(0.24 \mathrm{~T}\) magnetic field directed perpendicular to the plane of the loop. The length of each side of the square is decreasing at a constant rate of \(5.0 \mathrm{~cm} / \mathrm{s}\). What emf is induced in the loop when the length is \(12 \mathrm{~cm}\) ?

Short Answer

Expert verified
The induced emf is 0.00288 V when the side length is 12 cm.

Step by step solution

01

Understand the Problem

We are given a square loop of wire in a perpendicular magnetic field. The side of the square is decreasing, causing a change in the magnetic flux, and we need to find the emf induced when the side of the square is 12 cm.
02

Define the Variables

- Magnetic Field, \( B = 0.24 \) T.- Rate of change of the side of the square, \( \frac{dL}{dt} = -0.05 \) m/s (negative because it's decreasing).- Length of the side, \( L = 0.12 \) m.
03

Understand Faraday's Law of Induction

The induced emf (\( \epsilon \)) in the loop is given by Faraday's law of electromagnetic induction: \( \epsilon = - \frac{d\Phi}{dt} \), where \( \Phi \) is the magnetic flux.
04

Calculate the Magnetic Flux

Magnetic flux \( \Phi \) is defined as \( \Phi = B \times A \), where \( A \) is the area of the square. Given \( A = L^2 \), for \( L = 0.12 \) m, \( A = (0.12)^2 = 0.0144 \) m². Therefore, \( \Phi = 0.24 \times 0.0144 = 0.003456 \) T·m².
05

Differentiate the Magnetic Flux with Respect to Time

The change in magnetic flux with respect to time is \( \frac{d\Phi}{dt} = B \times \frac{dA}{dt} \). Since \( A = L^2 \), \( \frac{dA}{dt} = 2L \frac{dL}{dt} \). For \( L = 0.12 \) m and \( \frac{dL}{dt} = -0.05 \) m/s, \( \frac{dA}{dt} = 2 \times 0.12 \times (-0.05) = -0.012 \) m²/s.
06

Calculate the Induced EMF

Substitute \( \frac{dA}{dt} = -0.012 \) m²/s and \( B = 0.24 \) T into \( \frac{d\Phi}{dt} = B \times \frac{dA}{dt} \) to find \( \frac{d\Phi}{dt} = 0.24 \times (-0.012) = -0.00288 \) T·m²/s. The induced emf is \( \epsilon = - \frac{d\Phi}{dt} = 0.00288 \) V.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a crucial concept in understanding electromagnetic induction. It describes the quantity of magnetic field passing through a given area. The formula to calculate magnetic flux \( \Phi \) is \( \Phi = B \times A \), where \( B \) is the magnetic field strength, and \( A \) is the area through which the field lines pass.

For example, if you have a uniform magnetic field and a loop of wire, the flux depends directly on the area of the loop. This means that as the area changes, so does the magnetic flux. For a square loop with a side length \( L \), the area \( A \) can be calculated as \( L^2 \).

Understanding magnetic flux is vital because, according to Faraday's law of induction, it is the change in magnetic flux that induces an electromotive force (emf) in a loop. This principle forms the basis of many electrical devices, such as transformers and electric generators.
Induced EMF
When we talk about induced emf, we're referring to the voltage created through a change in magnetic flux over time. According to Faraday's law of induction, the induced emf \( \epsilon \) is equal to the negative rate of change of magnetic flux:
\[ \epsilon = -\frac{d\Phi}{dt} \]
Think of the emf as the electricity produced by cutting through magnetic field lines.
The negative sign in Faraday's law is significant, as it indicates the direction of the induced emf opposes the change in flux, aligning with Lenz's law.

In practical situations, like the exercise we're discussing, fluctuations in the size of a loop or the strength of the magnetic field lead to changes in magnetic flux, thereby generating an emf. This is how electrical power is often generated. Whenever there's motion in a magnetic field, or a varying magnetic field, emf induction takes place.
Uniform Magnetic Field
A uniform magnetic field is one where the magnetic field lines are parallel and equidistant. This means that the field's strength and direction are consistent throughout the area. Such fields are simple to work with because they allow for straightforward calculations involving magnetic flux and induced emf.

In electromagnetic problems, the concept of a uniform magnetic field ensures that when calculating flux, you can use the straightforward formula \( \Phi = B \times A \) without needing to account for variations in \( B \). This uniformity simplifies many real-world applications, like those in motors and generators, where control and predictability of the magnetic field are crucial.

Uniform fields often originate from magnets that have been designed specifically to produce these conditions, or from regions of space where external factors have been minimized to create a stable magnetosphere. Understanding uniform magnetic fields is essential for studying how they interact with conductive materials and induce emf.

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Most popular questions from this chapter

A small loop of area \(6.8 \mathrm{~mm}^{2}\) is placed inside a long solenoid that has 854 turns \(/ \mathrm{cm}\) and carries a sinusoidally varying current \(i\) of amplitude \(1.28\) A and angular frequency \(212 \mathrm{rad} / \mathrm{s}\). The central axes of the loop and solenoid coincide. What is the amplitude of the emf induced in the loop?

A coil \(C\) of \(N\) turns is placed around a long solenoid \(\mathrm{S}\) of radius \(R\) and \(n\) turns per unit length, as in Fig. 30-67. (a) Show that the mutual in. ductance for the coil-solenoid combination is given by \(M=\mu_{0} \pi R^{2} n N\). (b) Explain why \(M\) does not depend on the shape, size, or possible lack of close packing of the coil.

A wire forms a closed circular loop, of radius \(R=\) \(2.0 \mathrm{~m}\) and resistance \(4.0 \Omega\). The circle is centered on a long straight wire; at time \(t=0\), the current in the long straight wire is \(5.0 \mathrm{~A}\) rightward. Thereafter, the current changes according to \(i=5.0 \mathrm{~A}-\) \(\left(2.0 \mathrm{~A} / \mathrm{s}^{2}\right) t^{2}\). (The straight wire is insulated; so there is no electrical contact between it and the wire of the loop.) What is the magnitude of the current induced in the loop at times \(t>0\) ?

A coil with an inductance of \(2.0 \mathrm{H}\) and a resistance of \(10 \Omega\) is suddenly connected to an ideal battery with \(\mathscr{E}=100 \mathrm{~V}\). (a) What is the equilibrium current? (b) How much energy is stored in the magnetic field when this current exists in the coil?

Two inductors \(L_{1}\) and \(L_{2}\) are connected in parallel and separated by a large distance so that the magnetic field of one cannot affect the other. (a) Show that the equivalent inductance is given by $$\frac{1}{L_{\mathrm{eq}}}=\frac{1}{L_{1}}+\frac{1}{L_{2}}$$ (Hint: Review the derivations for resistors in parallel and capacitors in parallel. Which is similar here?) (b) What is the generalization of (a) for \(N\) inductors in parallel?

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