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Shows an arrangement known as a Helmholtz coil. It consists of two circular coaxial coils, each of 200 turns and radius \(R=25.0 \mathrm{~cm}\), separated by a distance \(s=R\). The two coils carry equal currents \(i=12.2 \mathrm{~mA}\) in the same direction. Find the magnitude of the net magnetic field at \(P\), midway between the coils.

Short Answer

Expert verified
The net magnetic field at P is approximately \(4.38 \times 10^{-9} \mathrm{~T}\).

Step by step solution

01

Understanding the Helmholtz Coil

A Helmholtz coil setup involves two identical circular coils separated by distance equal to their radius, each carrying an equal current. The coils are designed to generate a uniform magnetic field in the region between them, particularly at point P, which is exactly halfway between the coils.
02

Use the formula for magnetic field due to a single loop

The magnetic field at the center of a single loop carrying current is given by the formula: \( B_{loop} = \frac{\mu_0 i R^2}{2(R^2 + x^2)^{3/2}} \), where \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \mathrm{~T\cdot m/A} \)), \( i \) is current, \( R \) is radius, and \( x \) is distance along the axis of the coil from the center of the coil.
03

Calculate the magnetic field from one coil at point P

Point P is at the center axis and midway between the coils, which is at a distance \( x = R/2 \) from each coil. Replace the values into the formula for one coil: \( i = 12.2 \times 10^{-3} \mathrm{~A} \), \( R = 0.25 \mathrm{~m} \), \( x = 0.125 \mathrm{~m} \). Thus, the expression for the magnetic field at point P from a coil is: \[ B_{coil} = \frac{4\pi \times 10^{-7}\cdot 12.2 \times 10^{-3} \cdot (0.25)^2}{2((0.25)^2 + (0.125)^2)^{3/2}} \].
04

Simplify the equation for \(B_{coil}\)

Calculate \((0.25)^2 + (0.125)^2 = 0.078125 \). Then find \((0.078125)^{3/2} \approx 0.02176\). Plug these into the \( B_{coil} \) formula: \[ B_{coil} = \frac{4\pi \times 10^{-7}\cdot 12.2 \times 10^{-3} \cdot 0.0625}{2 \times 0.02176} \].
05

Compute the magnetic field from one coil

Perform the calculations: numerator = \(4\pi \times 10^{-7} \cdot 12.2 \times 10^{-3} \cdot 0.0625 \approx 9.55 \times 10^{-11}\). Denominator = \(2 \times 0.02176\). Thus, \( B_{coil} = \frac{9.55 \times 10^{-11}}{0.04352} \approx 2.19 \times 10^{-9} \mathrm{~T}\).
06

Find the total magnetic field at point P

Because the setup consists of two identical coils contributing equally to the magnetic field at point P, the total magnetic field \( B_{total} = 2 \times B_{coil}\). Calculate \( B_{total} = 2 \times 2.19 \times 10^{-9} \mathrm{~T} = 4.38 \times 10^{-9} \mathrm{~T} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Calculation
Magnetic field calculations in situations involving coils can often seem complex. However, breaking it down into simpler parts can ease the process. The aim is usually to determine the net magnetic field at a certain point, such as point P in a Helmholtz coil setup. For this, understanding how individual fields from each loop add up is crucial.
Calculate the field from a single coil using known formulas and sum up contributions from identical coils. This simplification helps in deducing the total magnetic field. The field contributions are based on the positions of the coils and specified distances between them. Depending on design, such as those in the Helmholtz configuration, the goal is to maintain uniformity in field strength across a region.
Biot-Savart Law
The Biot-Savart Law serves as a cornerstone for calculating magnetic fields produced by currents. It provides a mathematical description of the magnetic field generated at a point in space due to a current element.
For a small segment of current, the law states:
  • The magnetic field generated is proportional to the current magnitude.
  • The field is inversely proportional to the distance from the current element.
  • The direction follows the right-hand rule associated with the path of current.
The Biot-Savart Law formula is given by:\[ d\mathbf{B} = \frac{\mu_0}{4\pi} \frac{i \cdot d\mathbf{l} \times \mathbf{r}}{r^3} \]Where:
  • \( d\mathbf{B} \) is the infinitesimal magnetic field.
  • \( \mu_0 \) is the permeability of free space.
  • \( i \) is the current through the segment.
  • \( d\mathbf{l} \) is the direction vector of current.
  • \( \mathbf{r} \) is the distance vector from the current segment to the point of interest.
  • \( r \) is the magnitude of the distance \( \mathbf{r} \).
In essence, the Biot-Savart Law lets us piece together the entire magnetic field around a current loop by summing contributions from each segment.
Permeability of Free Space
The permeability of free space, denoted as \( \mu_0 \), is a fundamental constant in electromagnetism. It describes how much space can "allow" magnetic field lines to flow through. In formulas, it often acts as a scaling factor that relates the physical quantity of current (like in loops or wires) to the resulting magnetic field.
Its value is \[\mu_0 = 4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}.\]This value is crucial, as it turns concepts into quantifiable results, allowing for consistent calculations irrespective of cultural or geographic location.
Working with \( \mu_0 \) helps standardize calculations across vast distances and diverse experimental settings, correlating directly with how magnetic flux behaves in the absence of any other material.
Current Loops
Current loops are fundamental in understanding magnetic fields, particularly in devices like Helmholtz coils. When a current traverses through a loop, it generates a magnetic field. This arranges itself in concentric circles around the wire. The field tends to be strongest at the center of the loop or in between closely spaced loops, like in the Helmholtz design.
Factors affecting the magnetic field from a current loop include:
  • The magnitude of the current circulating through the loop.
  • The number of turns or coils present.
  • The geometry of the loop, such as its radius.
For Helmholtz coils, two or more loops are employed to create a consistent magnetic field across a specified volume. Their application ranges from particle accelerators to controlling environments in experimental physics. Thus, comprehending current loops and their effects is vital, allowing us to harness and manipulate magnetic forces for various technological benefits.

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Most popular questions from this chapter

Five long parallel wires in an \(x y\) plane are separated by distance \(d=50.0 \mathrm{~cm} .\) The currents into the page are \(i_{1}=2.00 \mathrm{~A}, i_{3}=0.250 \mathrm{~A}, i_{4}=4.00 \mathrm{~A}\), and \(i_{5}=2.00 \mathrm{~A} ;\) the current out of the page is \(i_{2}=4.00 \mathrm{~A}\). What is the magnitude of the net force per unit length acting on wire 3 due to the currents in the other wires?

Shows a snapshot of a proton moving at velocity \(\vec{v}=(-200 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\) toward a long straight wire with current \(i=\) \(350 \mathrm{~m} \mathrm{~A}\). At the instant shown, the proton's distance from the wire is \(d=2.89 \mathrm{~cm} .\) In unit-vector nota- tion, what is the magnetic force on the proton due to the current?

A long straight wire carries a current of 50 A. An electron, traveling at \(1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\), is \(5.0 \mathrm{~cm}\) from the wire. What is the magnitude of the magnetic force on the electron if the electron velocity is directed (a) toward the wire, (b) parallel to the wire in the direction of the current, and (c) perpendicular to the two directions defined by (a) and (b)?

Four long straight wires are perpendicular to the page, and their cross sections form a square of edge length \(a=20 \mathrm{~cm}\). The currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3 , and each wire carries 20 A. In unit-vector notation, what is the net magnetic field at the square's center?

A long circular pipe with outside radius \(R=2.6 \mathrm{~cm}\) carries a (uniformly distributed) current \(i=\) \(8.00 \mathrm{~mA}\) into the page. A wire runs parallel to the pipe at a distance of \(3.00 R\) from center to center. Find the (a) magnitude and (b) direction (into or out of the page) of the current in the wire such that the net magnetic field at point \(P\) has the same magnitude as the net magnetic field at the center of the pipe but is in the opposite direction.

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