/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Here are three vectors in meters... [FREE SOLUTION] | 91Ó°ÊÓ

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Here are three vectors in meters: $$ \begin{array}{l} \vec{d}_{1}=-3.0 \hat{\mathrm{i}}+3.0 \hat{\mathrm{j}}+2.0 \hat{\mathrm{k}} \\\ \vec{d}_{2}=-2.0 \hat{\mathrm{i}}-4.0 \hat{\mathrm{j}}+2.0 \hat{\mathrm{k}} \\\ \vec{d}_{3}=2.0 \hat{\mathrm{i}}+3.0 \hat{\mathrm{j}}+1.0 \hat{\mathrm{k}} \end{array} $$ What results from (a) \(\vec{d}_{1} \cdot\left(\vec{d}_{2}+\vec{d}_{3}\right)\), (b) \(\vec{d}_{1} \cdot\left(\vec{d}_{2} \times \vec{d}_{3}\right)\), and (c) \(\vec{d}_{1} \times\left(\vec{d}_{2}+\vec{d}_{3}\right) ?\)

Short Answer

Expert verified
(a) 3.0, (b) TBD, (c) TBD

Step by step solution

01

Compute \( \vec{d}_2 + \vec{d}_3 \)

First, we need to find \( \vec{d}_2 + \vec{d}_3 \). This is done by adding the corresponding components of \( \vec{d}_2 \) and \( \vec{d}_3 \):\[-2.0\hat{\mathbf{i}}-4.0\hat{\mathbf{j}}+2.0\hat{\mathbf{k}} + 2.0\hat{\mathbf{i}}+3.0\hat{\mathbf{j}}+1.0\hat{\mathbf{k}} = (0\hat{\mathbf{i}} - 1.0\hat{\mathbf{j}} + 3.0\hat{\mathbf{k}})\].
02

Compute \( \vec{d}_1 \cdot (\vec{d}_2 + \vec{d}_3) \)

Use the dot product formula to calculate \( \vec{d}_1 \cdot (\vec{d}_2 + \vec{d}_3) \):\[-3.0\hat{\mathbf{i}}+3.0\hat{\mathbf{j}}+2.0\hat{\mathbf{k}} \cdot (0\hat{\mathbf{i}} - 1.0\hat{\mathbf{j}} + 3.0\hat{\mathbf{k}}) = -3.0 \times 0 + 3.0 \times (-1.0) + 2.0 \times 3.0 = -3.0 + 6.0 = 3.0\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product is a way to multiply two vectors and find a scalar quantity. It's crucial in determining the angle between vectors or projecting one vector onto another. To calculate the dot product, multiply each corresponding component from the vectors and sum them up.

For vectors \(\vec{a} = a_1\hat{\mathbf{i}} + a_2\hat{\mathbf{j}} + a_3\hat{\mathbf{k}}\) and \(\vec{b} = b_1\hat{\mathbf{i}} + b_2\hat{\mathbf{j}} + b_3\hat{\mathbf{k}}\), the dot product \(\vec{a} \cdot \vec{b}\) is calculated as:

\[a_1b_1 + a_2b_2 + a_3b_3\].

In essence, this operation finds how much one vector goes in the direction of another. This is particularly useful in physics where understanding over-lapping vectors is key.

- It's commutative, meaning \(\vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a}\).- Results in a scalar, not a vector.- Reflects the magnitude of projection of one vector onto the other.
Cross Product
The cross product of two vectors results in a third vector that is perpendicular to the plane formed by the initial vectors. It is a pivotal concept in 3D space, often used in physics to determine torque or the rotational axis of objects.

If you have two vectors \(\vec{a} = a_1\hat{\mathbf{i}} + a_2\hat{\mathbf{j}} + a_3\hat{\mathbf{k}}\) and \(\vec{b} = b_1\hat{\mathbf{i}} + b_2\hat{\mathbf{j}} + b_3\hat{\mathbf{k}}\), the cross product \(\vec{a} \times \vec{b}\) is given by the determinant:

\[\begin{vmatrix} \hat{\mathbf{i}} & \hat{\mathbf{j}} & \hat{\mathbf{k}} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\].

This operation is not commutative, meaning \(\vec{a} \times \vec{b} eq \vec{b} \times \vec{a}\) in general.

- The result is a vector.- Provides a vector perpendicular to both input vectors.- Its magnitude is equal to the area of the parallelogram formed by the vectors.
Vector Addition
Vector addition is a fundamental operation that combines vectors to provide a new resultant vector. This is straightforward yet crucial in scenarios involving multiple forces, velocities, or other vector quantities.

To add vectors, simply add their respective components. Given two vectors \(\vec{a} = a_1\hat{\mathbf{i}} + a_2\hat{\mathbf{j}} + a_3\hat{\mathbf{k}}\) and \(\vec{b} = b_1\hat{\mathbf{i}} + b_2\hat{\mathbf{j}} + b_3\hat{\mathbf{k}}\), the sum \(\vec{a} + \vec{b}\) is:

\[(a_1 + b_1)\hat{\mathbf{i}} + (a_2 + b_2)\hat{\mathbf{j}} + (a_3 + b_3)\hat{\mathbf{k}}\].

This method visually aligns vector tails and extends the resulting vector head. It's handy for determining net magnitude and direction.

- It's commutative: \(\vec{a} + \vec{b} = \vec{b} + \vec{a}\).- It's associative: \((\vec{a} + \vec{b}) + \vec{c} = \vec{a} + (\vec{b} + \vec{c})\).- Allows decomposition of vectors into simpler parts for easy calculation.

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Most popular questions from this chapter

Express the following angles in radians: (a) \(20.0^{\circ}\), (b) \(50.0^{\circ}\), (c) \(100^{\circ}\), Convert the following angles to degrees: (d) 0.330 rad, (e) \(2.10 \mathrm{rad},(\mathrm{f}) 7.70 \mathrm{rad} .\)

A car is driven east for a distance of \(50 \mathrm{~km}\), then north for 30 \(\mathrm{km}\), and then in a direction \(30^{\circ}\) east of north for \(25 \mathrm{~km}\). Sketch the vector diagram and determine (a) the magnitude and (b) the angle of the car's total displacement from its starting point.

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) while returning to base camp. He was supposed to travel due north for \(5.6 \mathrm{~km}\), but when the snow clears, he discovers that he actually traveled \(7.8 \mathrm{~km}\) at \(50^{\circ}\) north of due east. (a) How far and (b) in what direction must he now travel to reach base camp?

Oasis \(B\) is \(25 \mathrm{~km}\) due east of oasis \(A\). Starting from oasis \(A\), a camel walks \(24 \mathrm{~km}\) in a direction \(15^{\circ}\) south of east and then walks \(8.0 \mathrm{~km}\) due north. How far is the camel then from oasis \(B\) ?

A particle undergoes three successive displacements in a plane, as follows: \(\vec{d}_{1}, 4.00 \mathrm{~m}\) southwest; then \(\vec{d}_{2}, 5.00 \mathrm{~m}\) east; and finally \(\vec{d}_{3}, 6.00 \mathrm{~m}\) in a direction \(60.0^{\circ}\) north of east. Choose a coordinate system with the \(y\) axis pointing north and the \(x\) axis pointing east. What are (a) the \(x\) component and (b) the \(y\) component of \(\vec{d}_{1} ?\) What are (c) the \(x\) component and (d) the \(y\) component of \(\vec{d}_{2} ?\) What are (e) the \(x\) component and (f) the \(y\) component of \(\vec{d}_{3}\) ? Next, consider the net displacement of the particle for the three successive displacements. What are \((\mathrm{g})\) the \(x\) component, \((\mathrm{h})\) the \(y\) component, (i) the magnitude, and (j) the direction of the net displacement? If the particle is to return directly to the starting point, (k) how far and (1) in what direction should it move?

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