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A rectangular loop (area = \(0.15 \mathrm{~m}^{2}\) ) turns in a uniform magnetic field, \(B=0.20 \mathrm{~T}\). When the angle between the field and the normal to the plane of the loop is \(\pi / 2\) rad and increasing at \(0.60 \mathrm{rad} / \mathrm{s}\), what emf is induced in the loop?

Short Answer

Expert verified
The induced emf in the loop is 0.018 V.

Step by step solution

01

Understand the Problem

We have a rectangular loop with area \(A = 0.15 \, \text{m}^2 \) turning in a uniform magnetic field, \(B = 0.20 \, \text{T}\). The angle \(\theta\) between the field and the normal to the plane of the loop is given as \(\frac{\pi}{2}\, \text{rad}\) and it is increasing at a rate of \(\frac{d\theta}{dt} = 0.60 \, \text{rad/s}\). We need to find the induced electromotive force (emf) in the loop.
02

Write Down the Formula for Induced EMF

According to Faraday's Law of Induction, the induced emf \(\mathcal{E}\) in the loop is given by the formula: \[\mathcal{E} = - \frac{d\Phi}{dt},\]where \(\Phi\) is the magnetic flux.
03

Magnetic Flux Expression

Magnetic flux \(\Phi\) through the loop is given by \[\Phi = B \cdot A \cdot \cos(\theta).\]Here, \(B\) is the magnetic field, \(A\) is the area of the loop, and \(\theta\) is the angle between the field and the normal to the loop.
04

Differentiate Flux with Respect to Time

To find the rate of change of magnetic flux, differentiate \(\Phi = B \cdot A \cdot \cos(\theta)\) with respect to time \(t\), considering \(B\) and \(A\) as constants:\[\frac{d\Phi}{dt} = -B \cdot A \cdot \sin(\theta) \cdot \frac{d\theta}{dt}.\]
05

Substitute Values into the Differentiated Expression

Substitute \(B = 0.20 \, \text{T}\), \(A = 0.15 \, \text{m}^2\), \(\theta = \frac{\pi}{2} \, \text{rad}\), and \(\frac{d\theta}{dt} = 0.60 \, \text{rad/s}\) into the expression:\[\frac{d\Phi}{dt} = -0.20 \cdot 0.15 \cdot \sin\left(\frac{\pi}{2}\right) \cdot 0.60.\]
06

Calculate the Sin Term and Final Result

Since \(\sin\left(\frac{\pi}{2}\right) = 1\), the equation simplifies to:\[\frac{d\Phi}{dt} = -0.20 \cdot 0.15 \cdot 1 \cdot 0.60 = -0.018 \, \text{V}.\]Therefore, the induced emf is \(\mathcal{E} = 0.018 \, \text{V}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle of electromagnetism that describes how an electromotive force (emf) is generated in a conductor due to a changing magnetic field. This concept is the cornerstone of many electrical devices and systems, such as transformers and electric generators. In simple terms, Faraday's Law states that the induced emf in a circuit is directly proportional to the rate of change of magnetic flux through the circuit. The mathematical expression for this law is given by:
  • \( \mathcal{E} = - \frac{d\Phi}{dt} \)
The negative sign indicates the direction of the induced emf, which opposes the change in flux, as per Lenz's Law. This opposition is important because it reflects the conservation of energy within the system. When dealing with problems in electromagnetic induction, it's crucial to correctly identify the elements involved, such as the area of the loop, the magnetic field intensity, and any changes in the angle between the magnetic field and the conductor.
Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking into account the strength and extent of a magnetic field. It is denoted by the symbol \( \Phi \) and is calculated as the product of the magnetic field \( B \), the area \( A \) through which the field lines pass, and the cosine of the angle \( \theta \) between the magnetic field lines and the perpendicular (normal) to the area. The formula is:
  • \( \Phi = B \cdot A \cdot \cos(\theta) \)
In the given exercise, understanding magnetic flux is crucial because it explains how a change in the orientation or rotation of the loop affects the total magnetism interacting with the loop, thereby affecting the rate of change of flux and ultimately the induced emf. The angle \( \theta \) plays a vital role. When this angle is \( \frac{\pi}{2} \), the cosine component is zero, indicating no magnetic flux through the loop if \( \theta \) is kept constant. However, when \( \theta \) changes over time, it influences the rate of change of the magnetic flux significantly.
Induced EMF
Induced electromotive force (emf) is the electrical action produced by a changing magnetic environment. This induced emf is what causes current to flow through a conductor even without direct electrical contact. The magnitude of the induced emf is determined by Faraday's Law of Induction, which is influenced by factors such as the rate of change of magnetic flux. In the context of the exercise, the changing angle \( \theta \) means that the magnetic field is dynamically interacting with the coil, leading to a change in flux over time, quantified by:
  • \( \frac{d\Phi}{dt} = -B \cdot A \cdot \sin(\theta) \cdot \frac{d\theta}{dt} \)
The exercise scenario shows that a fast or rapid increase in angle \( \theta \) results in a significant rate of change of magnetic flux, consequently inducing a noticeable emf. Understanding the induced emf is pivotal in designing circuits that harness electromagnetic induction for practical applications, focusing on how changes in magnetic fields can be transformed into usable electrical energy.

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Most popular questions from this chapter

A long cylindrical solenoid with 100 turns/cm has a radius of \(1.6 \mathrm{~cm}\). Assume that the magnetic field it produces is parallel to its axis and is uniform in its interior. (a) What is its inductance per meter of length? (b) If the current changes at the rate of \(13 \mathrm{~A} / \mathrm{s}\), what emf is induced per meter?

A small circular loop of area \(2.00 \mathrm{~cm}^{2}\) is placed in the plane of, and concentric with, a large circular loop of radius \(1.00 \mathrm{~m}\). The current in the large loop is changed at a constant rate from \(200 \mathrm{~A}\) to \(-200 \mathrm{~A}\) (a change in direction) in a time of \(1.00 \mathrm{~s}\), starting at \(t=0\). What is the magnitude of the magnetic field \(\vec{B}\) at the center of the small loop due to the current in the large loop at (a) \(t=0\), (b) \(t=0.500 \mathrm{~s}\), and \((\mathrm{c}) t=1.00 \mathrm{~s} ?\) (d) From \(t=0\) to \(t=1.00 \mathrm{~s}\), is \(\vec{B}\) reversed? Because the inner loop is small, assume \(\vec{B}\) is uniform over its area. (e) What emf is induced in the small loop at \(t=0.500 \mathrm{~s}\) ?

A toroidal inductor with an inductance of \(90.0 \mathrm{mH}\) encloses a volume of \(0.0200 \mathrm{~m}^{3}\). If the average energy density in the toroid is \(70.0 \mathrm{~J} / \mathrm{m}^{3}\), what is the current through the inductor?

At \(t=0\), a battery is connected to a series arrangement of a resistor and an inductor. At what multiple of the inductive time constant will the energy stored in the inductor's magnetic field be \(0.500\) its steady-state value?

The flux linkage through a certain coil of \(0.75 \Omega\) resistance would be \(26 \mathrm{mWb}\) if there were a current of \(5.5 \mathrm{~A}\) in it. (a) Calculate the inductance of the coil. (b) If a \(6.0 \mathrm{~V}\) ideal battery were suddenly connected across the coil, how long would it take for the current to rise from 0 to \(2.5 \mathrm{~A}\) ?

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