/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A uniform magnetic field \(\vec{... [FREE SOLUTION] | 91Ó°ÊÓ

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A uniform magnetic field \(\vec{B}\) is perpendicular to the plane of a circular loop of diameter \(10 \mathrm{~cm}\) formed from wire of diameter \(2.5 \mathrm{~mm}\) and resistivity \(1.69 \times 10^{-8} \Omega \cdot \mathrm{m}\). At what rate must the magnitude of \(\vec{B}\) change to induce a \(10 \mathrm{~A}\) current in the loop?

Short Answer

Expert verified
The magnetic field must change at a rate of 1.38 T/s.

Step by step solution

01

Determine the Area of the Loop

The diameter of the loop is given as 10 cm; therefore, the radius \( r \) of the loop is half of that: \( r = \frac{10}{2} = 5 \text{ cm} = 0.05 \text{ m} \).The area \( A \) of the loop is calculated using the formula for the area of a circle, \( A = \pi r^2 \).Substituting the values gives:\[ A = \pi (0.05)^2 = 7.85 \times 10^{-3} \text{ m}^2 \].
02

Calculate the Resistance of the Loop

The loop is formed from wire of diameter 2.5 mm, which is \( 0.0025 \text{ m} \). The radius of the wire, \( r_w \), is \( \frac{0.0025}{2} \text{ m} \).Use this to find the cross-sectional area of the wire: \( A_w = \pi (0.00125)^2 \approx 4.91 \times 10^{-6} \text{ m}^2 \).The resistivity \( \rho \) is given as \( 1.69 \times 10^{-8} \Omega \cdot \text{m} \).The resistance \( R \) of the wire is \( R = \rho \frac{L}{A_w} \).For a loop, \( L = 2 \pi r \), substitute to get:\[ L = 2\pi(0.05) = 0.314 \text{ m} \]\[ R = \frac{1.69 \times 10^{-8} \times 0.314}{4.91 \times 10^{-6}} \approx 1.083 \times 10^{-3} \Omega \].
03

Apply Faraday's Law of Induction

Faraday's law states that the induced electromotive force (EMF) in a closed loop equals the negative rate of change of magnetic flux through the loop.The induced current \( I \) is given as 10 A, so the EMF \( \mathcal{E} = I \times R \).\[ \mathcal{E} = 10 \times 1.083 \times 10^{-3} = 1.083 \times 10^{-2} \text{ V} \].
04

Calculate the Rate of Change of Magnetic Field

The EMF can also be expressed as \( \mathcal{E} = A \frac{dB}{dt} \).We now rearrange to find \( \frac{dB}{dt} \).\[ \frac{dB}{dt} = \frac{\mathcal{E}}{A} = \frac{1.083 \times 10^{-2}}{7.85 \times 10^{-3}} \approx 1.38 \text{ T/s} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law of Electromagnetic Induction is one of the fundamental principles of electromagnetism. It explains how an electromotive force (EMF) is induced in a conductor when there is a change in magnetic flux. This law is vital because it underpins technologies like transformers, electric generators, and induction motors.
In simple terms, Faraday's Law states that the induced EMF in any closed circuit is equal to the rate at which the magnetic flux through the circuit is changing. Mathematically, it is expressed as: \[ \mathcal{E} = - \frac{d\Phi_B}{dt} \] where \( \mathcal{E} \) is the induced electromotive force (EMF) and \( \Phi_B \) is the magnetic flux. The negative sign represents Lenz's Law, indicating that the direction of induced EMF opposes the change in flux.
In this exercise, applying Faraday's Law helps calculate the EMF necessary to induce a 10 A current in the loop by determining the rate of change of the magnetic field (\( \vec{B} \)). This shows the practical application of Faraday's Law in real-world scenarios.
Magnetic Field
A magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts. It is denoted by the symbol \( \vec{B} \) and is a vector field, meaning it has both a direction and a magnitude.
In the context of electromagnetic induction, the changing magnetic field is crucial. A steady magnetic field will not induce an EMF in a closed circuit; it is the variation in the magnetic field that creates the "action" needed to produce electricity. This is why, in this exercise, the rate of change of the magnetic field is calculated to ascertain the necessary field alteration to induce enough current.
To imagine a magnetic field, think about the invisible lines of force that emerge from a magnet and loop around. These lines are closest together at the poles of the magnet, where the magnetic field is strongest. This concept can be abstract but is key to understanding how circuits and devices manipulate magnetism to function.
Resistance
Resistance is a measure of how much an object opposes an electric current flowing through it. It is represented by \( R \) and measured in Ohms (\( \Omega \)). The resistance of a wire depends on its dimensions and material.
In this exercise, the wire forming the loop has a given resistivity and diameter, which help calculate its resistance. The formula \( R = \rho \frac{L}{A_w} \) is used, where \( \rho \) is resistivity, \( L \) is the length of the wire (circumference of the loop), and \( A_w \) is the cross-sectional area of the wire.
Understanding resistance is crucial because it directly affects how much current will flow for a given voltage (Ohm's Law: \( V = IR \)). Knowing the resistance allowed us to compute the voltage (EMF) needed to sustain the 10 A current, illustrating another fundamental principle in action.
Electromotive Force (EMF)
Electromotive Force, often abbreviated as EMF and denoted by \( \mathcal{E} \), represents the energy provided by a power source to move electrons through a circuit. It is measured in volts (V) but is not actually a force; instead, it's a potential or energy per unit charge.
In the context of Faraday's law, EMF is induced by the changing magnetic field in a loop of wire. The relationship between EMF, resistance, and current is given by \( \mathcal{E} = I \cdot R \), where \( I \) is the current and \( R \) is the resistance.
This exercise requires finding the EMF that produces a current of 10 A. The computed EMF was then used to determine the rate at which the magnetic field's magnitude needs to change. This showcases how EMF drives current and acts as a bridge between magnetic and electrical phenomena.

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Most popular questions from this chapter

Shows a rod of length \(L=10.0 \mathrm{~cm}\) that is forced to move at constant speed \(v=5.00\) \(\mathrm{m} / \mathrm{s}\) along horizontal rails. The rod, rails, and connecting strip at the right form a conducting loop. The rod has resistance \(0.400 \Omega\); the rest of the loop has negligible resistance. A current \(i=100 \mathrm{~A}\) through the long straight wire at distance \(a=10.0 \mathrm{~mm}\) from the loop sets up a (nonuniform) magnetic field through the loop. Find the (a) emf and (b) current induced in the loop. (c) At what rate is thermal energy generated in the rod? (d) What is the magnitude of the force that must be applied to the rod to make it move at constant speed? (e) At what rate does this force do work on the rod?

The current in an \(R L\) circuit drops from \(1.0 \mathrm{~A}\) to \(10 \mathrm{~mA}\) in the first second following removal of the battery from the circuit. If \(L\) is \(10 \mathrm{H}\), find the resistance \(R\) in the circuit.

At \(t=0\), a battery is connected to a series arrangement of a resistor and an inductor. At what multiple of the inductive time constant will the energy stored in the inductor's magnetic field be \(0.500\) its steady-state value?

A square loop of wire has sides of length \(2.0 \mathrm{~cm}\). A magnetic field is directed out of the page; its magnitude is given by \(B=4.0 t^{2} y\), where \(B\) is in teslas, \(t\) is in seconds, and \(y\) is in meters. At \(t=2.5 \mathrm{~s}\), what are the (a) magnitude and (b) direction of the emf induced in the loop?

A \(12 \mathrm{H}\) inductor carries a current of \(2.0 \mathrm{~A}\). At what rate must the current be changed to produce a \(60 \mathrm{~V}\) emf in the inductor?

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