Chapter 28: Problem 85
At one instant, \(\vec{v}=(-2.00 \hat{\mathrm{i}}+4.00 \hat{\mathrm{j}}-6.00 \hat{\mathrm{k}}) \mathrm{m} / \mathrm{s}\) is the ve- locity of a proton in a uniform magnetic field \(\vec{B}=(2.00 \hat{\mathrm{i}}-\) \(4.00 \hat{j}+8.00 \hat{k}) \mathrm{mT}\). At that instant, what are (a) the magnetic force \(\vec{F}\) acting on the proton, in unit-vector notation, (b) the angle between \(\vec{v}\) and \(\vec{F}\), and (c) the angle between \(\vec{v}\) and \(\vec{B}\) ?
Short Answer
Step by step solution
Understand the Given Variables
Recall the Magnetic Force Formula
Calculate the Cross Product \( \vec{v} \times \vec{B} \)
Determine \( \vec{F} \) Using the Calculated Cross Product
Calculate the Magnitude of \( \vec{v} \) and \( \vec{F} \)
Find the Angle between \( \vec{v} \) and \( \vec{F} \)
Find the Angle between \( \vec{v} \) and \( \vec{B} \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Cross Product
- \( v_x, v_y, v_z \) are the components of vector \( \vec{v} \)
- \( B_x, B_y, B_z \) are the components of vector \( \vec{B} \)
Magnetic Field
Proton Charge
- \( q \) is the charge of the proton
- \( \vec{v} \times \vec{B} \) is the cross product of the velocity vector and the magnetic field